Quantitative Aptitude Practice Question and Answer
8Q: Which is better investment : 11% stock at 143 (or) 9 3/4% stock at 117 ? 2287 05b5cc71be4d2b4197774f53f
5b5cc71be4d2b4197774f53f- 1Both are equally goodfalse
- 29 3/4% stock at 117true
- 3Cannot be compared, as the total amount of investment is not givenfalse
- 411% stock at 143false
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Answer : 2. "9 3/4% stock at 117"
Explanation :
Answer: B) 9 3/4% stock at 117 Explanation: Let investment in each case be Rs. (143 x 117). Income in 1st case = Rs.11143 x 143 x 117 = Rs. 1287.Income in 2nd case = Rs.394×117 x 143 x 117= Rs. 1394.25 Clearly, 9 3/4% stock at 117 is better.
Q: 28 Men and 52 women working together completes a work in 22.5 days. 35 men and 65 women working together on same work will complete it in how many days? 2285 05b5cc6bde4d2b4197774d93d
5b5cc6bde4d2b4197774d93d- 116false
- 218true
- 319false
- 421false
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Answer : 2. "18"
Explanation :
Answer: B) 18 Explanation: Clearly total persons are increased in 28/35 :: 52/65 = 4:5. As time is inversely proportional to men, so total time will decrease in the ratio 5:4. Hence, 22.5 x 4/5 = 18 days.
Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 2284 05b5cc74fe4d2b4197774fb21
5b5cc74fe4d2b4197774fb21- 179true
- 277false
- 376false
- 473false
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Answer : 1. "79"
Explanation :
Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.
Q: A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ? 2280 05b5cc6d1e4d2b4197774e3e3
5b5cc6d1e4d2b4197774e3e3- 112true
- 213false
- 311false
- 410false
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Answer : 1. "12"
Explanation :
Answer: A) 12 Explanation: Given 45 kg for painting And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg Now total paint required = 45+2.7 = 47.7 kgs But tins are available in only 4kgs Then, no. of tins req = 47.7/4 = 11.4 => 12 tins
Q: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 2278 05b5cc74ae4d2b4197774fad6
5b5cc74ae4d2b4197774fad6- 1175false
- 2345false
- 3265false
- 4300true
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Answer : 4. "300"
Explanation :
Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.
Q: The missing number in the Series 114, 131, 165, 216, ?, 369 2277 05b5cc6b3e4d2b4197774d3fd
5b5cc6b3e4d2b4197774d3fd- 1314false
- 2304false
- 3294false
- 4284true
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Answer : 4. "284"
Explanation :
Answer: D) 284 Explanation: 114 131 165 216 ? 369 +17 +34 +51 +68 +85 => The missing number in the given Number series = 216 + 68 = 284.
Q: In a mixture of three varities of oils , the ratio of their weight is 4 : 5 : 8. If 5 kg of oils of the first variety, 10 kg of the second variety and some quantity of oils of the third variety are added to the mixture, the ratio of the weights of three varieties of oils becomes as 5 : 7 : 9 in the final mixture, find the quantity of third variety of oil was ? 2275 05b5cc6cce4d2b4197774e177
5b5cc6cce4d2b4197774e177- 115 kgfalse
- 225 kgfalse
- 335 kgfalse
- 445 kgtrue
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Answer : 4. "45 kg"
Explanation :
Answer: D) 45 kg Explanation: Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.Let k be the quantity of third variety of oil in the final mixture.Let the ratio of initial quantity of oils be 'y'From given details,4x + 5 = 5y ..... (1)5x + 10 = 7y .....(2)8x + k = 9y ......(3) By solving (1) & (2), we getx = 5 & y = 5 From (3) => k = 5 Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.
Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 2274 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
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Answer : 1. "277"
Explanation :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.

