Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 2318 0

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    102 & 6
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  • 2
    99 & 3
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  • 3
    104 & 8
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  • 4
    100 & 4
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उत्तर : 4. "100 & 4"
व्याख्या :

Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.

प्र: A shop keeper sells an article at a loss of 8%, but when he increases the selling price of the article by Rs. 164 he earns a profit of 2.25% on the cost price. If he sells the same article at Rs. 1760, what is his profit percentage? 2312 0

  • 1
    2.5%
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  • 2
    5%
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  • 3
    10%
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  • 4
    7.5%
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उत्तर : 3. "10%"
व्याख्या :

Answer: C) 10% Explanation: According to the given data, Let Cost price of the article be 'cp' Then, 102.25 cp - 92 cp = 164 x 100 10.25 cp = 16400 cp = 1600 Now, if he sells at Rs. 1760 Profit = 1760 - 1600 = 160   Profit% = 160/1600 x 100 = 10%.

प्र: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 2308 1

  • 1
    42.2 mts
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  • 2
    33.45 mts
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  • 3
    66.6 mts
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  • 4
    58.78 mts
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उत्तर : 3. "66.6 mts"
व्याख्या :

Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.

प्र: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 2303 0

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    35
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  • 2
    165
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  • 3
    221
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  • 4
    77
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उत्तर : 2. "165"
व्याख्या :

Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.

प्र: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work ? 2299 0

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    14 days
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  • 2
    18 days
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  • 3
    21 deays
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  • 4
    16 days
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उत्तर : 1. "14 days"
व्याख्या :

Answer: A) 14 days Explanation: Let A worked for x days. x/21 + 4/28 = 1  => x = 18   A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.

प्र: What number should replace the question mark? 125, 138, 164, ?, 255 2295 0

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    189
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  • 2
    197
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  • 3
    200
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  • 4
    203
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उत्तर : 4. "203"
व्याख्या :

Answer: D) 203 Explanation: The given number series is 125,   138,   164,   ?,   255   125   125 + 13x1 = 138   138 + 13x2 = 164   164 + 13x3 = 203   203 + 13x4 = 255       Hence, the missing number in the series is 203.

प्र: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 2291 0

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    2101 hrs
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  • 2
    4125 hrs
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  • 3
    5124 hrs
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  • 4
    6011 hrs
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उत्तर : 4. "6011 hrs"
व्याख्या :

Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.

प्र: A can do a piece of work in 10 days, B in 15 days. They work together for 5 days, the rest of the work is finished by C in two more days. If they get Rs. 3000 as wages for the whole work, what are the daily wages of A, B and C respectively (in Rs): 2288 0

  • 1
    200, 250, 300
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  • 2
    300, 200, 250
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  • 3
    200, 300, 400
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  • 4
    None of these
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उत्तर : 2. "300, 200, 250"
व्याख्या :

Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50%   B's 5 days work = 33.33%  C's 2 days work = 16.66%     [100- (50+33.33)]  Ratio of contribution of work of A, B and C = 50 : 3313 : 1623 = 3 : 2 : 1    A's total share = Rs. 1500  B's total share = Rs. 1000  C's total share = Rs. 500     A's one day's earning = Rs.300   B's one day's earning = Rs.200   C's one day's earning = Rs.250

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