Quantitative Aptitude Practice Question and Answer
8Q: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1932 05b5cc723e4d2b4197774f67c
5b5cc723e4d2b4197774f67c- 160%false
- 250%false
- 370%true
- 445%false
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Answer : 3. "70%"
Explanation :
Answer: C) 70% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295 Required percentage = (295/420) * 100 = 70%(approx)
Q: The ratio of present ages of Hema and Chinnu is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ? 1930 05b5cc736e4d2b4197774f86f
5b5cc736e4d2b4197774f86f- 13 : 7false
- 27 : 9false
- 34 : 5true
- 41 : 3false
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Answer : 3. "4 : 5"
Explanation :
Answer: C) 4 : 5 Explanation: Let their present ages be 13x and 17x.Then, 13x-4/17x-4 = 11/15. Solving this, we get x = 2.Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.
Q: Find out the wrong term in the following number series. 4, 16, 37, 58, 81. 1930 05b5cc6cae4d2b4197774e09a
5b5cc6cae4d2b4197774e09a- 116false
- 237false
- 381true
- 44false
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Answer : 3. "81"
Explanation :
Answer: C) 81 Explanation: The series follows the following pattern. ┬а 4 ┬а 16 =┬а42 ┬а 37 =┬а12+62 ┬а 58 =┬а32+72 ┬а 81┬атЙа52+82. ┬а Here every number is based on the digits of previous number. Hence, 81 is the wrong number in the given series.
Q: Find the Odd one out of the following Numbers? 1930 05b5cc6a4e4d2b4197774cc4b
5b5cc6a4e4d2b4197774cc4b- 13false
- 219false
- 367false
- 4133true
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Answer : 4. "133"
Explanation :
Answer: D) 133 Explanation: Here among the given numbers, 3, 19, 67 are prime numbers. And 133 is not a prime number. ┬а Hence, the odd number of the given numbers is 133.
Q: The sum of the digits of a two-digits number is 10,while when the digits are reversed, the number decreases by 54. Find the changed number ? 1927 05b5cc701e4d2b4197774f1b2
5b5cc701e4d2b4197774f1b2- 128true
- 219false
- 337false
- 446false
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Answer : 1. "28"
Explanation :
Answer: A) 28 Explanation: Let the original number is 82 i.e 8 + 2 = 10 and when the digits are reversed i.e 28The difference is 82 - 28 = 54 i.e, the number is decreased by 54.
Q: The average age of 7 boys is increased by 1 year when one of tem whose age is replaced by a girl. What is the age of the girl ? 1927 05b5cc6cae4d2b4197774e086
5b5cc6cae4d2b4197774e086- 133 yrsfalse
- 227 yrsfalse
- 321 yrsfalse
- 429 yrstrue
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Answer : 4. "29 yrs"
Explanation :
Answer: D) 29 yrs Explanation: Let the avg age of 7 boys be 'p' yearsLet the age of the girl be 'q' yearsFrom given data,The age of 7 boys = 7p yearsNow the new average = (p + 1) when 22 yrs is replaced by qNow the age of all 7 will become = 7(p + 1) yrsHence, 7p - 22 + q = 7(p + 1) yrs7p - 22 + q = 7p + 7q = 22 + 7 = 29 Therefore, the age of girl = q = 29 years.
Q: Pavan and Sravan are two persons. If Pavan works with his actual efficiency and Sravan twice of his actual efficiency then it takes 25 days to complete the work. But If Pavan works twice of his actual efficiency and Sravan with his normal efficiency then the work is completed in 20 days. How many days would it take if Sravan alone works with his actual efficiency (in Days)? 1925 05b5cc6c7e4d2b4197774ded2
5b5cc6c7e4d2b4197774ded2- 150false
- 2100true
- 370false
- 435false
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Answer : 2. "100"
Explanation :
Answer: B) 100 Explanation: Let the Efficiency of pavan be E(P) Let the Efficiency of sravan be E(S) Here Work W = LCM(25,20) = 100 Now, E(P+2S) = 100/25 = 4 ....(1) E(2P+S) = 100/20 = 5 ....(2) Hence, from (1) & (2) we get E(S) = 1 => Number of days Savan alone work to complete the work ┬а= 100/1 = 100 days.
Q: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red. 1923 05b5cc7d0e4d2b4197775121d
5b5cc7d0e4d2b4197775121d- 123/42false
- 219/42true
- 37/32false
- 416/39false
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Answer : 2. "19/42"
Explanation :
Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways ┬а(i) Selecting bag I and then drawing a red ball from it. ┬а (ii) Selecting bag II and then drawing a red ball from it. ┬а Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore┬а P(E1) = 1/2 ┬аand ┬аP(E2) = 1/2 Now,┬аPAE1┬а= Probability of drawing a red ball when the first bag has been selected = 4/7 ┬а┬аPAE2┬а = Probability of drawing a red ball when the second bag has been selected = 2/6 ┬аUsing the law of total probability, we have┬а ┬аP(red ball) = P(A) =┬аPE1├ЧPAE1+PE2├ЧPAE2┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а ┬а =┬а12├Ч47+12├Ч26=1942