Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately? 2542 05b5cc6bfe4d2b4197774da97
5b5cc6bfe4d2b4197774da97- 120true
- 219false
- 317false
- 422false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "20"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m┬а Now, as the tent is in the conical form Volume of the conical tent =┬а╧Аr2h3┬а => (22 x 5 x 5 x 3) / (7 x 3)┬а = 22 x 25/7┬а = 78.54 cu.m┬а Given each person requires 3.92 cu.m of air┬а => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20
рдкреНрд░: A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ? 2540 05b5cc731e4d2b4197774f7e2
5b5cc731e4d2b4197774f7e2- 110.5 kgsfalse
- 212 kgsfalse
- 39.6 kgsfalse
- 411.5 kgstrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "11.5 kgs"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 11.5 kgs Explanation: Screws weight = 90x100 = 9000gmsbolts weight = 100 x 150 = 15000gmsweight = screws + bolts => 24000 gms =>24 kgGiven entire box weight = 35.5kgempty box = entire box weight - weight => 35.5kg - 24kg => 11.5kgso the empty box is 11.5kg.
рдкреНрд░: A can do a piece of work in 10 days, B in 15 days. They work together for 5 days, the rest of the work is finished by C in two more days. If they get Rs. 3000 as wages for the whole work, what are the daily wages of A, B and C respectively (in Rs): 2540 05b5cc7d0e4d2b419777511d6
5b5cc7d0e4d2b419777511d6- 1200, 250, 300false
- 2300, 200, 250true
- 3200, 300, 400false
- 4None of thesefalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "300, 200, 250"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50%┬а┬а B's 5 days work = 33.33%┬а C's 2 days work = 16.66%┬а ┬а ┬а[100- (50+33.33)]┬а Ratio of contribution of work of A, B and C =┬а50┬а:┬а3313┬а:┬а1623┬а= 3 : 2 : 1┬а┬а┬а A's total share = Rs. 1500┬а B's total share = Rs. 1000┬а C's total share = Rs. 500┬а┬а ┬а A's one day's earning = Rs.300┬а┬а B's one day's earning = Rs.200┬а┬а C's one day's earning = Rs.250
рдкреНрд░: 25% of 25%┬аIs Equal To 2538 05b5cc6bae4d2b4197774d78a
5b5cc6bae4d2b4197774d78a- 10.0625true
- 20.0210false
- 30.03145false
- 40.3210false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "0.0625"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 0.0625 Explanation: 25% of 25%┬аmeans ┬а 25/100 of 25/100 ┬а i.e, 1/4 of 1/4 ┬а or in other words 1/4 x 1/4=1/16 ┬а Hence, the answer is┬а1/16 = 0.0625.
рдкреНрд░: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 15%, he is only able to save Rs. 400 per month. What is his monthly salary ? 2536 05b5cc6e1e4d2b4197774ebf2
5b5cc6e1e4d2b4197774ebf2- 1Rs. 6000false
- 2Rs. 4500false
- 3Rs. 5000true
- 4Rs. 6500false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "Rs. 5000"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) Rs. 5000 Explanation: Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80x(15/100) = Rs. 12 = 80 + 12 = Rs. 92 Present Savings = 100 тАУ 92 = Rs. 8 100 ------ 8? --------- 400 => 5000 His salary = Rs. 5000
рдкреНрд░: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each┬аgentleman received twice the paise as each lady received. Find the number of┬а┬аgentlemen in the family? 2534 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "23"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115┬а ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 ┬а Hence, required number of gentlemen in the family = x = 23.
рдкреНрд░: рдПрдХ рд░реЗрд▓рдЧрд╛реЬреА рдХреА рд▓рдореНрдмрд╛рдИ 300 рдореАрдЯрд░ рд╣реИрдВред рд╡рд╣ 72 рдХрд┐рдореА рдкреНрд░рддрд┐ рдШрдВрдЯреЗ рдХреА рд░рдлреНрддрд╛рд░ рд╕реЗ рдПрдХ рдЦрдореНрднреЗ рдХреЛ рдХрд┐рддрдиреА рджреЗрд░ рдореЗрдВ рдкрд╛рд░ рдХрд░ рдЬрд╛рдПрдЧреА? 2530 05d15fd8e44a3a75f13296b87
5d15fd8e44a3a75f13296b87- 118 рд╕реИрдВрдХрдгреНрдбfalse
- 215 рд╕реИрдВрдХрдгреНрдбtrue
- 312 рд╕реИрдВрдХрдгреНрдбfalse
- 420 рд╕реИрдВрдХрдгреНрдбfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "15 рд╕реИрдВрдХрдгреНрдб"
рдкреНрд░: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 2529 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "6011 hrs"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.

