Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year ? 1903 05b5cc6e1e4d2b4197774ebf7
5b5cc6e1e4d2b4197774ebf7- 1Rs. 1100false
- 2Rs. 1200true
- 3Rs. 1000false
- 4Rs. 1840false
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उत्तर : 2. "Rs. 1200"
व्याख्या :
Answer: B) Rs. 1200 Explanation: P --- 10 ----- 600 P --- 5 ----- 300 3P --- 5 ----- 900 __________ 1200
प्र: The ratio of investments of two partners A and B is 7:5 and the ratio of their profits is 7:10. If A invested the money for 5 months, find for how much time did B invest the money ? 1901 05b5cc6dfe4d2b4197774eaf3
5b5cc6dfe4d2b4197774eaf3- 111 monthsfalse
- 29 monthsfalse
- 37 monthsfalse
- 410 monthstrue
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उत्तर : 4. "10 months"
व्याख्या :
Answer: D) 10 months Explanation: 7x5: 5xk = 7:10k = 10 months
प्र: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 1900 05b5cc73ae4d2b4197774f902
5b5cc73ae4d2b4197774f902- 114.69 cmfalse
- 229.39 cmtrue
- 318.65 cmfalse
- 422.21 cmfalse
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उत्तर : 2. "29.39 cm"
व्याख्या :
Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms. As speed is same, area of cross sections should be same. Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 i.e πR2 = 6πR12 Here R = R and R1 = 12/2 = 6 ⇒R2 = 6×6×6 R = 14.696 => D = X = 14.696 * 2 = 29.3938 cm.
प्र: A certain job was assigned to a group of women to do it in 20 days. But 12 women did not turn up for the job and the remaining did the job in 32 days. The original number of women in the group was? 1900 05b5cc6bae4d2b4197774d794
5b5cc6bae4d2b4197774d794- 136false
- 232true
- 322false
- 428false
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उत्तर : 2. "32"
व्याख्या :
Answer: B) 32 Explanation: Let the total women in the group be 'W' Then according to the given data, W x 20 = (W-12) x 32 => W = 32 Therefore, the total number of women in the group = 32
प्र: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ? 1897 05b5cc74fe4d2b4197774fafe
5b5cc74fe4d2b4197774fafe- 14false
- 21false
- 35true
- 43false
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उत्तर : 3. "5"
व्याख्या :
Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1) But (3x + 2)(2x - 5) = 6x2-11x-10........(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.
प्र: A number divided by 296 leaves the remainder 75. If the same number is divided by 37, what will be the remainder ? 1897 05b5cc77ae4d2b41977750147
5b5cc77ae4d2b41977750147- 10false
- 21true
- 311false
- 48false
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उत्तर : 2. "1"
व्याख्या :
Answer: B) 1 Explanation: Let x be the number. Given: x = 296n + 75 [where n is quotient] --> (378n) +( 372 + 1) -->37(8n + 2) + 1 Hence, when x divided by 37, 1 is the remainder.
प्र: 1397 x 1397 = ? Here what replaces '?' 1895 05b5cc6bbe4d2b4197774d853
5b5cc6bbe4d2b4197774d853- 11951609true
- 21821504false
- 32031489false
- 41847879false
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उत्तर : 1. "1951609"
व्याख्या :
Answer: A) 1951609 Explanation: 1397 x 1397
प्र: One girl can eat 112 chocolates in half a minute, and her boy friend can eat half as many in twice the length of time. How many chocolates can both boy and girl eat in 12 seconds ? 1895 05b5cc745e4d2b4197774fa27
5b5cc745e4d2b4197774fa27- 144false
- 232false
- 356true
- 449false
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उत्तर : 3. "56"
व्याख्या :
Answer: C) 56 Explanation: Girl eats 112 chocolates in 30 sec so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates. Her boy friend can eat one-half of 112 in twice of 30 sec so he can eat 56 in 60 sec Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates. Hence, together they can eat = 44.8 + 11.2 =56 chocolates in 12 seconds.

