Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ? 2385 05b5cc774e4d2b4197775001b
5b5cc774e4d2b4197775001b- 111/91false
- 24/11false
- 31/11false
- 490/91true
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उत्तर : 4. "90/91"
व्याख्या :
Answer: D) Option D Explanation: Let S be the sample space. Then,n(s) = number of ways of drawing 4 pearls out of 14 = C414 ways = 14×13×12×114×3×2×1= 1001 Let E be the event of drawing 4 pearls of the same colour.Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5) ⇒C15+ C44+ C15 = 5+1+5 =11 P(E) = n(E)n(S)=111001=191 Required probability = 1-191=9091
प्र: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ? 2385 05b5cc74ae4d2b4197774fad1
5b5cc74ae4d2b4197774fad1- 11 : 2 : 3false
- 22 : 3 : 4true
- 33: 4 : 5false
- 44 : 5 : 6false
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उत्तर : 2. "2 : 3 : 4"
व्याख्या :
Answer: B) 2 : 3 : 4 Explanation: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x. There is a proposal to increase these seats by 40%, 50% and 75% respectively. Then Seats for Mathematics, Physics and Biology in a school will be 1.4 X 5x, 1.5 X 7x and 1.75 X 8x and ratio will be 7 : 10.5 : 14 => 2:3:4.
प्र: If 15% of x = 20% of y, then x:y is ___? 2384 05b5cc6bde4d2b4197774d929
5b5cc6bde4d2b4197774d929- 14:3true
- 25:4false
- 34:5false
- 43:4false
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उत्तर : 1. "4:3"
व्याख्या :
Answer: A) 4:3 Explanation: Given 15% of x = 20% of y => 15x = 20y => x/y = 20/15 => x : y = 4 : 3
प्र: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 15%, he is only able to save Rs. 400 per month. What is his monthly salary ? 2380 05b5cc6e1e4d2b4197774ebf2
5b5cc6e1e4d2b4197774ebf2- 1Rs. 6000false
- 2Rs. 4500false
- 3Rs. 5000true
- 4Rs. 6500false
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उत्तर : 3. "Rs. 5000"
व्याख्या :
Answer: C) Rs. 5000 Explanation: Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80x(15/100) = Rs. 12 = 80 + 12 = Rs. 92 Present Savings = 100 – 92 = Rs. 8 100 ------ 8? --------- 400 => 5000 His salary = Rs. 5000
प्र: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 2379 05b5cc728e4d2b4197774f6dc
5b5cc728e4d2b4197774f6dc- 135false
- 2165true
- 3221false
- 477false
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उत्तर : 2. "165"
व्याख्या :
Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.
प्र: A motorboat goes 8 km an hour in still water, but takes thrice as much time in going the same distance against the current than going with the current. Then find the speed of the current? 2375 05b5cc6ace4d2b4197774d09b
5b5cc6ace4d2b4197774d09b- 14 kmphtrue
- 26 kmphfalse
- 33 kmphfalse
- 42 kmphfalse
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उत्तर : 1. "4 kmph"
व्याख्या :
Answer: A) 4 kmph Explanation: Let the speed of current = 'C' km/hr Given the speed of boat in still water = 6 kmph Let 'd' kms be the distance it covers. According to the given data, Boat takes thrice as much time in going the same distance against the current than going with the current i.e, d8 - C = 3 × d8 + C ⇒ 24 - 3C = 8 + C⇒ 4C = 16⇒ C = 4 kmph Hence, the speed of the current C = 4 kmph.
प्र: A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ? 2371 05b5cc731e4d2b4197774f7e2
5b5cc731e4d2b4197774f7e2- 110.5 kgsfalse
- 212 kgsfalse
- 39.6 kgsfalse
- 411.5 kgstrue
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उत्तर : 4. "11.5 kgs"
व्याख्या :
Answer: D) 11.5 kgs Explanation: Screws weight = 90x100 = 9000gmsbolts weight = 100 x 150 = 15000gmsweight = screws + bolts => 24000 gms =>24 kgGiven entire box weight = 35.5kgempty box = entire box weight - weight => 35.5kg - 24kg => 11.5kgso the empty box is 11.5kg.
प्र: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58 ? 2365 05b5cc6e9e4d2b4197774ee15
5b5cc6e9e4d2b4197774ee15- 1Rs. 3748false
- 2Rs. 3847false
- 3Rs. 3944true
- 4Rs. 3154false
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उत्तर : 3. "Rs. 3944"
व्याख्या :
Answer: C) Rs. 3944 Explanation: Let the side of the square plot be 'a' ft.Given area of the plot (a x a) = 289 => a = 17Length of the fence = Perimeter of the plot = 4a = 68 ft.Cost of building the fence = 68 x 58 = Rs. 3944.

