Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is : 2100 05b5cc6e7e4d2b4197774ed88
5b5cc6e7e4d2b4197774ed88- 1Rs. 560false
- 2Rs. 530false
- 3Rs. 500true
- 4Rs. 514false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "Rs. 500"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) Rs. 500 Explanation: 110% of S.P. = Rs. 616 S.P. = (616 x 100)/110 = Rs. 560 C.P = (110 x 560)/112 = Rs. 500
рдкреНрд░: The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday ? 2321 05b5cc6e7e4d2b4197774ed83
5b5cc6e7e4d2b4197774ed83- 134true
- 236false
- 338false
- 440false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "34"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 34 Explanation: M + Tu + W + Th = 4 x 48 = 192Tu + W + Th + F = 4 x 46 = 184M = 42Tu + W + Th = 192 - 42 = 150F = 184 тАУ 150 = 34
рдкреНрд░: If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is: 2104 05b5cc6e7e4d2b4197774ed7e
5b5cc6e7e4d2b4197774ed7e- 1Rs. 408false
- 2Rs. 204true
- 3Rs. 412false
- 4Rs. 220false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "Rs. 204"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) Rs. 204 Explanation: Given ratio = 1/2:2/3:3/4 = 6:8:9 1st part = 782 x 6/23 = Rs. 204.
рдкреНрд░: A train sets off at 3 p.m. at the speed of 70 kmph. Another train starts at 4:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet ? 2333 05b5cc6e7e4d2b4197774ed79
5b5cc6e7e4d2b4197774ed79- 110:10 pmfalse
- 29:50 pmfalse
- 311:30 pmtrue
- 410:30 pmfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "11:30 pm"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 11:30 pm Explanation: Distance = 70 x 1 ┬╜ = 105 km Relative Speed = 85 тАУ 70 = 15 Time = 105/15 = 7 hrs 4:30 + 7 hrs = 11.30 p.m.
рдкреНрд░: Twenty times a positive integer is less than its square by 96. What is the integer ? 1697 05b5cc6e7e4d2b4197774ed74
5b5cc6e7e4d2b4197774ed74- 142false
- 236false
- 348false
- 424true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "24"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 24 Explanation: Let the integer be x. Then, x2 - 20x = 96 (x + 4)(x - 24) = 0 x = 24
рдкреНрд░: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ? 1481 05b5cc6e7e4d2b4197774ed6f
5b5cc6e7e4d2b4197774ed6f- 110 yrstrue
- 211 yrsfalse
- 312 yrsfalse
- 413 yrsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "10 yrs"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 10 yrs Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 => x = 5 Hence, B's age = 2x = 10 years.
рдкреНрд░: A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ? 1588 05b5cc6e7e4d2b4197774ed6a
5b5cc6e7e4d2b4197774ed6a- 1115false
- 2117true
- 3116false
- 4114false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "117"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 117 Explanation: Length = 6 m 24 cm = 624 cmWidth = 4 m 32 cm = 432 cmHCF of 624 and 432 = 48Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.
рдкреНрд░: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3427 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "127.5 m"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

