Quantitative Aptitude Practice Question and Answer
8Q: A sum of Rs. 731 is divided among A,B and C, such that 'A' receives 255 more than 'B' and 'B' receives 25% less than 'C'. What is 'C' s share in the amount? 2324 05b5cc7c8e4d2b41977750e2c
5b5cc7c8e4d2b41977750e2c- 1Rs.172false
- 2Rs.200false
- 3Rs.262false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: If a+b=5 and 3a+2b=20,then (3a+b)will be : 2323 05b5cc783e4d2b419777501fb
5b5cc783e4d2b419777501fb- 120false
- 215false
- 325true
- 430false
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Answer : 3. "25"
Explanation :
Answer: C) 25 Explanation: a+b=5 ...(1) and 3a+2b=20 ...(2) Multiplying (1) by 2 and subtracting from (2), we get : a=10. Putting a=10 in (1), we get : b=-5 Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.
Q: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys? 2323 05b5cc6b9e4d2b4197774d72a
5b5cc6b9e4d2b4197774d72a- 14 daystrue
- 26 daysfalse
- 37 daysfalse
- 45 daysfalse
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Answer : 1. "4 days"
Explanation :
Answer: A) 4 days Explanation: Given that 6 men and 8 boys can do a piece of work in 10 days 26 men and 48 boys can do the same in 2 days As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B => M = 2B => B = M/2 ……(1) Now Put (1) in 15M + 20B => 15M + 10M = 25M Now, 6M + 8B in 10 days => (6M + 4M) 10 = 100M Then D(25M) = 100M => D = 4 days.
Q: At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other? A. 5111 B. 15415 C. 16411 D. 4415 2320 05b5cc77ae4d2b41977750133
5b5cc77ae4d2b41977750133- 1Option Afalse
- 2Option Bfalse
- 3Option Ctrue
- 4Option Dfalse
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Answer : 3. "Option C"
Explanation :
Answer: C) Option C Explanation: At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand. To be coincident, it must gain 15 min. spaces. 55 min. are gained in 60 min. Then 15 min spaces are gained in = 6055×15 min. Therefore, The hands are coincident at 16411 min. past 3 o'clock.
Q: Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ? 2320 05b5cc6c7e4d2b4197774de6e
5b5cc6c7e4d2b4197774de6e- 1108false
- 2107false
- 3109true
- 4110false
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Answer : 3. "109"
Explanation :
Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109
Q: A fair six-sided die is rolled twice. What is the probability of getting 4 on the first roll and not getting 6 on the second roll ? 2319 05b5cc6d7e4d2b4197774e6c1
5b5cc6d7e4d2b4197774e6c1- 11/36false
- 25/36true
- 31/12false
- 41/9false
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Answer : 2. "5/36"
Explanation :
Answer: B) 5/36 Explanation: The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied. P(getting first 4) = 1/6 P(no second 6) = 5/6 Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36
Q: When the price of whear was increased by 32%, a family reduced its consumption in such a way that the expenditure on wheat was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption of family? 2318 05b5cc61ee4d2b4197774b758
5b5cc61ee4d2b4197774b758- 127 kgsfalse
- 225 kgstrue
- 324 kgsfalse
- 421 kgsfalse
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Answer : 2. "25 kgs"
Explanation :
Answer: B) 25 kgs Explanation: Initial wheat per kg cost be Rs. 100 Then, monthly expenditure of the family = 30 x 100 = 3000 After increase in cost, Let P be new monthly consumption of family. P x 132 = 110/100 x 3000 => P = 25 kg.
Q: A letter is takenout at random from 'ASSISTANT' and another is taken out from 'STATISTICS'. The probability that they are the same letter is : 2318 05b5cc7d0e4d2b41977751213
5b5cc7d0e4d2b41977751213- 135/96false
- 219/90true
- 319/96false
- 4None of thesefalse
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Answer : 2. "19/90"
Explanation :
Answer: B) 19/90 Explanation: ASSISTANT→AAINSSSTT STATISTICS→ACIISSSTTT Here N and C are not common and same letters can be A, I, S, T. Therefore Probability of choosing A = 2C19C1×1C110C1 = 1/45 Probability of choosing I = 19C1×2C110C1 = 1/45 Probability of choosing S = 3C19C1×3C110C1 = 1/10 Probability of choosing T = 2C19C1×3C110C1 = 1/15 Hence, Required probability = 145+145+110+115= 1990