Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2849 05b5cc736e4d2b4197774f87e
5b5cc736e4d2b4197774f87e- 155 kmstrue
- 235 kmsfalse
- 325 kmsfalse
- 465 kmsfalse
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उत्तर : 1. "55 kms"
व्याख्या :
Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.
प्र: How many remainders are possible if 16n is divided by 9 for any positive integral value of n ? 2843 05b5cc77ae4d2b41977750151
5b5cc77ae4d2b41977750151- 11false
- 22false
- 33true
- 44false
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उत्तर : 3. "3"
व्याख्या :
Answer: C) 3 Explanation: When 16nis divided by 9, we have 1619, remainder = 7 1629, remainder = 4 1639, remainder = 1 1649, remainder = 7 1659, remainder = 4 1669, remainder = 1 So, we have cyclicity of 3 factors i.e 7,4,1. Hence only 3 remainders are possible.
प्र: Find the Odd One Out? 4, 6, 12, 30, 81, 315. 2839 05b5cc6aae4d2b4197774cf56
5b5cc6aae4d2b4197774cf56- 16false
- 212false
- 381true
- 4315false
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उत्तर : 3. "81"
व्याख्या :
Answer: C) 81 Explanation: Given the number series is 4, 6, 12, 30, 81, 315. Here it follows a pattern that 4 4 x 1.5 = 6 6 x 2 = 12 12 x 2.5 = 30 30 x 3 = 90 not equals to 81 90 x 3.5 = 315 Hence the odd one in the series is 81.
प्र: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2839 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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उत्तर : 3. "(24-1)(23-1)25"
व्याख्या :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
प्र: A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together? 2836 05b5cc754e4d2b4197774fb62
5b5cc754e4d2b4197774fb62- 112 daystrue
- 224 daysfalse
- 332 daysfalse
- 416 daysfalse
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उत्तर : 1. "12 days"
व्याख्या :
Answer: A) 12 days Explanation: It is given that efficiency ratio =3:1 so time ratio will be 1:3 (since work is same) Also given that time diff = 32 days. ratio difference = 3-1 =2 2 ratio = 32 days 1 ratio = 16 days. So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days. Total work = LCM of 16 and 48 = 48. Total time = Total work/Total efficiency ie; 48/4= 12 days.
प्र: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 2830 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
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उत्तर : 1. "5 kmph"
व्याख्या :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
प्र: दो कारें बिंदु A और B से एक साथ रवाना होती है। A और B बिन्दुओं के बीच 120 किमी. का फासला है। यदि वे दोनों कारें विपरीत दिशा से एक -दूसरे की ओर आये तो वह एक घंटे के बाद आपस में मिलती है पर वे एक ही दिशा की ओर चलें (जैसे A बिन्दु कार B बिन्दु की ओर चलें, तो वह एक -दूसरे से 6 घंटे के बाद मिलती हैं। A बिंदु से चलने वाली कार की रफ्तार क्या है- 2830 05d15e50744a3a75f13296b35
5d15e50744a3a75f13296b35- 170 किमी प्रति घंटाfalse
- 2120 किमी प्रति घंटाfalse
- 360 किमी प्रति घंटाfalse
- 4डेटा अपर्याप्त हैtrue
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उत्तर : 4. "डेटा अपर्याप्त है"
प्र: A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is ? 2829 05b5cc6d8e4d2b4197774e778
5b5cc6d8e4d2b4197774e778- 163false
- 231true
- 316false
- 427false
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उत्तर : 2. "31"
व्याख्या :
Answer: B) 31 Explanation: To get the least number of coconuts :LCM = 30 => 30 + 1 = 31

