Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 1764 0

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    1000 (r - p) + pq
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  • 2
    1000 p + qr
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  • 3
    1000 (r - q) + pr
    सही
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  • 4
    1000(p - q) + qr
    सही
    गलत
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उत्तर : 4. "1000(p - q) + qr"
व्याख्या :

Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or)  The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y   Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr

प्र: A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ? 1762 0

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    9 and 3 kmph
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  • 2
    6 and 7 kmph
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  • 3
    8 and 1 kmph
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  • 4
    7 and 2 kmph
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उत्तर : 3. "8 and 1 kmph"
व्याख्या :

Answer: C) 8 and 1 kmph Explanation: Downstream speed = 72km/8hrs  = 9 kmphupstream speed = 84km/12hrs = 7 kmphspeed of boat = avg of downstream and upstream speedsspeed of boat = (9+7)/2kmph = 8 kmph.current speed = half of the difference of downstream and upstream speedscurrend speed = (9-7)/2kmph = 1 kmph

प्र: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1758 0

  • 1
    21.4 and 42.8
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  • 2
    25.2 and 50.4
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  • 3
    31.4208 and 62.8416
    सही
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  • 4
    33.12 and 66.24
    सही
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उत्तर : 3. "31.4208 and 62.8416"
व्याख्या :

Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.

प्र: A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal ? 1757 0

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    72 kgs
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  • 2
    80 kgs
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  • 3
    76 kgs
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  • 4
    84 kgs
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उत्तर : 2. "80 kgs"
व्याख्या :

Answer: B) 80 kgs Explanation: Say total cost price of tea is x.Then total profit at a rate of 15% is = (15x/100)According to question,15x/100 = 60so x = 400C.p of the tea is Rs. 400.so total selling price will be = (400+60) = Rs.460so the quantity of the tea will be = (460/5.75) = 80kg.

प्र: Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ? 1756 0

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    11 & 17
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  • 2
    7 & 17
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  • 3
    9 & 21
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  • 4
    13 & 23
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उत्तर : 3. "9 & 21"
व्याख्या :

Answer: C) 9 & 21 Explanation: Let the two numbers be x and y Given x : y = 3 : 7 .....(1) Now, x+6 : y+6 = 5 : 9 .....(2) From (1), x = 3y/7 From (2), 5y - 9x = 24 => 5y - 9(3y/7) = 24 => y = 21 => From(1), x = 9 Hence, the two numbers be 9 and 21

प्र: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 1754 0

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    12 a.m.
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  • 2
    1 p.m.
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  • 3
    11 a.m.
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  • 4
    12 p.m.
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उत्तर : 4. "12 p.m."
व्याख्या :

Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

प्र: A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved? 1754 0

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    1/4
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  • 2
    1/2
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  • 3
    3/4
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  • 4
    7/12
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उत्तर : 3. "3/4"
व्याख्या :

Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now,  P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4  PA=12, PB=23, PC= 34 ∴ P( none  solves the problem) = P(not A) and (not B) and (not C)                     = PA∩B∩C                    = PAPBPC         ∵ A, B, C are Independent                                          =  12×23×34                     = 14   Hence, P(the problem will be solved) = 1 - P(none solves the problem)                  = 1-14= 3/4

प्र: Find out the wrong term in the following number series. 4, 16, 37, 58, 81. 1754 0

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    16
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  • 2
    37
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  • 3
    81
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  • 4
    4
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उत्तर : 3. "81"
व्याख्या :

Answer: C) 81 Explanation: The series follows the following pattern.   4   16 = 42   37 = 12+62   58 = 32+72   81 ≠52+82.   Here every number is based on the digits of previous number. Hence, 81 is the wrong number in the given series.

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