Quantitative Aptitude Practice Question and Answer

Q: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 2193 0

  • 1
    Rs.2010
    Correct
    Wrong
  • 2
    Rs.2200
    Correct
    Wrong
  • 3
    Rs.2000
    Correct
    Wrong
  • 4
    Rs.2100
    Correct
    Wrong
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Answer : 3. "Rs.2000"
Explanation :

Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.

Q: A fair six-sided die is rolled twice. What is the probability of getting 4 on the first roll and not getting 6 on the second roll ? 2192 0

  • 1
    1/36
    Correct
    Wrong
  • 2
    5/36
    Correct
    Wrong
  • 3
    1/12
    Correct
    Wrong
  • 4
    1/9
    Correct
    Wrong
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Answer : 2. "5/36"
Explanation :

Answer: B) 5/36 Explanation: The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied. P(getting first 4) = 1/6 P(no second 6) = 5/6 Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36

Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 2191 0

  • 1
    79
    Correct
    Wrong
  • 2
    77
    Correct
    Wrong
  • 3
    76
    Correct
    Wrong
  • 4
    73
    Correct
    Wrong
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Answer : 1. "79"
Explanation :

Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.

Q: A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ? 2191 0

  • 1
    12
    Correct
    Wrong
  • 2
    13
    Correct
    Wrong
  • 3
    11
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 1. "12"
Explanation :

Answer: A) 12 Explanation: Given 45 kg for painting  And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg Now total paint required = 45+2.7 = 47.7 kgs But tins are available in only 4kgs Then, no. of tins req = 47.7/4 = 11.4 => 12 tins

Q: The missing number in the Series 114, 131, 165, 216,  ?, 369 2186 0

  • 1
    314
    Correct
    Wrong
  • 2
    304
    Correct
    Wrong
  • 3
    294
    Correct
    Wrong
  • 4
    284
    Correct
    Wrong
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Answer : 4. "284"
Explanation :

Answer: D) 284 Explanation: 114       131     165     216     ?      369    +17      +34     +51     +68    +85   => The missing number in the given Number series = 216 + 68 = 284.

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Answer : 3. "109"
Explanation :

Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109

Q: If a+b=5 and 3a+2b=20,then (3a+b)will be : 2182 0

  • 1
    20
    Correct
    Wrong
  • 2
    15
    Correct
    Wrong
  • 3
    25
    Correct
    Wrong
  • 4
    30
    Correct
    Wrong
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Answer : 3. "25"
Explanation :

Answer: C) 25 Explanation: a+b=5   ...(1)    and    3a+2b=20 ...(2)   Multiplying (1) by 2 and subtracting from (2), we get : a=10.   Putting a=10 in (1), we get : b=-5   Therefore,   (3a+b) = 3 x 10+(-5)=30-5=25.

Q: There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ? 2182 0

  • 1
    1/10
    Correct
    Wrong
  • 2
    1/9
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    0
    Correct
    Wrong
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Answer : 4. "0"
Explanation :

Answer: D) 0 Explanation: As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address P(E) = favorable outcomes /total outcomesHere favorable outcomes are '0'.So probability is '0'.

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