Quantitative Aptitude Practice Question and Answer

Q: The Value of  logtan10+logtan20+⋯⋯+logtan890 is 2061 1

  • 1
    -1
    Correct
    Wrong
  • 2
    0
    Correct
    Wrong
  • 3
    1/2
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 2. "0"
Explanation :

Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450     = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1     ∵ tan(90-θ)=cotθ and tan 450=1     = log 1 + log 1 +.....+log 1    = 0.

Q: Sixty men can stitch 150 shirts in 30 days working 8 hours a day. In how many days can 35 men stitch 200 shirts working 6 hours a day ? 2060 0

  • 1
    87.5
    Correct
    Wrong
  • 2
    89
    Correct
    Wrong
  • 3
    91.5
    Correct
    Wrong
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    93.5
    Correct
    Wrong
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Answer : 3. "91.5"
Explanation :

Answer: C) 91.5 Explanation: We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)(60 x 30 x 8)/ 150 = (35 x D2 x 6) / 200 D2 = (60 x 30 x 8 x 200) / (150 x 35 x 6) => D2 = 91.42 days =~ 91.5 days.

Q: Salaries of Karthik, Arun and Akhil were in the ratio 4 : 5 : 6 respectively. If their salaries were increased by 50 per cent, 60 per cent and 50 per cent respectively, what will be the new ratio of the salaries of Akhil, Arun and Karthik ? 2060 0

  • 1
    6 : 8 : 9
    Correct
    Wrong
  • 2
    8 : 6 : 9
    Correct
    Wrong
  • 3
    9 : 8 : 6
    Correct
    Wrong
  • 4
    6 : 5 : 4
    Correct
    Wrong
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Answer : 3. "9 : 8 : 6"
Explanation :

Answer: C) 9 : 8 : 6 Explanation: Given the salaries are in the ratio of 4 : 5 : 6   Now the salaries are increased by 50%, 60% and 50% respectively   The New ratio of salaries will be   4 x (150/100) : 5 x (160/100) : 6 x (150/100)   = 6 : 8 : 9   The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6

Q: 70000 a year is how much an hour? 2058 0

  • 1
    80
    Correct
    Wrong
  • 2
    8
    Correct
    Wrong
  • 3
    0.8
    Correct
    Wrong
  • 4
    0.08
    Correct
    Wrong
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Answer : 2. "8"
Explanation :

Answer: B) 8 Explanation: Given for year = 70000 => 365 days = 70000 => 365 x 24 hours = 70000 =>   1 hour = ? 70000/365x24 = 7.990 = 8

Q: What percent of a day is 3 hours? 2057 0

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    14.9%
    Correct
    Wrong
  • 2
    12.5%
    Correct
    Wrong
  • 3
    15.6%%
    Correct
    Wrong
  • 4
    11.4%
    Correct
    Wrong
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Answer : 2. "12.5%"
Explanation :

Answer: B) 12.5% Explanation: Let p% of a day is 3 hrs. We know that a day has 24 hrs. => p x 24/100 = 3 => p = 300/24 => p = 12.5%   Hence, 3 hrs is 12.5% of a day.

Q: 3 is what percent of 5? 2056 0

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    45%
    Correct
    Wrong
  • 2
    60%
    Correct
    Wrong
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    72%
    Correct
    Wrong
  • 4
    80%
    Correct
    Wrong
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Answer : 2. "60%"
Explanation :

Answer: B) 60% Explanation: Here it is asked that 3 is what percent of 5 Let 3 is K percent of 5. => K x 5/100 = 3 => K = 300/5 = 60   Hence, 3 is 60% of 5.

Q: Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ? 2056 0

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    18 years
    Correct
    Wrong
  • 2
    21 years
    Correct
    Wrong
  • 3
    23 years
    Correct
    Wrong
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    17 years
    Correct
    Wrong
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Answer : 1. "18 years"
Explanation :

Answer: A) 18 years Explanation: At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x12 years after:Age of Sudeer = 4x+12Age of Swetha = 3x+12Now the equation is 3x+12=5/6(4x+12)Solving equation we get x=6Hence Swetha got married at the age of 18.

Q: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 2056 0

  • 1
    49450
    Correct
    Wrong
  • 2
    50540
    Correct
    Wrong
  • 3
    46587
    Correct
    Wrong
  • 4
    52487
    Correct
    Wrong
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Answer : 2. "50540"
Explanation :

Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed),   Total : C121×C320+C321×C120= 50540 ways.

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