Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 2318 05b5cc6bbe4d2b4197774d80c
5b5cc6bbe4d2b4197774d80c- 1102 & 6false
- 299 & 3false
- 3104 & 8false
- 4100 & 4true
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उत्तर : 4. "100 & 4"
व्याख्या :
Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.
प्र: A shop keeper sells an article at a loss of 8%, but when he increases the selling price of the article by Rs. 164 he earns a profit of 2.25% on the cost price. If he sells the same article at Rs. 1760, what is his profit percentage? 2312 05b5cc62ae4d2b4197774b89f
5b5cc62ae4d2b4197774b89f- 12.5%false
- 25%false
- 310%true
- 47.5%false
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उत्तर : 3. "10%"
व्याख्या :
Answer: C) 10% Explanation: According to the given data, Let Cost price of the article be 'cp' Then, 102.25 cp - 92 cp = 164 x 100 10.25 cp = 16400 cp = 1600 Now, if he sells at Rs. 1760 Profit = 1760 - 1600 = 160 Profit% = 160/1600 x 100 = 10%.
प्र: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 2308 15b5cc72ce4d2b4197774f79c
5b5cc72ce4d2b4197774f79c- 142.2 mtsfalse
- 233.45 mtsfalse
- 366.6 mtstrue
- 458.78 mtsfalse
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उत्तर : 3. "66.6 mts"
व्याख्या :
Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.
प्र: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 2303 05b5cc728e4d2b4197774f6dc
5b5cc728e4d2b4197774f6dc- 135false
- 2165true
- 3221false
- 477false
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उत्तर : 2. "165"
व्याख्या :
Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.
प्र: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work ? 2299 05b5cc6e5e4d2b4197774ed3d
5b5cc6e5e4d2b4197774ed3d- 114 daystrue
- 218 daysfalse
- 321 deaysfalse
- 416 daysfalse
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उत्तर : 1. "14 days"
व्याख्या :
Answer: A) 14 days Explanation: Let A worked for x days. x/21 + 4/28 = 1 => x = 18 A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
प्र: What number should replace the question mark? 125, 138, 164, ?, 255 2295 05b5cc6a1e4d2b4197774cabd
5b5cc6a1e4d2b4197774cabd- 1189false
- 2197false
- 3200false
- 4203true
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उत्तर : 4. "203"
व्याख्या :
Answer: D) 203 Explanation: The given number series is 125, 138, 164, ?, 255 125 125 + 13x1 = 138 138 + 13x2 = 164 164 + 13x3 = 203 203 + 13x4 = 255 Hence, the missing number in the series is 203.
प्र: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 2291 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
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उत्तर : 4. "6011 hrs"
व्याख्या :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
प्र: A can do a piece of work in 10 days, B in 15 days. They work together for 5 days, the rest of the work is finished by C in two more days. If they get Rs. 3000 as wages for the whole work, what are the daily wages of A, B and C respectively (in Rs): 2288 05b5cc7d0e4d2b419777511d6
5b5cc7d0e4d2b419777511d6- 1200, 250, 300false
- 2300, 200, 250true
- 3200, 300, 400false
- 4None of thesefalse
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उत्तर : 2. "300, 200, 250"
व्याख्या :
Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50% B's 5 days work = 33.33% C's 2 days work = 16.66% [100- (50+33.33)] Ratio of contribution of work of A, B and C = 50 : 3313 : 1623 = 3 : 2 : 1 A's total share = Rs. 1500 B's total share = Rs. 1000 C's total share = Rs. 500 A's one day's earning = Rs.300 B's one day's earning = Rs.200 C's one day's earning = Rs.250

