Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: The top and bottom of a tower were seen to be at angles of depression 30┬░ and 60┬░ from the top of a hill of height 100 m. Find the height of the tower ? 2825 15b5cc72ce4d2b4197774f79c
5b5cc72ce4d2b4197774f79c- 142.2 mtsfalse
- 233.45 mtsfalse
- 366.6 mtstrue
- 458.78 mtsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "66.6 mts"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30┬░ (тИ╡ AX || BD ) angleXAE = angleAEC = 60┬░ (тИ╡ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (тИ╡ AC=100 and BC = h), BD = CE tan 60┬░=AC/CE => тИЪ3 = 100/CE =>CE = 100/тИЪ3 ----- (1) tan 30┬░ = AB/BD => 1/тИЪ3 = 100тИТh/BD => BD = 100тИТh(тИЪ3)тИ╡ BD = CE and Substitute the value of CE from equation 1 100/тИЪ3 = 100тИТh(тИЪ3) => h = 66.66 mts The height of the tower = 66.66 mts.
рдкреНрд░: The third proportional to 9 and 12 is ? 2825 05b5cc6e9e4d2b4197774ede8
5b5cc6e9e4d2b4197774ede8- 114false
- 216true
- 318false
- 420false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "16"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 16 Explanation: Let the third proportion to 9 & 12 be 'x'. => 9:12 = 12 :p => p = 12x12/9 = 16.
рдкреНрд░: If two fractions, each of which has a value between 0 and 1, are multiplied together, the product will be : 2825 05b5cc6cfe4d2b4197774e303
5b5cc6cfe4d2b4197774e303- 1always greater than either of the original fractionsfalse
- 2always less than either of the original fractionstrue
- 3sometimes greater and sometimes less than either of the original fractionsfalse
- 4remains the samefalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "always less than either of the original fractions"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) always less than either of the original fractions Explanation: We can easily Answer this by taking some values. ┬а The question states that the two fractions, each have values between 0 and 1.Let us say one of the fraction is 1/2 and the other fraction is 1/3 .The product of the two fractions is 1/2 x 1/3 = 1/6 .┬аis lesser than both 1/2 ┬аand 1/3 .So, the correct answer is that the product is┬аalways less than either of the original fractions.
рдкреНрд░: Find the next number in the series 125, 80, 45, 20, .... 2824 05b5cc76fe4d2b4197774ff5d
5b5cc76fe4d2b4197774ff5d- 15true
- 215false
- 3-5false
- 410false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "5"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 5 Explanation: The pattern is -45, -35, -25, -15 The next number = 20-15= 5
рдкреНрд░: A motorboat can go 10 miles downstream on a river in 20 min. It takes 30 min for this boat to go back at the same 10 miles. Find the speed of the current ? 2823 05b5cc6bfe4d2b4197774da29
5b5cc6bfe4d2b4197774da29- 18 m/hfalse
- 25 m/htrue
- 37 m/hfalse
- 46 m/hfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "5 m/h"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 5 m/h Explanation: As the distance travelled is constant, the time taken is inversely proportional to speed. Let 'u' be the speed of the current and 'v' be the speed of the boat. Speed of the boat downstream = v + u & upstream = v - u => v+u/v-u = 30/20 => v/u = 5 => v = 5u => v + u = 6u = 10/20/60 miles/hr => 6u = 30 m/h => u = 5 m/h
рдкреНрд░: A train sets off at 3 p.m. at the speed of 70 kmph. Another train starts at 4:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet ? 2823 05b5cc6e7e4d2b4197774ed79
5b5cc6e7e4d2b4197774ed79- 110:10 pmfalse
- 29:50 pmfalse
- 311:30 pmtrue
- 410:30 pmfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "11:30 pm"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 11:30 pm Explanation: Distance = 70 x 1 ┬╜ = 105 km Relative Speed = 85 тАУ 70 = 15 Time = 105/15 = 7 hrs 4:30 + 7 hrs = 11.30 p.m.
рдкреНрд░: рдПрдХ рд░реЗрд▓рдЧрд╛реЬреА рдХреА рд▓рдореНрдмрд╛рдИ 300 рдореАрдЯрд░ рд╣реИрдВред рд╡рд╣ 72 рдХрд┐рдореА рдкреНрд░рддрд┐ рдШрдВрдЯреЗ рдХреА рд░рдлреНрддрд╛рд░ рд╕реЗ рдПрдХ рдЦрдореНрднреЗ рдХреЛ рдХрд┐рддрдиреА рджреЗрд░ рдореЗрдВ рдкрд╛рд░ рдХрд░ рдЬрд╛рдПрдЧреА? 2815 05d15fd8e44a3a75f13296b87
5d15fd8e44a3a75f13296b87- 118 рд╕реИрдВрдХрдгреНрдбfalse
- 215 рд╕реИрдВрдХрдгреНрдбtrue
- 312 рд╕реИрдВрдХрдгреНрдбfalse
- 420 рд╕реИрдВрдХрдгреНрдбfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "15 рд╕реИрдВрдХрдгреНрдб"
рдкреНрд░: What number should replace the question mark? 125, 138, 164, ?, 255 2812 05b5cc6a1e4d2b4197774cabd
5b5cc6a1e4d2b4197774cabd- 1189false
- 2197false
- 3200false
- 4203true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "203"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 203 Explanation: The given number series is┬а125,┬а ┬а138,┬а ┬а164,┬а ┬а?,┬а ┬а255 ┬а 125 ┬а 125 + 13x1 = 138 ┬а 138 + 13x2 = 164 ┬а 164 + 13x3 = 203 ┬а 203 + 13x4 = 255 ┬а ┬а ┬а Hence, the missing number in the series is 203.

