Quantitative Aptitude Practice Question and Answer
8Q: 1, 2, 8, 33, ? Find the next number in the given series? 2309 05b5cc6bae4d2b4197774d7e4
5b5cc6bae4d2b4197774d7e4- 1148true
- 2145false
- 3143false
- 4141false
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Answer : 1. "148"
Explanation :
Answer: A) 148 Explanation: 1 x 1 + 1 x 1 = (1 + 1) = 2 2 x 2 + 2 x 2 = (4 + 4) = 8 8 x 3 + 3 x 3 = (24 + 9) = 33 33 x 4 + 4 x 4 = (132 + 16) = 148 148 x 5 + 5 x 5 = (740 + 25) = 765.
Q: A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey? 2307 05b5cc6ade4d2b4197774d12f
5b5cc6ade4d2b4197774d12f- 132 kmphfalse
- 220 kmphfalse
- 318 kmphfalse
- 424 kmphtrue
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Answer : 4. "24 kmph"
Explanation :
Answer: D) 24 kmph Explanation: Let the total distance of the journey of a man = d kms Now, the average speed of the entire journey = dd120 + d120 + d40 = 24 kmph.
Q: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 2307 05b5cc73ae4d2b4197774f902
5b5cc73ae4d2b4197774f902- 114.69 cmfalse
- 229.39 cmtrue
- 318.65 cmfalse
- 422.21 cmfalse
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Answer : 2. "29.39 cm"
Explanation :
Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms. As speed is same, area of cross sections should be same. Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 i.e πR2 = 6πR12 Here R = R and R1 = 12/2 = 6 ⇒R2 = 6×6×6 R = 14.696 => D = X = 14.696 * 2 = 29.3938 cm.
Q: A class has 8 football players. A 5-member team and a captain will be selected out of these 8 players. How many different selections can be made ? 2304 05b5cc6d0e4d2b4197774e38a
5b5cc6d0e4d2b4197774e38a- 1210false
- 2168true
- 31260false
- 410!/6!false
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Answer : 2. "168"
Explanation :
Answer: B) 168 Explanation: we can select the 5 member team out of the 8 in 8C5 ways = 56 ways. The captain can be selected from amongst the remaining 3 players in 3 ways. Therefore, total ways the selection of 5 players and a captain can be made = 56x3 = 168 ways. (or) Alternatively, A team of 6 members has to be selected from the 8 players. This can be done in 8C6 or 28 ways. Now, the captain can be selected from these 6 players in 6 ways. Therefore, total ways the selection can be made is 28x6 = 168 ways.
Q: A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ? 2302 05b5cc761e4d2b4197774fd0c
5b5cc761e4d2b4197774fd0c- 112 p.m. on Wednesdayfalse
- 22 p.m. on Thursdaytrue
- 33 p.m. on Thursdayfalse
- 42 p.m. on Wednesdayfalse
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Answer : 2. "2 p.m. on Thursday"
Explanation :
Answer: B) 2 p.m. on Thursday Explanation: Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.= 170 hours.The watch gains = (2 + 4 x 4/5) min= 34/5 min. in 170 hrs.Now, 34/5 min are gained in 170 hrs.Then, 2 min are gained in (170 x 5/34 x 2) hrs.Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.
Q: Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ? 2297 05b5cc745e4d2b4197774fa54
5b5cc745e4d2b4197774fa54- 164false
- 269false
- 371true
- 458false
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Answer : 3. "71"
Explanation :
Answer: C) 71 Explanation: To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51). Therefore, HCF of 923, 1207 and 1349 is 71.
Q: P, Q, and R can do a job in 12 days together. If their efficiency of working be in the ratio 3 : 8 : 5, Find in what time Q can complete the same work alone? 2293 05b5cc698e4d2b4197774c61d
5b5cc698e4d2b4197774c61d- 136 daystrue
- 230 daysfalse
- 324 daysfalse
- 422 daysfalse
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Answer : 1. "36 days"
Explanation :
Answer: A) 36 days Explanation: Given the ratio of efficiencies of P, Q & R are 3 : 8 : 5 Let the efficiencies of P, Q & R be 3x, 8x and 5x respectively They can do work for 12 days. => Total work = 12 x 16x = 192x Now, the required time taken by Q to complete the job alone = 162x8x = 24 days.
Q: The ratio of K’s and M’s ages is 4: 5. If the difference between the present age of M and the age of K, 5 years hence is 3 years, then what is the difference and total of present ages of K and M? 2293 05b5cc639e4d2b4197774ba7d
5b5cc639e4d2b4197774ba7d- 18, 72 yrstrue
- 216, 65 yrsfalse
- 312, 84 yrsfalse
- 410, 60 yrsfalse
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Answer : 1. "8, 72 yrs"
Explanation :
Answer: A) 8, 72 yrs Explanation: Let the present ages be K,M Given K/M = 4/5 5K - 4M = 0 ......(1) Also given that, M - (K + 5) = 3 M - K = 8 .........(2) Then, by solving (1) & (2) M = 40 yrs and K = 32 yrs Hence, Total of ages = 40 + 32 = 72 yrs Difference of ages = 40 - 32 = 8 yrs.

