Quantitative Aptitude Practice Question and Answer

Q: Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ? 2294 0

  • 1
    60
    Correct
    Wrong
  • 2
    120
    Correct
    Wrong
  • 3
    360
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 4. "6"
Explanation :

Answer: D) 6 Explanation: For this we have to find the LCM of 24, 36 and 30 LCM of 24, 36 and 30 = 360 sec 360/60 min = 6 minutes.

Q: The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is : 2293 0

  • 1
    Rs. 560
    Correct
    Wrong
  • 2
    Rs. 530
    Correct
    Wrong
  • 3
    Rs. 500
    Correct
    Wrong
  • 4
    Rs. 514
    Correct
    Wrong
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Answer : 3. "Rs. 500"
Explanation :

Answer: C) Rs. 500 Explanation: 110% of S.P. = Rs. 616 S.P. = (616 x 100)/110 = Rs. 560 C.P = (110 x 560)/112 = Rs. 500

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Answer : 3. "Rs. 10664.15"
Explanation :

Answer: C) Rs. 10664.15 Explanation: Profit received by Chinna as working partner = 14.5% of Rs. 19600 = 14.5x19600/100 = Rs. 2842 Balance in profit = 19600-2842 = Rs. 16758 Ratio of investment of Chinna & Munna = 80,000 : 1,40,000 = 4 : 7 Hence share of Chinna in investment = 4x16758/100 = Rs. 6093.85 Therefore, Share of Munna = 19600 - 2842 - 6093.85 = Rs. 10664.15

Q: Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ? 2291 0

  • 1
    25 years
    Correct
    Wrong
  • 2
    24 years
    Correct
    Wrong
  • 3
    23 years
    Correct
    Wrong
  • 4
    22 years
    Correct
    Wrong
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Answer : 1. "25 years"
Explanation :

Answer: A) 25 years Explanation: Let varun's age = x yrs. From the given conditions, x+1  =  2(x-12) x = 25 years.

Q: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 2291 0

  • 1
    Rs.2010
    Correct
    Wrong
  • 2
    Rs.2200
    Correct
    Wrong
  • 3
    Rs.2000
    Correct
    Wrong
  • 4
    Rs.2100
    Correct
    Wrong
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Answer : 3. "Rs.2000"
Explanation :

Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.

Q: Madhu started a business and he invested in 76000, After some month, Amar came to join with him and invest 57000.The end of the year the total profit was divided among them into ratio form 2 : 1.Find after how many months Amar join. 2290 0

  • 1
    7 months
    Correct
    Wrong
  • 2
    8 months
    Correct
    Wrong
  • 3
    3 months
    Correct
    Wrong
  • 4
    4 months
    Correct
    Wrong
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Answer : 4. "4 months"
Explanation :

Answer: D) 4 months Explanation: we can assume that Amar join into business after x months. So Amar money was invest into  (12 – x ) months.   76000×1257000×(12-x)=21   --> 912000 = 114000 ( 12 – x ) = 114 ( 12 – x ) = 912 --> x = 4 After 4 months amar join the business.

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Answer : 2. "535"
Explanation :

Answer: B) 535 Explanation: The number of points of intersection of 37 lines is C237. But 13 straight lines out of the given 37 straight lines pass through the same point A.   Therefore instead of getting C213 points, we get only one point A. Similarly 11 straight lines out of the given 37 straight lines intersect at point B. Therefore instead of getting C211 points, we get only one point B.    Hence the number of intersection points of the lines is C237-C213-C211 +2 = 535

Q: Find the odd man out of the following number sequence? 3, 5, 13, 43, 167 2289 0

  • 1
    167
    Correct
    Wrong
  • 2
    43
    Correct
    Wrong
  • 3
    13
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 1. "167"
Explanation :

Answer: A) 167 Explanation: The given number series is 3, 5, 13, 43, 167 3 3 x 1 + 2 = 5 5 x 2 + 3 = 13 13 x 3 + 4 = 43 43 x 4 + 5 = 177 (not equal to 167)   Hence, the odd number in the given number sequence is 167.

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