Quantitative Aptitude Practice Question and Answer

Q: A fair six-sided die is rolled twice. What is the probability of getting 4 on the first roll and not getting 6 on the second roll ? 2391 0

  • 1
    1/36
    Correct
    Wrong
  • 2
    5/36
    Correct
    Wrong
  • 3
    1/12
    Correct
    Wrong
  • 4
    1/9
    Correct
    Wrong
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Answer : 2. "5/36"
Explanation :

Answer: B) 5/36 Explanation: The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied. P(getting first 4) = 1/6 P(no second 6) = 5/6 Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36

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Answer : 4. "8:3"
Explanation :

Answer: D) 8:3 Explanation: Let the speed of the boat upstream be p kmph and that of downstream be q kmph   Time for upstream = 8 hrs 48 min = 845hrs   Time for downstream = 4 hrs   Distance in both the cases is same.   => p x  845= q x 4   => 44p/5 = 4q   => q = 11p/5    Now, the required ratio of Speed of boat : Speed of water current   = q+p2:q-p2   => (11p/5 + p)/2  : (11p/5 - p)/2   => 8 : 3

Q: If a+b=5 and 3a+2b=20,then (3a+b)will be : 2389 0

  • 1
    20
    Correct
    Wrong
  • 2
    15
    Correct
    Wrong
  • 3
    25
    Correct
    Wrong
  • 4
    30
    Correct
    Wrong
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Answer : 3. "25"
Explanation :

Answer: C) 25 Explanation: a+b=5   ...(1)    and    3a+2b=20 ...(2)   Multiplying (1) by 2 and subtracting from (2), we get : a=10.   Putting a=10 in (1), we get : b=-5   Therefore,   (3a+b) = 3 x 10+(-5)=30-5=25.

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Answer : 3. "109"
Explanation :

Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109

Q: Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train? 2380 0

  • 1
    105 mts
    Correct
    Wrong
  • 2
    115 mts
    Correct
    Wrong
  • 3
    120 mts
    Correct
    Wrong
  • 4
    140 mts
    Correct
    Wrong
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Answer : 4. "140 mts"
Explanation :

Answer: D) 140 mts Explanation: Speeds of two trains = 30 kmph and 58 kmph => Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s Given a man takes time to cross length of faster train = 18 sec   Now, required Length of faster train = speed x time = 70/9  x  18 = 140 mts.

Q: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most  ? 2379 0

  • 1
    215
    Correct
    Wrong
  • 2
    268
    Correct
    Wrong
  • 3
    254
    Correct
    Wrong
  • 4
    216
    Correct
    Wrong
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Answer : 1. "215"
Explanation :

Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt.   Maximum number of unsuccessful attempts = 216 - 1 = 215.

Q: How many numbers up to 101 and 300 are divisible by 11  ? 2379 0

  • 1
    18
    Correct
    Wrong
  • 2
    20
    Correct
    Wrong
  • 3
    19
    Correct
    Wrong
  • 4
    17
    Correct
    Wrong
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Answer : 1. "18"
Explanation :

Answer: A) 18 Explanation: (300 – 101)/11 = 199/11 = 18 1/1118 Numbers.

Q: H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is : 2378 0

  • 1
    360
    Correct
    Wrong
  • 2
    180
    Correct
    Wrong
  • 3
    90
    Correct
    Wrong
  • 4
    120
    Correct
    Wrong
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Answer : 2. "180"
Explanation :

Answer: B) 180 Explanation: 4 x 27 x 3125 = 22 × 33 × 55 ;   8 x 9 x 25 x 7 = 23 × 32 × 52 × 7   16 x 81 x 5 x 11 x 49 = 24 × 34 × 5 × 11 × 72   H.C.F = 22 × 32 × 5 = 180.

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