Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ? 2073 05b5cc6e2e4d2b4197774ec57
5b5cc6e2e4d2b4197774ec57- 12 hrsfalse
- 220 mintrue
- 340 minfalse
- 430 minfalse
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "20 min"
व्याख्या :
Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.
प्र: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 2068 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 1. "277"
व्याख्या :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.
प्र: A number divided by 296 leaves the remainder 75. If the same number is divided by 37, what will be the remainder ? 2067 05b5cc77ae4d2b41977750147
5b5cc77ae4d2b41977750147- 10false
- 21true
- 311false
- 48false
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- Workspace
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उत्तर : 2. "1"
व्याख्या :
Answer: B) 1 Explanation: Let x be the number. Given: x = 296n + 75 [where n is quotient] --> (378n) +( 372 + 1) -->37(8n + 2) + 1 Hence, when x divided by 37, 1 is the remainder.
प्र: Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ? 2066 05b5cc75ce4d2b4197774fc43
5b5cc75ce4d2b4197774fc43- 192.8%true
- 284.23%false
- 387.14%false
- 494.1%false
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उत्तर : 1. "92.8%"
व्याख्या :
Answer: A) 92.8% Explanation: Here, x = 40 and y = 30;Therefore second number= [[100+y100+x] x 100 ]% of first number= [[100+y100+x] x 100 ]% of first numberSecond number = 92.8% of the first number.
प्र: If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained. If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun ? 2065 05b5cc71be4d2b4197774f53a
5b5cc71be4d2b4197774f53a- 172 yearsfalse
- 254 yearsfalse
- 360 yearstrue
- 447 yearsfalse
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उत्तर : 3. "60 years"
व्याख्या :
Answer: C) 60 years Explanation: Let the Present age of arun is xGokul's age = 5-2 = 3x-6/18 = 3x-6 = 54x = 60Arun's present age = 60 years
प्र: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ? 2062 05b5cc6dce4d2b4197774e997
5b5cc6dce4d2b4197774e997- 15 kmphfalse
- 27 kmphfalse
- 33 kmphfalse
- 44 kmphtrue
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- Workspace
- SingleChoice
उत्तर : 4. "4 kmph"
व्याख्या :
Answer: D) 4 kmph Explanation: Speed of Man = 4.5 kmphSpeed of stream = 1.5 kmphSpeed in DownStream = 6 kmphSpeed in UpStream = 3 kmphAverage Speed = (2 x 6 x 3)/9 = 4 kmph.
प्र: Find the odd one out of the series ? 35, 48, 54, 63, 81, 105 2058 05b5cc6dae4d2b4197774e8c3
5b5cc6dae4d2b4197774e8c3- 163false
- 248false
- 335true
- 481false
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उत्तर : 3. "35"
व्याख्या :
Answer: C) 35 Explanation: 48, 54, 63, 81 and 105 are divisible by 3 but not 35.
प्र: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ? 2058 05b5cc6e1e4d2b4197774ebde
5b5cc6e1e4d2b4197774ebde- 1215true
- 2268false
- 3254false
- 4216false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 1. "215"
व्याख्या :
Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 216 - 1 = 215.