Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 'A' sold an article to 'B' at a profit of 20%. 'B' sold the same article to 'C' at a loss of 25% and 'C' sold the same article to 'D' at a profit of 40%. If 'D' paid Rs 252 for the article, then find how much did 'A' pay for it? 2558 0

  • 1
    Rs.196
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  • 2
    Rs.210
    सही
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  • 3
    Rs.200
    सही
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  • 4
    Rs.235
    सही
    गलत
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उत्तर : 3. "Rs.200"
व्याख्या :

Answer: C) Rs.200 Explanation: Let the article costs 'X' to ACost price of B = 1.2XCost price of C = 0.75(1.2X) = 0.9XCost price of D = 1.4(0.9X) = 1.26X = 252Amount paid by A for the article = Rs. 200.

प्र: Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ? 2550 0

  • 1
    404
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  • 2
    415
    सही
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  • 3
    418
    सही
    गलत
  • 4
    420
    सही
    गलत
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उत्तर : 3. "418"
व्याख्या :

Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages =  1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100   28x117=100 --> x = 418   The total pages in the book are 418

प्र: Find the next number in the series 125, 80, 45, 20, .... 2549 0

  • 1
    5
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  • 2
    15
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  • 3
    -5
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  • 4
    10
    सही
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उत्तर : 1. "5"
व्याख्या :

Answer: A) 5 Explanation: The pattern is -45, -35, -25, -15 The next number = 20-15= 5

प्र: A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ? 2538 0

  • 1
    15
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  • 2
    20
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  • 3
    10
    सही
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  • 4
    8
    सही
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उत्तर : 3. "10"
व्याख्या :

Answer: C) 10 Explanation: Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => -150+x2+5x multiplying both sides by -1/10x => x2+15x-10x-150=0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.

प्र: A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the invest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest ? 2535 0

  • 1
    4% p.a.
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  • 2
    6% p.a.
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  • 3
    8% p.a.
    सही
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  • 4
    12% p.a.
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उत्तर : 4. "12% p.a."
व्याख्या :

Answer: D) 12% p.a. Explanation: If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate. Let the earlier rate of interest be x%. Now it will be (x + 3)% % increase = (x + 3) - x/x * 100 = 25=> x = 12%

प्र: Find the odd one out? 6, 3, 3, 4.5, 10 2533 0

  • 1
    3
    सही
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  • 2
    4.5
    सही
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  • 3
    6
    सही
    गलत
  • 4
    10
    सही
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उत्तर : 4. "10"
व्याख्या :

Answer: D) 10 Explanation: Here the given number series is 6, 3, 3, 4.5, 10 The odd one in the given series is 10 The pattern it follows is 6 6 x 0.5 = 3 3 x  1  = 3 3 x 1.5 = 4.5 4.5 x 2 = 9   Hence, the odd number is 10.

प्र: Out of 135 applicants for a post, 60 are graduates and 80 have experience. What is the ratio of minimum to maximum numberof graduates having experience? 2531 0

  • 1
    12:1
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  • 2
    5:1
    सही
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  • 3
    1:5
    सही
    गलत
  • 4
    1:12
    सही
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उत्तर : 4. "1:12"
व्याख्या :

Answer: D) 1:12 Explanation: Given total applicants = 135Given graduates are G=60 Otherthan graduates=135-60 = 75Given experienced candidates = 801) For maximum number of graduates have experience    Total graduates to have experience = 60 2) For minimum number of graduates have experience    Remaining after taking other than graduates in experience= 80-75 = 5

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उत्तर : 2. "16:25"

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