Answer: C) 13 days Explanation: Now, Total work = LCM(16, 8) = 48 A's one day work = + 48/16 = + 3 B's one day work = - 48/8 = -6 Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15 2days B joined with A in working = 2(3 - 6) = - 6 Remaining Work of building wall = 48 - (15 - 6) = 39 Now this remaining work will be done by A in = 39/3 = 13 days.

Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115  ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23   Hence, required number of gentlemen in the family = x = 23.

Answer: C) 12 Explanation: we can do this by trial and error method. Putting x = 2,we get 2²(2² - 1) = 12.checking with other integers, the above equation always gives a value which is a multiple of 12,So, x²(x² - 1) is always divisible by 12.

Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms

Answer: B) 210 Explanation: Let the required number be 'p' We know, sum of angles in a triangle are 180 deg According to given data, p - p/7 = 180 7p - p = 180 x 7 => 6p = 1260 => p = 1260/6 = 210

Answer: A) 14 days Explanation: Let A worked for x days. x/21 + 4/28 = 1  => x = 18   A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.

Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd.   4 women can be arranged at 4 even places in 4! ways.   and 5 men can be placed in remaining 5 places in 5! ways.   Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880

Answer: B) 32 sec Explanation: Given that, 1st train speed = 62 km/hr  2nd train speed  = 44 km/hr Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s. There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in,    time = distancespeed = 85+755 = 32 sec.