Quantitative Aptitude Practice Question and Answer
8Q: How many four digit even numbers can be formed using the digits {2, 7, 5, 3, 9, 1} ? 2606 05b5cc6d7e4d2b4197774e705
5b5cc6d7e4d2b4197774e705- 159false
- 260true
- 361false
- 464false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: The given digits are 1, 2, 3, 5, 7, 9 A number is even when its units digit is even. Of the given digits, two is the only even digit.Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways. Number of even numbers = ⁵P₃ = 60.
Q: Find the next number in the series 125, 80, 45, 20, .... 2606 05b5cc76fe4d2b4197774ff5d
5b5cc76fe4d2b4197774ff5d- 15true
- 215false
- 3-5false
- 410false
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Answer : 1. "5"
Explanation :
Answer: A) 5 Explanation: The pattern is -45, -35, -25, -15 The next number = 20-15= 5
Q: Rushi and Arun are two business partners. They invest their capital in the ratio 7 : 9. After 6 months, a third person Ram joins them with a capital of two third of that of Arun. After a year, profit share of Rushi was Rs. 5600, then find total profit? 2605 05b5cc619e4d2b4197774b70f
5b5cc619e4d2b4197774b70f- 126,250false
- 219,200false
- 318,650,false
- 415,200true
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Answer : 4. "15,200"
Explanation :
Answer: D) 15,200 Explanation: Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6) = 7 : 9 : 3 Given Rushi's one year profit = Rs. 5600 => Let the total profit = Rs. P Then, P x 7/19 = 5600 Total profit P = 19 x 5600/7 = Rs. 15,200.
Q: Out of 135 applicants for a post, 60 are graduates and 80 have experience. What is the ratio of minimum to maximum numberof graduates having experience? 2603 05b5cc774e4d2b41977750066
5b5cc774e4d2b41977750066- 112:1false
- 25:1false
- 31:5false
- 41:12true
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Answer : 4. "1:12"
Explanation :
Answer: D) 1:12 Explanation: Given total applicants = 135Given graduates are G=60 Otherthan graduates=135-60 = 75Given experienced candidates = 801) For maximum number of graduates have experience Total graduates to have experience = 60 2) For minimum number of graduates have experience Remaining after taking other than graduates in experience= 80-75 = 5
Q: A shop keeper sells an article at a loss of 8%, but when he increases the selling price of the article by Rs. 164 he earns a profit of 2.25% on the cost price. If he sells the same article at Rs. 1760, what is his profit percentage? 2601 05b5cc62ae4d2b4197774b89f
5b5cc62ae4d2b4197774b89f- 12.5%false
- 25%false
- 310%true
- 47.5%false
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Answer : 3. "10%"
Explanation :
Answer: C) 10% Explanation: According to the given data, Let Cost price of the article be 'cp' Then, 102.25 cp - 92 cp = 164 x 100 10.25 cp = 16400 cp = 1600 Now, if he sells at Rs. 1760 Profit = 1760 - 1600 = 160 Profit% = 160/1600 x 100 = 10%.
Q: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a. ? 2600 05b5cc6dde4d2b4197774ea19
5b5cc6dde4d2b4197774ea19- 1Rs. 22.5true
- 2Rs. 2.5false
- 3Rs. 202false
- 4Rs. 25false
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Answer : 1. "Rs. 22.5"
Explanation :
Answer: A) Rs. 22.5 Explanation: We know that I = PTR/100=> P = 20250/4.5 = 4500Now, new Interest at 5% = 4500x1x5/100 = 225Now the additional amount = 225 - 202.5 = Rs. 22.5
Q: A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is ? 2600 05b5cc6d8e4d2b4197774e778
5b5cc6d8e4d2b4197774e778- 163false
- 231true
- 316false
- 427false
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Answer : 2. "31"
Explanation :
Answer: B) 31 Explanation: To get the least number of coconuts :LCM = 30 => 30 + 1 = 31
Q: Tilak rides on a cycle to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 min. more than that of the first case, what is the total distance travelled by him (in km)? 2596 05b5cc6a0e4d2b4197774ca6c
5b5cc6a0e4d2b4197774ca6c- 1132 kmfalse
- 2264 kmtrue
- 3134 kmfalse
- 4236 kmfalse
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Answer : 2. "264 km"
Explanation :
Answer: B) 264 km Explanation: Let the distance travelled by Tilak in first case or second case = d kms Now, from the given data, d/20 = d/22 + 36 min => d/20 = d/22 + 3/5 hrs => d = 132 km. Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.