Quantitative Aptitude Practice Question and Answer
8Q: Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ? 2295 05b5cc70be4d2b4197774f2f6
5b5cc70be4d2b4197774f2f6- 160%false
- 240%true
- 350%false
- 430%false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "40%"
Explanation :
Answer: B) 40% Explanation: Lets say shyam sells at 100, ┬а Since Ram sells 25% cheaper than Shyam, ┬а Therefor Ram sells at less than 25% of100 or 75 rs. ┬а Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or ┬а 125% of x (say x price of bram )=75rs.or 100% of x =60rs.hence price of bram is 60rs. ┬а now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%. ┬а Hence Brams Good is 40% cheaper than that of Shyam's good.
Q: 3 is what percent of 5? 2289 05b5cc64ae4d2b4197774bc0c
5b5cc64ae4d2b4197774bc0c- 145%false
- 260%true
- 372%false
- 480%false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "60%"
Explanation :
Answer: B) 60% Explanation: Here it is asked that┬а3 is what percent of 5 Let┬а3 is K percent of 5. => K x 5/100 = 3 => K = 300/5 = 60 ┬а Hence,┬а3 is 60% of 5.
Q: Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ? 2285 05b5cc6cae4d2b4197774e068
5b5cc6cae4d2b4197774e068- 131 yearstrue
- 237 yearsfalse
- 346 yearsfalse
- 429 yearsfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "31 years"
Explanation :
Answer: A) 31 years Explanation: Let the present age of Pinky be x years ┬а Then the age of Mary is x - 12 years ┬а After 3 years, ┬а Ratio of┬а┬аMaryPinky┬а=┬аx┬а-┬а9x┬а+┬а3┬а=┬а58 ┬а 8x - 72 = 5x +15 ┬а => 3x = 87 ┬а => x = 29 ┬а => Age of Pinky = 29 years ┬а => Age of Mary = 29 - 12 = 17 years ┬а Present age of Sam = 29 + 17 = 46 ┬а Before 15 years Sam age = 46 - 15 = 31 years.
Q: A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ? 2284 05b5cc723e4d2b4197774f690
5b5cc723e4d2b4197774f690- 1Rs. 345.15true
- 2Rs. 245.1false
- 3Rs. 234.18false
- 4Rs. 456.65false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "Rs. 345.15"
Explanation :
Answer: A) Rs. 345.15 Explanation: area of the plot = 120m x 60m = 7200 sq.marea of plot excluding gravel = 117m x 57m = 6669 sq.marea of gravel = 7200 sq.m - 6669 sq.m = 531 sq.mcost of building it = 531 sq.m x 65 ps┬а= 34515 psIn Rs. = 34515/100 = Rs. 345.15.
Q: H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is : 2283 05b5cc6e7e4d2b4197774eda6
5b5cc6e7e4d2b4197774eda6- 1360false
- 2180true
- 390false
- 4120false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "180"
Explanation :
Answer: B) 180 Explanation: 4 x 27 x 3125 =┬а22┬а├Ч┬а33┬а├Ч┬а55┬а; ┬а 8 x 9 x 25 x 7 =┬а23┬а├Ч┬а32┬а├Ч┬а52┬а├Ч┬а7 ┬а 16 x 81 x 5 x 11 x 49 =┬а24┬а├Ч┬а34┬а├Ч┬а5┬а├Ч┬а11┬а├Ч┬а72 ┬а H.C.F = 22┬а├Ч┬а32┬а├Ч┬а5┬а= 180.
Q: Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ? 2283 05b5cc6f8e4d2b4197774f06d
5b5cc6f8e4d2b4197774f06d- 184 yrsfalse
- 296 yrsfalse
- 3116 yrsfalse
- 4108 yrstrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "108 yrs"
Explanation :
Answer: D) 108 yrs Explanation: Let the present ages of the mother and daughter be 2x and x years respectively. Then, (2x - 18) = 3(x - 18) => x = 36 Required sum = (2x + x) = 108 years.
Q: рдПрдХ рдирд╛рд╡ рдзрд╛рд░рд╛ рдХреЗ рдкреНрд░рддрд┐рдХреБрд▓ рдХреБрдЫ рджреВрд░реА рддрдп рдХрд░рдиреЗ рдореЗрдВ 8 рдШрдВрдЯреЗ рдФрд░ 48 рдорд┐рдирдЯ рдХрд╛ рд╕рдордп рд▓реЗрддреА рд╣реИ рдЬрдм рдХрд┐ рд╡рд╣ рд╡рд╣реА рд╕рдорд╛рди рджреВрд░реА рдзрд╛рд░рд╛ рдХреЗ рдЕрдиреБрдХреБрд▓ рддрдп рдХрд░рдиреЗ рдореЗрдВ 4 рдШрдВрдЯреЗ рдХрд╛ рд╕рдордп рд▓реЗрддреА рд╣реИ рддреЛ рдирд╛рд╡ рдХреА рдЪрд╛рд▓ рдФрд░ рд╕реНрдерд┐рд░ рдЬрд▓ рдореЗрдВ рдзрд╛рд░рд╛ рдХреА рдЪрд╛рд▓ рдХрд╛ рдЕрдиреБрдкрд╛рдд рдХреНрдпрд╛ рд╣реЛрдЧрд╛? 2282 05b5cc6bce4d2b4197774d88b
5b5cc6bce4d2b4197774d88b- 17:4false
- 211:4false
- 34:7false
- 48:3true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "8:3"
Explanation :
Answer: D) 8:3 Explanation: Let the speed of the boat upstream be p┬аkmph┬аand that of downstream be q┬аkmph ┬а Time for upstream = 8 hrs 48 min =┬а845hrs ┬а Time for downstream = 4 hrs ┬а Distance in both the cases is same. ┬а => p x┬а┬а845= q x 4 ┬а => 44p/5 = 4q ┬а => q = 11p/5 ┬а ┬аNow, the required ratio of Speed of boat : Speed of water current ┬а =┬аq+p2:q-p2 ┬а => (11p/5 + p)/2┬а : (11p/5 - p)/2 ┬а => 8 : 3
Q: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ? 2278 05b5cc6dce4d2b4197774e997
5b5cc6dce4d2b4197774e997- 15 kmphfalse
- 27 kmphfalse
- 33 kmphfalse
- 44 kmphtrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "4 kmph"
Explanation :
Answer: D) 4 kmph Explanation: Speed of Man = 4.5 kmphSpeed of stream = 1.5 kmphSpeed in DownStream = 6 kmphSpeed in UpStream = 3 kmphAverage Speed = (2 x 6 x 3)/9 = 4 kmph.

