Answer: C) 23 years Explanation: Ayush's present age = 10 years.His mother's present age = (10 + 20) years = 30 years.Ayush's father's present age = (30 + 5) years = 35 years.Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years. Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.

Answer: D) 36 yrs Explanation: Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , thenw+x+y = 43x3 = 129 ---(i) andw+y+z = 49x3 = 147 ---(ii)Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36

Answer: D) 3/10 Explanation: One hour = 60 min 18/60 = 3/10

Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.

Answer: A) 200 Explanation: As per given     40100×250 =50100×x   ⇒x=200

Answer: C) 1425/18 min Explanation: 55 min. spaces are covered in 60 min.60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.Loss in 65 min. = (720/11 - 65 ) = 5/11Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.

Answer: B) k=7 & l=2 Explanation: If a number to be divisile by 88, it should be divisible by both "8" and "11" Check for '8' :For a number to be divisible by "8", the last 3-digit should be divisible by "8"Here 72x23y --> last 3-digit is '23y'So y=2 [ (i.e) 232 is absolutely divisible by "8"] Chech for '11' :For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"(7 + x + 3) - (2 + 2 + y)(7 + x + 3) - (2 + 2 + 2)(10 + x) - 6 should be divisible by "11"for x = 7=> 17 - 6 = 11 [ which is absolutely divisible by "11"] So x = 7 , y= 2.