Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the Odd one out of the following Numbers? 2102 05b5cc6a4e4d2b4197774cc4b
5b5cc6a4e4d2b4197774cc4b- 13false
- 219false
- 367false
- 4133true
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उत्तर : 4. "133"
व्याख्या :
Answer: D) 133 Explanation: Here among the given numbers, 3, 19, 67 are prime numbers. And 133 is not a prime number. Hence, the odd number of the given numbers is 133.
प्र: 45 men working 9 hours per day dig 40 m deep. How many extra men should be put to dig to a depth of 56 m working 7 hours per day ? 2100 05b5cc6dae4d2b4197774e8c8
5b5cc6dae4d2b4197774e8c8- 136true
- 261false
- 348false
- 454false
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उत्तर : 1. "36"
व्याख्या :
Answer: A) 36 Explanation: (45 x 9)/40 = (M x 7)/56 => M = 81 => 81 – 45 = 36
प्र: A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ? 2096 05b5cc761e4d2b4197774fd0c
5b5cc761e4d2b4197774fd0c- 112 p.m. on Wednesdayfalse
- 22 p.m. on Thursdaytrue
- 33 p.m. on Thursdayfalse
- 42 p.m. on Wednesdayfalse
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उत्तर : 2. "2 p.m. on Thursday"
व्याख्या :
Answer: B) 2 p.m. on Thursday Explanation: Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.= 170 hours.The watch gains = (2 + 4 x 4/5) min= 34/5 min. in 170 hrs.Now, 34/5 min are gained in 170 hrs.Then, 2 min are gained in (170 x 5/34 x 2) hrs.Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.
प्र: In following number series only one number is wrong. Find out that wrong or odd number in the series? 6, 78, 858, 7722, 54055, 270270 2093 05b5cc6bce4d2b4197774d8bb
5b5cc6bce4d2b4197774d8bb- 1270270false
- 254055true
- 37722false
- 4858false
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उत्तर : 2. "54055"
व्याख्या :
Answer: B) 54055 Explanation: Here the given series follows a pattern that, multiplying the number with odd numbers in decreasing order starting with 13. That is, 6 × 13 = 78 65 × 11 = 858 858 × 9 = 7722 7722 × 7 = 54054 54054 × 5 = 270270 Hence, the wrong number is 54055
प्र: A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey? 2093 05b5cc6ade4d2b4197774d12f
5b5cc6ade4d2b4197774d12f- 132 kmphfalse
- 220 kmphfalse
- 318 kmphfalse
- 424 kmphtrue
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उत्तर : 4. "24 kmph"
व्याख्या :
Answer: D) 24 kmph Explanation: Let the total distance of the journey of a man = d kms Now, the average speed of the entire journey = dd120 + d120 + d40 = 24 kmph.
प्र: Vishal and Raghu jointly started a business. Vishal invested three times as Raghu did and invested his money for double time as compared to Raghu. Raghu earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was ? 2092 05b5cc6dee4d2b4197774ea8f
5b5cc6dee4d2b4197774ea8f- 1Rs. 28,000true
- 2Rs. 18,000false
- 3Rs. 14,000false
- 4Rs. 8,000false
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उत्तर : 1. "Rs. 28,000"
व्याख्या :
Answer: A) Rs. 28,000 Explanation: Investments ratio is = 3:1Time period ratio is = 2:1 As they are proportional to gain ------Gain ratio of Vishal and raghu = 6:1 But given Raghu got Rs. 4000, =? 1 ----- 4000 7 ----- ? => Rs.28,000 The total gain = Rs.28,000
प्र: There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number? 2092 05b5cc6aee4d2b4197774d165
5b5cc6aee4d2b4197774d165- 129true
- 227false
- 331false
- 433false
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उत्तर : 1. "29"
व्याख्या :
Answer: A) 29 Explanation: Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4 According to the question, Difference between square of the average of first two odd number and the of the average last two odd numbers is 396 i.e, x+3 and x-3 ⇒x + 32 - x - 32 = 396⇒ x2 + 9 + 6x - x2 + 6x - 9 = 396⇒ 12x = 396⇒ x = 33 Hence, the smallest odd number is 33 - 4 = 29.
प्र: A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved? 2092 05b5cc7d0e4d2b4197775122c
5b5cc7d0e4d2b4197775122c- 11/4false
- 21/2false
- 33/4true
- 47/12false
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उत्तर : 3. "3/4"
व्याख्या :
Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4 PA=12, PB=23, PC= 34 ∴ P( none solves the problem) = P(not A) and (not B) and (not C) = PA∩B∩C = PAPBPC ∵ A, B, C are Independent = 12×23×34 = 14 Hence, P(the problem will be solved) = 1 - P(none solves the problem) = 1-14= 3/4

