Quantitative Aptitude Practice Question and Answer
8Q: Three strategies P, Q and R have been initiated for cost cutting in a company producing respectively 20%, 30% and 10% savings. Assuming that they operate independently, what is the net saving achieved ? 2624 05b5cc73ae4d2b4197774f8dd
5b5cc73ae4d2b4197774f8dd- 149.6%true
- 250.4%false
- 333.67%false
- 466.66%false
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Answer : 1. "49.6%"
Explanation :
Answer: A) 49.6% Explanation: As these three strategies P, Q and R are independent so these will cut cost one after the other.If initial cost is Rs 100, then20% cost is cut after initializing strategy P, then cost will remain 80% = 80further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4 Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.
Q: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 2618 15b5cc72ce4d2b4197774f79c
5b5cc72ce4d2b4197774f79c- 142.2 mtsfalse
- 233.45 mtsfalse
- 366.6 mtstrue
- 458.78 mtsfalse
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Answer : 3. "66.6 mts"
Explanation :
Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.
Q: 25% of 25% Is Equal To 2617 05b5cc6bae4d2b4197774d78a
5b5cc6bae4d2b4197774d78a- 10.0625true
- 20.0210false
- 30.03145false
- 40.3210false
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Answer : 1. "0.0625"
Explanation :
Answer: A) 0.0625 Explanation: 25% of 25% means 25/100 of 25/100 i.e, 1/4 of 1/4 or in other words 1/4 x 1/4=1/16 Hence, the answer is 1/16 = 0.0625.
Q: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58 ? 2608 05b5cc6e9e4d2b4197774ee15
5b5cc6e9e4d2b4197774ee15- 1Rs. 3748false
- 2Rs. 3847false
- 3Rs. 3944true
- 4Rs. 3154false
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Answer : 3. "Rs. 3944"
Explanation :
Answer: C) Rs. 3944 Explanation: Let the side of the square plot be 'a' ft.Given area of the plot (a x a) = 289 => a = 17Length of the fence = Perimeter of the plot = 4a = 68 ft.Cost of building the fence = 68 x 58 = Rs. 3944.
Q: Find the next number in the given series 0.25, 8, 128, 1024, ? 2608 05b5cc6bce4d2b4197774d8b1
5b5cc6bce4d2b4197774d8b1- 14096true
- 22526false
- 38486false
- 42620false
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Answer : 1. "4096"
Explanation :
Answer: A) 4096 Explanation: Here given series follows a pattern that 0.25, 8, 128, 1024, ? 0.25 x 32 = 8 8 x 16 = 128 128 x 8 = 1024 1024 x 4 = 4096
Q: If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ? 2604 05b5cc728e4d2b4197774f6c8
5b5cc728e4d2b4197774f6c8- 113/125false
- 214/57false
- 311/120true
- 416/41false
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Answer : 3. "11/120"
Explanation :
Answer: C) 11/120 Explanation: Let the numbers be a and b.We know that product of two numbers = Product of their HCF and LCMThen, a + b = 55 and ab = 5 x 120 = 600.=> The required sum = (1/a) + (1/b) = (a+b)/ab=55/600 = 11/120
Q: A boat takes 2 hours to travel from point A to B in still water. To find out its speed upstream, which of the following information is/are required? A. Distance between point A and B. B. Time taken to travel downstream from B to A. C. Speed of the stream of water. 2604 05b5cc69fe4d2b4197774c9f1
5b5cc69fe4d2b4197774c9f1- 1Only A and Bfalse
- 2Only B and Cfalse
- 3All are requiredfalse
- 4Any one pair of A and B, B and C or C and A is sufficienttrue
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Answer : 4. "Any one pair of A and B, B and C or C and A is sufficient"
Explanation :
Answer: D) Any one pair of A and B, B and C or C and A is sufficient Explanation: Let distance between A & B = d kmLet speed in still water = x kmphLet speed of current = y kmph from the given data,d/x = 2 From A) we get dFrom B) we get d/x+yFrom C) we get y So, Any one pair of A and B, B and C or C and A is sufficient to give the answer i.e, the speed of upstream.
Q: 88 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be ? 2604 05b5cc723e4d2b4197774f659
5b5cc723e4d2b4197774f659- 1112 mtsfalse
- 284 mtstrue
- 396 mtsfalse
- 4108 mtsfalse
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Answer : 2. "84 mts"
Explanation :
Answer: B) 84 mts Explanation: Vol of silver = πR2h = 66 C.C Given D= 1mm => R = D/2 = 1/20 cm => 227×1202×h = 66 = 66 x 400 x (7/22) = 8400 cm = 84 mtrs.

