Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50%   B's 5 days work = 33.33%  C's 2 days work = 16.66%     [100- (50+33.33)]  Ratio of contribution of work of A, B and C = 50 : 3313 : 1623 = 3 : 2 : 1    A's total share = Rs. 1500  B's total share = Rs. 1000  C's total share = Rs. 500     A's one day's earning = Rs.300   B's one day's earning = Rs.200   C's one day's earning = Rs.250

Answer: A) 34 Explanation: M + Tu + W + Th = 4 x 48 = 192Tu + W + Th + F = 4 x 46 = 184M = 42Tu + W + Th = 192 - 42 = 150F = 184 – 150 = 34

Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.

Answer: C) 1/6 Explanation: Given X can do in 10 days  => 1 day work of X = 1/10   Y can do in 15 days  => 1 day work of Y = 1/15   1day work of (X + Y) = 1/10 + 1/15 = 1/6   Given they are hired for 5 days  => 5 days work of (X + Y) = 5 x 1/6 = 5/6  Therefore, Unfinished work = 1 - 5/6 = 1/6

Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m  Now, as the tent is in the conical form Volume of the conical tent = πr2h3  => (22 x 5 x 5 x 3) / (7 x 3)  = 22 x 25/7  = 78.54 cu.m  Given each person requires 3.92 cu.m of air  => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

Answer: A) i Explanation: We know that, i2 = -1i3 = i2 x i = -1 x i = -ii4 = i2 x i2 = -1 x -1 = 1Hence, i233  =i4 x 58 + 1 = i232 x i1 = 1 x i = i

Answer: B) 210 Explanation: Let the required number be 'p' We know, sum of angles in a triangle are 180 deg According to given data, p - p/7 = 180 7p - p = 180 x 7 => 6p = 1260 => p = 1260/6 = 210

Answer: D) 203 Explanation: The given number series is 125,   138,   164,   ?,   255   125   125 + 13x1 = 138   138 + 13x2 = 164   164 + 13x3 = 203   203 + 13x4 = 255       Hence, the missing number in the series is 203.