Answer: A) 5 kmph Explanation: Speed of the boat downstream  s=a/t= 60/3 = 20 kmph Speed of the boat upstream s= d/t = 30/3= 10 kmph   Therefore,  The speed of the stream = speed of downstream - speed of upstream2=5 kmph

Answer: B) 3/2 Explanation:  = log 33 + log 23+ log 103log10×3×22        =log33 12+log 23+log 10312log(10×3×22)                 =12log 33+3 log 2+12 log103log10+log3+log22                 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32

Answer: C) 90 Explanation: The given number series follows a pattern that, 56 56 + 8 = 64 64 - 16 = 48 48 + 32 = 80 (Not equal to 90) 80 - 64 = 16 16 + 128 = 144    Hence, the odd number in the given number series is 90.

Answer: B) 12.5% Explanation: Let p% of a day is 3 hrs. We know that a day has 24 hrs. => p x 24/100 = 3 => p = 300/24 => p = 12.5%   Hence, 3 hrs is 12.5% of a day.

Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.

Answer: D) 10 months Explanation: 7x5: 5xk = 7:10k = 10 months

Answer: B) 5/36 Explanation: The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied. P(getting first 4) = 1/6 P(no second 6) = 5/6 Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36

Answer: D) 8:3 Explanation: Let the speed of the boat upstream be p kmph and that of downstream be q kmph   Time for upstream = 8 hrs 48 min = 845hrs   Time for downstream = 4 hrs   Distance in both the cases is same.   => p x  845= q x 4   => 44p/5 = 4q   => q = 11p/5    Now, the required ratio of Speed of boat : Speed of water current   = q+p2:q-p2   => (11p/5 + p)/2  : (11p/5 - p)/2   => 8 : 3