Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: एक बगीचे में, नारियल के पेड़ों की संख्या आम के पेड़ों की संख्या का अनुपात क्रमशः 5: 6 है। यदि पेड़ों की कुल संख्या 121 है, तो बगीचे में नारियल के कितने पेड़ हैं? 8068 45d1b08d58a754124194a7526
5d1b08d58a754124194a7526- 150false
- 245false
- 356false
- 455true
- उत्तर देखेंउत्तर छिपाएं
- Workspace
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उत्तर : 4. "55"
प्र: what is the missing number in the sequence given below? 12 9 13.50 30.37 ? 341.71 7899 05b5cc6b2e4d2b4197774d3a9
5b5cc6b2e4d2b4197774d3a9- 187.63false
- 291.12true
- 393.41false
- 497.94false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "91.12"
व्याख्या :
Answer: B) 91.12 Explanation: Given number series is 12 9 13.5 30.3 ? 341.7 Here the pattern followed by the series is 12 12 x 0.75 = 9 9 x 1.5 = 13.5 13.5 x 2.25 = 30.3 30.37 x 3 = 91.12 91.12 x 3.75 = 341.71 Hence, the missing number in the sequence is 91.12.
प्र: निम्नलिखित ग्राफ का ध्यानपूर्वक अध्ययन करें और उस प्रश्न का उत्तर दें जो अनुसरण करता है।
डिजाइन, कस्टुमर रिलेशन, और एच.आर डिपारटमेंट में कुल कितने पुरूष है?
7898 15d4ab6bc11160f20523745d9
5d4ab6bc11160f20523745d9डिजाइन, कस्टुमर रिलेशन, और एच.आर डिपारटमेंट में कुल कितने पुरूष है?

- 11550false
- 21510true
- 31540false
- 41580false
- 5None of thesefalse
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "1510"
प्र: A and B can fill the tank in 60 min and 90 min. There is a leak at 3/4th of the height. If leak is opened alone, it takes 36 min to empty till 3/4th the height. Find the time taken to fill the tank if all of the taps and the leak are opened simultaneously. 7675 05b5cc6bfe4d2b4197774da56
5b5cc6bfe4d2b4197774da56- 139true
- 227false
- 337false
- 433false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 1. "39"
व्याख्या :
Answer: A) 39 Explanation:
प्र: K and L start the business, with L investing the total capital of Rs. 40,000 on the condition that K pays L interest @ 8% per annum on his half of the capital. L is a working partner and receives Rs.1200 per month from the total profit and any profit reamaining is equally shared by both of them. At the end of the year, it was found that the income of L is twice that of K. Find the total profit for the year ? 7574 05b5cc777e4d2b4197775008e
5b5cc777e4d2b4197775008e- 1Rs.44000false
- 2Rs.46400true
- 3Rs.480800false
- 4Rs.46000false
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उत्तर : 2. "Rs.46400"
व्याख्या :
Answer: B) Rs.46400 Explanation: Interest received by L from K = 8% of half of Rs.40,000 ⇒8100×20000=1600 Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400 Let 'A' be the part of remaing profit that 'L' receives as his share. Total income of 'K' = only his share from the reamaing profit = 'A', as both share equally. Given income of L = Twice the income of K --> (1600 + 14400 + A ) = 2A --> A= Rs.16000 Thus total profit = 2A + Rs.14,400= 2(16000) + 14400 = 32000 +14400 = Rs.46,400.
प्र: एक बक्से में 300 रूपये है जो 1रूपये, 50 पैसे तथा 25 पैसे के सिक्कों में है एवं उनका अनुपात 2ः4ः8 है। 25 पैसे वाले सिक्कों की संख्या बताइए। 7522 35d1b179d1fc62311c773687f
5d1b179d1fc62311c773687f- 1300false
- 2200false
- 3400true
- 4100false
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उत्तर : 3. "400"
प्र: In a purse there are 30 coins, twenty one-rupee and remaining 50-paise coins. Eleven coins are picked simultaneously at random and are placed in a box. If a coin is now picked from the box, find the probability of it being a rupee coin? 7164 05b5cc60de4d2b4197774b618
5b5cc60de4d2b4197774b618- 14/7false
- 22/3true
- 31/2false
- 45/6false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "2/3"
व्याख्या :
Answer: B) 2/3 Explanation: Total coins 30 In that, 1 rupee coins 20 50 paise coins 10Probability of total 1 rupee coins = 20C11 Probability that 11 coins are picked = 30C11 Required probability of a coin now picked from the box is 1 rupee = 20C11/30C11 = 2/3.
प्र: For x∈N, x>1, and p=logxx+1, q=logx+1x+2 then which one of the following is correct? 7143 25b5cc7d0e4d2b419777511ff
5b5cc7d0e4d2b419777511ff- 1p < qfalse
- 2p = qfalse
- 3p > qtrue
- 4can't be determinedfalse
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 3. "p > q"
व्याख्या :
Answer: C) p > q Explanation: kl>k+1l+1 for (k,l) > 0 and k > l Let k = x+1 and l = x Therefore, x+1x>(x+1)+1(x)+1 (x + 1) > x Therefore, log(x+1)log(x)>log(x+2)log(x+1) ⇒logxx+1 >logx+1x+2

