Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is: 2462 05b5cc6e7e4d2b4197774ed7e
5b5cc6e7e4d2b4197774ed7e- 1Rs. 408false
- 2Rs. 204true
- 3Rs. 412false
- 4Rs. 220false
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उत्तर : 2. "Rs. 204"
व्याख्या :
Answer: B) Rs. 204 Explanation: Given ratio = 1/2:2/3:3/4 = 6:8:9 1st part = 782 x 6/23 = Rs. 204.
प्र: 2.5, 3.5, 9, 40, ? Find the next number in the above-given series? 2461 05b5cc6bae4d2b4197774d7df
5b5cc6bae4d2b4197774d7df- 1316false
- 2328true
- 3323false
- 4340false
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उत्तर : 2. "328"
व्याख्या :
Answer: B) 328 Explanation: 2.5 × 1 + 1 = 3.5 3.5 × 2 + 2 = 9 9 × 4 + 4 = 40 40 × 8 + 8 = 328
प्र: Ravi and Ramu are partners in a business.Ravi contributes 1/6 of the capital for 16 months and Ramu received 2/3 of the profit. For how long Ramu's money was used ? 2460 05b5cc71ee4d2b4197774f590
5b5cc71ee4d2b4197774f590- 111 monthsfalse
- 210 monthsfalse
- 39 monthsfalse
- 48 monthstrue
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उत्तर : 4. "8 months"
व्याख्या :
Answer: D) 8 months Explanation: Let the total Profit be Z.Ramu's profit share is 2/3 of profit (i.e 2Z/3)Ravi's profit is (Z-2Z/3) =Z/3Hence the profit ratio is , Ravi : Ramu = Z/3 : 2Z/3 = 1:2 Let total Capital be Rs.X and Ramu has contributed for Y months.Since Ramu's profit share is 2/3, his invest share will be 2/3 in capital. Ravi's invest for 16 months / Ramu's invest for Y months = Ravi's profit share / Ramu's profit sharei.e. (X/6 x 16) / (2X/3 x Y) = 1/2 Solving the above equation, we get Y = 8.So Ramu's money has been used for 8 months.
प्र: A passenger train covers the distance between station K and L, 40 minutes faster than a goods train. Find this distance between K and L if the average speed of the passenger train is 50 km/h and that of goods train is 30 km/h? 2459 05b5cc6b4e4d2b4197774d4c5
5b5cc6b4e4d2b4197774d4c5- 150 kmstrue
- 248 kmsfalse
- 346 kmsfalse
- 444 kmsfalse
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उत्तर : 1. "50 kms"
व्याख्या :
Answer: A) 50 kms Explanation: Let the distance be 'd' kms. According to the given data, d30 - d50 = 4060 hrs=> 6d = 300=> d = 50 kms.
प्र: 3131×31-27 =? 2457 05b5cc783e4d2b419777501e2
5b5cc783e4d2b419777501e2- 1961 x 861false
- 2961 x 961true
- 3961 x 2false
- 429791false
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उत्तर : 2. "961 x 961"
व्याख्या :
Answer: B) 961 x 961 Explanation: We know that am×an=am+n ∴3131-27 = 314 = 961 x 961.
प्र: From a bunch of flowers having 16 red roses and 14 white roses, four flowers have to be selected. In how many different ways can they be selected such that at least one red rose is selected? 2456 05b5cc77ae4d2b41977750165
5b5cc77ae4d2b41977750165- 127405false
- 226584false
- 326585false
- 427404true
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उत्तर : 4. "27404"
व्याख्या :
Answer: D) 27404 Explanation: Given total 16 Red roses and 14 White roses = 30 roses Four flowers have to be selected from 30 i.e, C430= 27405 Ways Now, atleast one Red rose is selected i.e, 27405(total) - 1(all four are white roses) = 27404 ways.
प्र: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 2456 05b5cc75ee4d2b4197774fcc0
5b5cc75ee4d2b4197774fcc0- 127 %true
- 226 %false
- 329 %false
- 421 %false
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उत्तर : 1. "27 %"
व्याख्या :
Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %
प्र: If Reena’s age was twice of her present age, when subtracted from four times three years from hence, with three times the three years before her present age. What will be her age after one year ? 2456 05b5cc70ee4d2b4197774f37b
5b5cc70ee4d2b4197774f37b- 122 yrstrue
- 221 yrsfalse
- 320 yrsfalse
- 424 yrsfalse
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उत्तर : 1. "22 yrs"
व्याख्या :
Answer: A) 22 yrs Explanation: Let Reena’s present age be 'K' yrs.Given:{(K+3) x 4} - {(K-3) x 3)} => K = 21 yrsSo her present age is 21 yrs.Then, her age after 1 year is 22 yrs.

