Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 2154 05b5cc73ae4d2b4197774f902
5b5cc73ae4d2b4197774f902- 114.69 cmfalse
- 229.39 cmtrue
- 318.65 cmfalse
- 422.21 cmfalse
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उत्तर : 2. "29.39 cm"
व्याख्या :
Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms. As speed is same, area of cross sections should be same. Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 i.e πR2 = 6πR12 Here R = R and R1 = 12/2 = 6 ⇒R2 = 6×6×6 R = 14.696 => D = X = 14.696 * 2 = 29.3938 cm.
प्र: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 2154 05b5cc774e4d2b41977750011
5b5cc774e4d2b41977750011- 1205false
- 2194false
- 3209true
- 4159false
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उत्तर : 3. "209"
व्याख्या :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.
प्र: The Value of logtan10+logtan20+⋯⋯+logtan890 is 2152 15b5cc7d0e4d2b41977751204
5b5cc7d0e4d2b41977751204- 1-1false
- 20true
- 31/2false
- 41false
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उत्तर : 2. "0"
व्याख्या :
Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450 = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1 ∵ tan(90-θ)=cotθ and tan 450=1 = log 1 + log 1 +.....+log 1 = 0.
प्र: 400 मीटर लम्बी रेलगाड़ी 60 किमी प्रति घण्टा की चाल से जा रही है। उसके सामने से रेलगाड़ी की विपरित दिशा में एक व्यक्ति 12 किमी प्रति घण्टा की चाल से भागा जा रहा है। रेलगाड़ी इस व्यक्ति को कितनी देर में पार कर लेगी? 2150 15d15fbab44a3a75f13296b82
5d15fbab44a3a75f13296b82- 150 सैंकण्डfalse
- 230 सैंकण्डfalse
- 320 सैंकण्डtrue
- 440 सैंकण्डfalse
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उत्तर : 3. "20 सैंकण्ड"
प्र: Find the Odd One Out? 3, 4, 14, 48, 576, 27648 2145 05b5cc6b0e4d2b4197774d2c6
5b5cc6b0e4d2b4197774d2c6- 14false
- 214true
- 348false
- 427648false
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उत्तर : 2. "14"
व्याख्या :
Answer: B) 14 Explanation: Given Number series is : 3 4 14 48 576 27648 It follows a pattern that, 3 4 4 x 3 = 12 but not 14 12 x 4 = 48 48 x 12 = 576 576 x 48 = 27648 Hence, the odd one in the given Number Series is 14.
प्र: Express 3/8 and 1/10 as a Decimals? 2145 05b5cc6b3e4d2b4197774d437
5b5cc6b3e4d2b4197774d437- 11.375 & 1false
- 20.375 & 1false
- 313.75 & 1.1false
- 40.375 & 0.1true
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उत्तर : 4. "0.375 & 0.1"
व्याख्या :
Answer: D) 0.375 & 0.1 Explanation: 3/8 as a Decimal : In this we should convert the denominator into 10, 100, 1000, 10000, 100000,... to make it simple. Now to make 8 into 1000, we multiply numerator and denominator with 125 => 3 x 1258 x 125 = 3751000 = 0.375 1/10 as a Decimal : 1 divided into 10 parts of each 0.1. Therefore, 3/8 = 0.375 and 1/10 = 0.1 in decimals.
प्र: If y/(x - z) = (y + x)/z = x/y then find z : y : x ? 2144 05b5cc761e4d2b4197774fd4e
5b5cc761e4d2b4197774fd4e- 11:2:3false
- 23:2:4true
- 34:3:2false
- 42:3:4false
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उत्तर : 2. "3:2:4"
व्याख्या :
Answer: B) 3:2:4 Explanation: Given, y/(x - z) = (y + x)/z = x/yyz = xy + x2 - yz - xz ....(1)Also xy = yx-z ⇒x2 -xz = y2 ....(2)Using (1) and (2), we get yz = xy - yz + y22yz = xy + y22z = x + y Only option (B) satisfies the equation.
प्र: Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train? 2140 05b5cc67ee4d2b4197774c23f
5b5cc67ee4d2b4197774c23f- 1105 mtsfalse
- 2115 mtsfalse
- 3120 mtsfalse
- 4140 mtstrue
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उत्तर : 4. "140 mts"
व्याख्या :
Answer: D) 140 mts Explanation: Speeds of two trains = 30 kmph and 58 kmph => Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s Given a man takes time to cross length of faster train = 18 sec Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.

