Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the next number in the following number series? 11, 13, 30, 96, ? 2236 05b5cc688e4d2b4197774c318
5b5cc688e4d2b4197774c318- 1264false
- 2392true
- 3412false
- 4459false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "392"
व्याख्या :
Answer: B) 392 Explanation: The given number series 11, 13, 30, 96, ? follows a pattern that, 11 11 x 1 + 2 = 13 13 x 2 + 4 = 30 30 x 3 + 6 = 96 96 x 4 + 8 = 392 Hence, the next number in the given series is 392.
प्र: How many square units in 13 by 9? 2234 05b5cc615e4d2b4197774b6b8
5b5cc615e4d2b4197774b6b8- 113false
- 29false
- 3117true
- 413/9false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 3. "117"
व्याख्या :
Answer: C) 117 Explanation: Number of square units in 13 by 9 is given by the area it forms with length and breadth as 13 & 9 Area = 13 x 9 = 117 Hence, number of square units in 13 by 9 is 117 sq.units.
प्र: A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ? 2228 05b5cc6cee4d2b4197774e208
5b5cc6cee4d2b4197774e208- 112 daysfalse
- 214 daysfalse
- 313 daystrue
- 416 daysfalse
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 3. "13 days"
व्याख्या :
Answer: C) 13 days Explanation: Now, Total work = LCM(16, 8) = 48 A's one day work = + 48/16 = + 3 B's one day work = - 48/8 = -6 Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15 2days B joined with A in working = 2(3 - 6) = - 6 Remaining Work of building wall = 48 - (15 - 6) = 39 Now this remaining work will be done by A in = 39/3 = 13 days.
प्र: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2227 05b5cc6c5e4d2b4197774dd23
5b5cc6c5e4d2b4197774dd23- 15.75 kmsfalse
- 27.36 kmstrue
- 38.2 kmsfalse
- 46.98 kmsfalse
- उत्तर देखेंउत्तर छिपाएं
- Workspace
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उत्तर : 2. "7.36 kms"
व्याख्या :
Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms
प्र: Three milkmen rented a pasture. A grazed 24 cows for 4 months; B 10 cows for 6 months; C 56 cows for 5 months. If A's share of rent is Rs. 960, find the total rent of the field? 2225 05b5cc783e4d2b419777501f1
5b5cc783e4d2b419777501f1- 14530false
- 24440false
- 34360true
- 44280false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 3. "4360"
व्याख्या :
Answer: C) 4360 Explanation: Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5) = 96 : 60 : 280. Let total rent be Rs. x. Then, A's share = Rs.96x436 ∴96x436=960 ⇔x=960×43696=4360 Hence total rent of the field is Rs. 4360.
प्र: Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev? 2218 05b5cc655e4d2b4197774bd70
5b5cc655e4d2b4197774bd70- 112false
- 214false
- 322false
- 410true
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उत्तर : 4. "10"
व्याख्या :
Answer: D) 10 Explanation: Let Rajeev's present age be x years. Rajeev's age after 15 years = (x + 15) years. Rajeev's age 5 years back = (x - 5) years Then ATQ, x + 15 = 5 (x - 5) x + 15 = 5x - 25 => x = 10 Hence, Rajeev's present age = x = 10 years.
प्र: The third proportional to 9 and 12 is ? 2213 05b5cc6e9e4d2b4197774ede8
5b5cc6e9e4d2b4197774ede8- 114false
- 216true
- 318false
- 420false
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उत्तर : 2. "16"
व्याख्या :
Answer: B) 16 Explanation: Let the third proportion to 9 & 12 be 'x'. => 9:12 = 12 :p => p = 12x12/9 = 16.
प्र: From a bunch of flowers having 16 red roses and 14 white roses, four flowers have to be selected. In how many different ways can they be selected such that at least one red rose is selected? 2210 05b5cc77ae4d2b41977750165
5b5cc77ae4d2b41977750165- 127405false
- 226584false
- 326585false
- 427404true
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 4. "27404"
व्याख्या :
Answer: D) 27404 Explanation: Given total 16 Red roses and 14 White roses = 30 roses Four flowers have to be selected from 30 i.e, C430= 27405 Ways Now, atleast one Red rose is selected i.e, 27405(total) - 1(all four are white roses) = 27404 ways.

