Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A tailor has 37.5 metres of cloth and he has to make 8 pieces out of a metre of cloth. How many pieces can he make out of half of the cloth he has ? 2765 05b5cc6dfe4d2b4197774eb0c
5b5cc6dfe4d2b4197774eb0c- 1300false
- 2150true
- 3175false
- 4200false
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उत्तर : 2. "150"
व्याख्या :
Answer: B) 150 Explanation: Half of the cloth = 37.5/2 From 1 meter he will make 8 pieces=> in 37.5/2 ---- ? 37.5/2 x 8 = 150.
प्र: Three milkmen rented a pasture. A grazed 24 cows for 4 months; B 10 cows for 6 months; C 56 cows for 5 months. If A's share of rent is Rs. 960, find the total rent of the field? 2764 05b5cc783e4d2b419777501f1
5b5cc783e4d2b419777501f1- 14530false
- 24440false
- 34360true
- 44280false
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उत्तर : 3. "4360"
व्याख्या :
Answer: C) 4360 Explanation: Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5) = 96 : 60 : 280. Let total rent be Rs. x. Then, A's share = Rs.96x436 ∴96x436=960 ⇔x=960×43696=4360 Hence total rent of the field is Rs. 4360.
प्र: A retailer buys product from a shopkeeper at discount of 40% on the list price (marked price) and sells them to the customer at a discount of 25% on the list price.What is his profit percentage ? 2763 05b5cc7a5e4d2b4197775066f
5b5cc7a5e4d2b4197775066f- 110%false
- 215%false
- 320%false
- 425%true
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उत्तर : 4. "25%"
व्याख्या :
Answer: D) 25% Explanation: Let the list price be Rs.100. Therefore, the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15. Therefore, his percentage is = 1560x100 = 25%
प्र: Two bottles contains mixture of milk and water. First bottle contains 64% milk and second bottle contains 26% water. In what ratio these two mixtures are mixed so that new mixture contains 68% milk? 2763 05b5cc626e4d2b4197774b82a
5b5cc626e4d2b4197774b82a- 13 : 2true
- 22 : 1false
- 31 : 2false
- 42 : 3false
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उत्तर : 1. "3 : 2"
व्याख्या :
Answer: A) 3 : 2 Explanation: % of milk in first bottle = 64% % of milk in second bottle = 100 - 26 = 74% Now, ATQ 64% 74% 68% 6 4 Hence, by using allegation method, Required ratio = 3 : 2
प्र: Find the missing number in the following Series ? 18, 97, 26, 91, ? , 83 2760 05b5cc6c2e4d2b4197774dbaf
5b5cc6c2e4d2b4197774dbaf- 132false
- 236false
- 330false
- 434true
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उत्तर : 4. "34"
व्याख्या :
Answer: D) 34 Explanation: The given series follows the pattern that, 18, 97, 26, 91, ?, 83 => 18 + 8 = 26 => 97 - 8 = 91 => 26 + 8 = 34 => 91 - 8 = 83 Hence, the missing number is 34.
प्र: A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece? 2750 05b5cc6bbe4d2b4197774d85d
5b5cc6bbe4d2b4197774d85d- 128 cmfalse
- 23.5 cmfalse
- 37 cmfalse
- 414 cmtrue
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उत्तर : 4. "14 cm"
व्याख्या :
Answer: D) 14 cm Explanation: Circular piece is 4 x 11 = 44 cm long, Then Circumference of circle is given by, 44 = pi x D, where D is the diameter D = 44 / pi Take pi = 22 / 7, then D = 44 / (22/7) = (44 x 7) / 22 D = 14 cm.
प्र: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 2748 05b5cc6bbe4d2b4197774d80c
5b5cc6bbe4d2b4197774d80c- 1102 & 6false
- 299 & 3false
- 3104 & 8false
- 4100 & 4true
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उत्तर : 4. "100 & 4"
व्याख्या :
Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.
प्र: A train covers a distance between station A and station B in 45 min.If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min.what is the distance between the stations A and B ? 2746 05b5cc70ee4d2b4197774f347
5b5cc70ee4d2b4197774f347- 180 kmsfalse
- 260 kmstrue
- 345 kmsfalse
- 432 kmsfalse
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उत्तर : 2. "60 kms"
व्याख्या :
Answer: B) 60 kms Explanation: Let 'd' be the distance and 's' be the speed and 't' be the timed=sxt45 mins = 3/4 hr and 48 mins = 4/5 hrAs distance is same in both cases;s(3/4) = (s-5)(4/5)3s/4 = (4s-20)/515s = 16s-80s = 80 km.=> d = 80 x 3/4 = 60 kms.