Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find value of log27 +log 8 +log1000log 120 2317 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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उत्तर : 2. "3/2"
व्याख्या :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
प्र: 70000 a year is how much an hour? 2307 05b5cc626e4d2b4197774b886
5b5cc626e4d2b4197774b886- 180false
- 28true
- 30.8false
- 40.08false
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उत्तर : 2. "8"
व्याख्या :
Answer: B) 8 Explanation: Given for year = 70000 => 365 days = 70000 => 365 x 24 hours = 70000 => 1 hour = ? 70000/365x24 = 7.990 = 8
प्र: 6 boys and 8 girls can do job in 10 days , 26 boys & 48 women do work in 2 days. Find time taken by 15 boys and 20 girls to do same work ? 2303 05b5cc74ae4d2b4197774fadb
5b5cc74ae4d2b4197774fadb- 12 daysfalse
- 23 daysfalse
- 34 daystrue
- 45 daysfalse
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उत्तर : 3. "4 days"
व्याख्या :
Answer: C) 4 days Explanation: One day work of 6 boys and 8 girls is given as 6b + 8g = 1/10 -------->(I) One day work of 26 boys and 48 women is given as 26b + 48w = 1/2 -------->(II) Divide both sides by 2 in (I) and then multiply both sides by 5 Now we get, 15b + 20g = 1/4. Therefore, 15 boys and 20 girls can do the same work in 4 days.
प्र: Find the odd one out of the following number series? 56, 64, 48, 90, 16, 144 2301 05b5cc658e4d2b4197774bddd
5b5cc658e4d2b4197774bddd- 148false
- 264false
- 390true
- 416false
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उत्तर : 3. "90"
व्याख्या :
Answer: C) 90 Explanation: The given number series follows a pattern that, 56 56 + 8 = 64 64 - 16 = 48 48 + 32 = 80 (Not equal to 90) 80 - 64 = 16 16 + 128 = 144 Hence, the odd number in the given number series is 90.
प्र: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 2301 05b5cc767e4d2b4197774fe45
5b5cc767e4d2b4197774fe45- 161%true
- 275%false
- 355%false
- 481%false
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उत्तर : 1. "61%"
व्याख्या :
Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220, S.P. = Rs.320. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195 Required percentage = 195320×100== 60.9 =~ 61%
प्र: Salaries of Karthik, Arun and Akhil were in the ratio 4 : 5 : 6 respectively. If their salaries were increased by 50 per cent, 60 per cent and 50 per cent respectively, what will be the new ratio of the salaries of Akhil, Arun and Karthik ? 2300 05b5cc761e4d2b4197774fd2a
5b5cc761e4d2b4197774fd2a- 16 : 8 : 9false
- 28 : 6 : 9false
- 39 : 8 : 6true
- 46 : 5 : 4false
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उत्तर : 3. "9 : 8 : 6"
व्याख्या :
Answer: C) 9 : 8 : 6 Explanation: Given the salaries are in the ratio of 4 : 5 : 6 Now the salaries are increased by 50%, 60% and 50% respectively The New ratio of salaries will be 4 x (150/100) : 5 x (160/100) : 6 x (150/100) = 6 : 8 : 9 The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6
प्र: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 2299 05b5cc701e4d2b4197774f170
5b5cc701e4d2b4197774f170- 1Rs. 1,24,000false
- 2Rs. 1,44,000true
- 3Rs. 1,32,000false
- 4Rs. 1,62,000false
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उत्तर : 2. "Rs. 1,44,000"
व्याख्या :
Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.
प्र: There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ? 2296 05b5cc705e4d2b4197774f1ee
5b5cc705e4d2b4197774f1ee- 11/10false
- 21/9false
- 31false
- 40true
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उत्तर : 4. "0"
व्याख्या :
Answer: D) 0 Explanation: As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address P(E) = favorable outcomes /total outcomesHere favorable outcomes are '0'.So probability is '0'.

