Quantitative Aptitude Practice Question and Answer

Q: Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ? 2390 0

  • 1
    404
    Correct
    Wrong
  • 2
    415
    Correct
    Wrong
  • 3
    418
    Correct
    Wrong
  • 4
    420
    Correct
    Wrong
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Answer : 3. "418"
Explanation :

Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages =  1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100   28x117=100 --> x = 418   The total pages in the book are 418

Q: A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is  ? 2389 0

  • 1
    63
    Correct
    Wrong
  • 2
    31
    Correct
    Wrong
  • 3
    16
    Correct
    Wrong
  • 4
    27
    Correct
    Wrong
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Answer : 2. "31"
Explanation :

Answer: B) 31 Explanation: To get the least number of coconuts :LCM = 30 => 30 + 1 = 31

Q: Rushi and Arun are two business partners. They invest their capital in the ratio 7 : 9. After 6 months, a third person Ram joins them with a capital of two third of that of Arun. After a year, profit share of Rushi was Rs. 5600, then find total profit? 2388 0

  • 1
    26,250
    Correct
    Wrong
  • 2
    19,200
    Correct
    Wrong
  • 3
    18,650,
    Correct
    Wrong
  • 4
    15,200
    Correct
    Wrong
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Answer : 4. "15,200"
Explanation :

Answer: D) 15,200 Explanation: Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6) = 7 : 9 : 3 Given Rushi's one year profit = Rs. 5600 => Let the total profit = Rs. P Then, P x 7/19 = 5600 Total profit P = 19 x 5600/7 = Rs. 15,200.

Q: A retailer buys product from a shopkeeper at discount of 40% on the list price (marked price) and sells them to the customer at a discount of 25% on the list price.What is his profit percentage ? 2381 0

  • 1
    10%
    Correct
    Wrong
  • 2
    15%
    Correct
    Wrong
  • 3
    20%
    Correct
    Wrong
  • 4
    25%
    Correct
    Wrong
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Answer : 4. "25%"
Explanation :

Answer: D) 25% Explanation: Let the list price be Rs.100.    Therefore, the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15.   Therefore, his percentage is = 1560x100 = 25%

Q: Find the odd one out? 6, 3, 3, 4.5, 10 2378 0

  • 1
    3
    Correct
    Wrong
  • 2
    4.5
    Correct
    Wrong
  • 3
    6
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 4. "10"
Explanation :

Answer: D) 10 Explanation: Here the given number series is 6, 3, 3, 4.5, 10 The odd one in the given series is 10 The pattern it follows is 6 6 x 0.5 = 3 3 x  1  = 3 3 x 1.5 = 4.5 4.5 x 2 = 9   Hence, the odd number is 10.

Q: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.  ? 2377 0

  • 1
    Rs. 22.5
    Correct
    Wrong
  • 2
    Rs. 2.5
    Correct
    Wrong
  • 3
    Rs. 202
    Correct
    Wrong
  • 4
    Rs. 25
    Correct
    Wrong
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Answer : 1. "Rs. 22.5"
Explanation :

Answer: A) Rs. 22.5 Explanation: We know that I = PTR/100=> P = 20250/4.5 = 4500Now, new Interest at 5% = 4500x1x5/100 = 225Now the additional amount = 225 - 202.5 = Rs. 22.5

Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of  gentlemen in the family? 2371 0

  • 1
    23
    Correct
    Wrong
  • 2
    92
    Correct
    Wrong
  • 3
    48
    Correct
    Wrong
  • 4
    52
    Correct
    Wrong
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Answer : 1. "23"
Explanation :

Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115  ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23   Hence, required number of gentlemen in the family = x = 23.

Q: Sum of present ages of P and Q is 41. Age of P 2 year hence is equal to age of R, 1 year ago. Age of P, 4 year hence is equal to age of Q 1 year ago and ratio of present age of P and S is 3 : 4. Find the difference of age of R and S. 2366 0

  • 1
    2
    Correct
    Wrong
  • 2
    3
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 2. "3"
Explanation :

Answer: B) 3 Explanation: According to the given data, P + Q = 41 ......(1) R - 1 = P + 2 R = P + 3 and P + 4 = Q - 1 => Q = P + 5 ....(2) From (1)&(2) P = 18 Q = 18 + 5 = 23 R = 18 + 3 = 21 => P/S = 3/4 => S = 4/3 x 18 = 24 Required Difference = S - R = 24 - 21 = 3.

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