Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ? 2010 0

  • 1
    60
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  • 2
    120
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  • 3
    360
    सही
    गलत
  • 4
    6
    सही
    गलत
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उत्तर : 4. "6"
व्याख्या :

Answer: D) 6 Explanation: For this we have to find the LCM of 24, 36 and 30 LCM of 24, 36 and 30 = 360 sec 360/60 min = 6 minutes.

प्र: What is the equivalent compound ratio of 5:6::7:10::6:5  ? 2010 0

  • 1
    7 : 9
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  • 2
    9 : 7
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  • 3
    7 : 4
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  • 4
    7 : 10
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उत्तर : 4. "7 : 10"
व्याख्या :

Answer: D) 7 : 10 Explanation: Given 5:6 :: 7:10 :: 6:5 We know that compound ratio is calculated as a:b :: c:d :: e:f(axcxe):(bxdxf) => (5x7x6):(6x10x5)=> (210):(300)= 7:10

प्र: 7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age? 2009 0

  • 1
    91 years
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  • 2
    115 years
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  • 3
    103 years
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  • 4
    Can't be determined
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उत्तर : 3. "103 years"
व्याख्या :

Answer: C) 103 years Explanation: Let present Anirudh's age be 'A' and Bhavana's age be 'B' Given seven years, their ratio is 7:9 => A-7 : B-7 = 7 : 9 => 9A - 7B = 14 .......(1) And given, Chandhu is 12 years older than A nad 12 years younger than B => C = A + 12....(2) => B = C + 12 => B = A + 12 + 12 .....(From (2)) => B = A + 24 ....(3) Put (3) in (1) 9A - 7(A+24) = 14 9A - 7A - 168 = 14 2A = 182 => A = 91 years => C = A + 12 = 91 +12 = 103 years.

प्र: A man rows his boat 60 km downstream and 30 km upstream taking 3 hrs each time. Find the speed of the stream ? 2008 0

  • 1
    5 kmph
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  • 2
    10 kmph
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  • 3
    15 kmph
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  • 4
    45 kmph
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उत्तर : 1. "5 kmph"
व्याख्या :

Answer: A) 5 kmph Explanation: Speed of the boat downstream  s=a/t= 60/3 = 20 kmph Speed of the boat upstream s= d/t = 30/3= 10 kmph   Therefore,  The speed of the stream = speed of downstream - speed of upstream2=5 kmph

प्र: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 2008 0

  • 1
    Rs.2010
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  • 2
    Rs.2200
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  • 3
    Rs.2000
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  • 4
    Rs.2100
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उत्तर : 3. "Rs.2000"
व्याख्या :

Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.

प्र: K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ? 2007 0

  • 1
    6:00 am
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  • 2
    6:30 pm
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  • 3
    5:45 am
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  • 4
    5:52 pm
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उत्तर : 2. "6:30 pm"
व्याख्या :

Answer: B) 6:30 pm Explanation: Suppose they meet after 'h' hours Then 3h + 4h = 17.5 7h = 17.5 h = 2.5 hours So they meet at => 4 + 2.5 = 6:30 pm

प्र: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 2006 0

  • 1
    175
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  • 2
    345
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  • 3
    265
    सही
    गलत
  • 4
    300
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उत्तर : 4. "300"
व्याख्या :

Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.

प्र: If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 2002 0

  • 1
    2.8 hrs
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  • 2
    2.7 hrs
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  • 3
    2.6 hrs
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  • 4
    2.5 hrs
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उत्तर : 2. "2.7 hrs"
व्याख्या :

Answer: B) 2.7 hrs Explanation: Let Speed of boat in still water = b Let Speed of still water = w Then we know that, Speed of Upstream = U = boat - water Speed of Downstream = D = boat + water Given, U + D = 82 b - w + b + w = 82 2b = 82 => b = 41 kmph From the given data, 41 - w = 105/3 = 35 w = 6 kmph Now, b + w = 126/t => 41 + 6 = 126/t => t = 126/47  = 2.68 hrs.

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