Answer: A) 1/7 Explanation: A leap year has 52 weeks and two daysTotal number of cases = 7Number of favourable cases = 1i.e., {Friday, Saturday} Required Probability = 1/7

Answer: C) 20 Explanation: Given (2a + 3b)/(5a - 3b) = 23/5 => 10a + 15b = 115a - 69b=> 105a = 84b => 5a = 4b a/b = 4/5 => a=4 & b=5=> bxa = 5x4 = 20.

Answer: B) 32 sec Explanation: Given that, 1st train speed = 62 km/hr  2nd train speed  = 44 km/hr Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s. There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in,    time = distancespeed = 85+755 = 32 sec.

Answer: A) Sunday Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004. Given that, 5th March, 2005 is Monday. 5th March, 2004 is Sunday (1 day before to 5th March, 2005).

Answer: A) 50 yrs Explanation: Let the daughter age be 'x'Therefore, Son age = 5x, Mother age = 25x, Person age = 50x. Thus we get, x+5x+25x+50x = 8181x = 81x = 1 Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.

Answer: B) 60 degrees Explanation: Given the angles of a quadrilateral are in the ratio of 2:4:7:5Let the angles of a quadrilateral are 2x, 4x, 7x, 5xBut we know that sum of the angles = 360 degrees.=> 2x + 4x + 7x + 5x = 360=> x = 20Therfore, the smallest angle of the quadrilateral = 2x = 2x20 = 40 degrees.One of the angle of the triangle = 2 x 40 = 80 degreesThe other angle is 180 - (40 + 80) = 60 degrees. Hence the second largest angle of the triangle is 60 degrees.

Answer: D) 0 Explanation: 1523+2323=19-423+19+423    The remainder on dividing by 19 will be -423+423= 0.

Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.