Quantitative Aptitude Practice Question and Answer
8Q: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 2193 05b5cc75ee4d2b4197774fc9d
5b5cc75ee4d2b4197774fc9d- 1Rs.2010false
- 2Rs.2200false
- 3Rs.2000true
- 4Rs.2100false
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Answer : 3. "Rs.2000"
Explanation :
Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.
Q: A fair six-sided die is rolled twice. What is the probability of getting 4 on the first roll and not getting 6 on the second roll ? 2192 05b5cc6d7e4d2b4197774e6c1
5b5cc6d7e4d2b4197774e6c1- 11/36false
- 25/36true
- 31/12false
- 41/9false
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Answer : 2. "5/36"
Explanation :
Answer: B) 5/36 Explanation: The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied. P(getting first 4) = 1/6 P(no second 6) = 5/6 Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36
Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 2191 05b5cc74fe4d2b4197774fb21
5b5cc74fe4d2b4197774fb21- 179true
- 277false
- 376false
- 473false
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Answer : 1. "79"
Explanation :
Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.
Q: A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ? 2191 05b5cc6d1e4d2b4197774e3e3
5b5cc6d1e4d2b4197774e3e3- 112true
- 213false
- 311false
- 410false
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Answer : 1. "12"
Explanation :
Answer: A) 12 Explanation: Given 45 kg for painting And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg Now total paint required = 45+2.7 = 47.7 kgs But tins are available in only 4kgs Then, no. of tins req = 47.7/4 = 11.4 => 12 tins
Q: The missing number in the Series 114, 131, 165, 216, ?, 369 2186 05b5cc6b3e4d2b4197774d3fd
5b5cc6b3e4d2b4197774d3fd- 1314false
- 2304false
- 3294false
- 4284true
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Answer : 4. "284"
Explanation :
Answer: D) 284 Explanation: 114 131 165 216 ? 369 +17 +34 +51 +68 +85 => The missing number in the given Number series = 216 + 68 = 284.
Q: Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ? 2185 05b5cc6c7e4d2b4197774de6e
5b5cc6c7e4d2b4197774de6e- 1108false
- 2107false
- 3109true
- 4110false
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Answer : 3. "109"
Explanation :
Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109
Q: If a+b=5 and 3a+2b=20,then (3a+b)will be : 2182 05b5cc783e4d2b419777501fb
5b5cc783e4d2b419777501fb- 120false
- 215false
- 325true
- 430false
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Answer : 3. "25"
Explanation :
Answer: C) 25 Explanation: a+b=5 ...(1) and 3a+2b=20 ...(2) Multiplying (1) by 2 and subtracting from (2), we get : a=10. Putting a=10 in (1), we get : b=-5 Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.
Q: There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ? 2182 05b5cc705e4d2b4197774f1ee
5b5cc705e4d2b4197774f1ee- 11/10false
- 21/9false
- 31false
- 40true
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Answer : 4. "0"
Explanation :
Answer: D) 0 Explanation: As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address P(E) = favorable outcomes /total outcomesHere favorable outcomes are '0'.So probability is '0'.

