Quantitative Aptitude Practice Question and Answer
8Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2918 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
Q: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2913 05b5cc745e4d2b4197774fa0e
5b5cc745e4d2b4197774fa0e- 139 daysfalse
- 237 daysfalse
- 335 daystrue
- 433 daysfalse
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Answer : 3. "35 days"
Explanation :
Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.
Q: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 2912 05b5cc728e4d2b4197774f6dc
5b5cc728e4d2b4197774f6dc- 135false
- 2165true
- 3221false
- 477false
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Answer : 2. "165"
Explanation :
Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.
Q: एक दुकानदार किसी वस्तु पर 20 प्रतिशत का बट्टा देते हुए 25 प्रतिशत का लाभ प्राप्त करता है। तो क्रय मूल्य एवं अंकित मूल्य के बीच अनुपात ज्ञात करें? 2911 15d134055d2441c3c5ff90aa4
5d134055d2441c3c5ff90aa4- 125:16false
- 216:25true
- 316:27false
- 427:10false
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Answer : 2. "16:25"
Q: In how many ways word of 'GLACIOUS' can be arranged such that 'C' always comes at end? 2910 05b5cc626e4d2b4197774b825
5b5cc626e4d2b4197774b825- 13360false
- 25040true
- 3720false
- 41080false
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Answer : 2. "5040"
Explanation :
Answer: B) 5040 Explanation: Given word is GLACIOUS has 8 letters. => C is fixed in one of the 8 places Then, the remaining 7 letters can be arranged in 7! ways = 5040.
Q: Find the odd one out? 6, 3, 3, 4.5, 10 2906 05b5cc698e4d2b4197774c670
5b5cc698e4d2b4197774c670- 13false
- 24.5false
- 36false
- 410true
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Answer : 4. "10"
Explanation :
Answer: D) 10 Explanation: Here the given number series is 6, 3, 3, 4.5, 10 The odd one in the given series is 10 The pattern it follows is 6 6 x 0.5 = 3 3 x 1 = 3 3 x 1.5 = 4.5 4.5 x 2 = 9 Hence, the odd number is 10.
Q: Tilak rides on a cycle to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 min. more than that of the first case, what is the total distance travelled by him (in km)? 2906 05b5cc6a0e4d2b4197774ca6c
5b5cc6a0e4d2b4197774ca6c- 1132 kmfalse
- 2264 kmtrue
- 3134 kmfalse
- 4236 kmfalse
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Answer : 2. "264 km"
Explanation :
Answer: B) 264 km Explanation: Let the distance travelled by Tilak in first case or second case = d kms Now, from the given data, d/20 = d/22 + 36 min => d/20 = d/22 + 3/5 hrs => d = 132 km. Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.
Q: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a. ? 2905 05b5cc6dde4d2b4197774ea19
5b5cc6dde4d2b4197774ea19- 1Rs. 22.5true
- 2Rs. 2.5false
- 3Rs. 202false
- 4Rs. 25false
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Answer : 1. "Rs. 22.5"
Explanation :
Answer: A) Rs. 22.5 Explanation: We know that I = PTR/100=> P = 20250/4.5 = 4500Now, new Interest at 5% = 4500x1x5/100 = 225Now the additional amount = 225 - 202.5 = Rs. 22.5

