Quantitative Aptitude Practice Question and Answer
8Q: A Committee of 5 persons is to be formed from a group of 6 gentlemen and 4 ladies. In how many ways can this be done if the committee is to be included atleast one lady? 1993 05b5cc7d1e4d2b41977751286
5b5cc7d1e4d2b41977751286- 1123false
- 2113false
- 3246true
- 4945false
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Answer : 3. "246"
Explanation :
Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking. (i) 1 lady out of 4 and 4 gentlemen out of 6 (ii) 2 ladies out of 4 and 3 gentlemen out of 6 (iii) 3 ladies out of 4 and 2 gentlemen out of 6 (iv) 4 ladies out of 4 and 1 gentlemen out of 6 In case I the number of ways = C14×C46 = 4 x 15 = 60 In case II the number of ways = C24×C36 = 6 x 20 = 120 In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6 Hence, the required number of ways = 60 + 120 + 60 + 6 = 246
Q: A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ? 1991 05b5cc761e4d2b4197774fd0c
5b5cc761e4d2b4197774fd0c- 112 p.m. on Wednesdayfalse
- 22 p.m. on Thursdaytrue
- 33 p.m. on Thursdayfalse
- 42 p.m. on Wednesdayfalse
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Answer : 2. "2 p.m. on Thursday"
Explanation :
Answer: B) 2 p.m. on Thursday Explanation: Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.= 170 hours.The watch gains = (2 + 4 x 4/5) min= 34/5 min. in 170 hrs.Now, 34/5 min are gained in 170 hrs.Then, 2 min are gained in (170 x 5/34 x 2) hrs.Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.
Q: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1991 05b5cc723e4d2b4197774f67c
5b5cc723e4d2b4197774f67c- 160%false
- 250%false
- 370%true
- 445%false
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Answer : 3. "70%"
Explanation :
Answer: C) 70% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295 Required percentage = (295/420) * 100 = 70%(approx)
Q: K and L start a business jointly. K invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit L claims 2/7th share. How much money is contributed by L? 1987 05b5cc767e4d2b4197774fe22
5b5cc767e4d2b4197774fe22- 1Rs. 13,204false
- 2Rs. 14,521false
- 3Rs. 12,800true
- 4Rs. 15,000false
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Answer : 3. "Rs. 12,800"
Explanation :
Answer: C) Rs. 12,800 Explanation: Given share of L is 2/7 th of profit. Then, their profits are divided in to 5:2 ratio. Ratio of K and L is 16000×8x×4=52 x = Rs. 12,800.
Q: From a group of 7 boys and 6 girls, five persons are to be selected to form a team, so that at least 3 girls are there in the team. In how many ways can it be done? 1987 05b5cc675e4d2b4197774c115
5b5cc675e4d2b4197774c115- 1427false
- 2531true
- 3651false
- 4714false
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Answer : 2. "531"
Explanation :
Answer: B) 531 Explanation: Given in the question that, there are 7 boys and 6 girls. Team members = 5 Now, required number of ways in which a team of 5 having atleast 3 girls in the team = 6C3 x 7C2 + 6C4 x 7C1 + 6C5= 6x5x43x2x1 x 7x62x1 + 6x5x4x34x3x2x1 x 7 + 6x5x4x3x25x4x3x2x1= 420 + 105 + 6= 531.
Q: A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved? 1985 05b5cc7d0e4d2b4197775122c
5b5cc7d0e4d2b4197775122c- 11/4false
- 21/2false
- 33/4true
- 47/12false
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Answer : 3. "3/4"
Explanation :
Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4 PA=12, PB=23, PC= 34 ∴ P( none solves the problem) = P(not A) and (not B) and (not C) = PA∩B∩C = PAPBPC ∵ A, B, C are Independent = 12×23×34 = 14 Hence, P(the problem will be solved) = 1 - P(none solves the problem) = 1-14= 3/4
Q: A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey? 1984 05b5cc6ade4d2b4197774d12f
5b5cc6ade4d2b4197774d12f- 132 kmphfalse
- 220 kmphfalse
- 318 kmphfalse
- 424 kmphtrue
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Answer : 4. "24 kmph"
Explanation :
Answer: D) 24 kmph Explanation: Let the total distance of the journey of a man = d kms Now, the average speed of the entire journey = dd120 + d120 + d40 = 24 kmph.
Q: A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ? 1983 05b5cc71ee4d2b4197774f581
5b5cc71ee4d2b4197774f581- 19 and 3 kmphfalse
- 26 and 7 kmphfalse
- 38 and 1 kmphtrue
- 47 and 2 kmphfalse
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Answer : 3. "8 and 1 kmph"
Explanation :
Answer: C) 8 and 1 kmph Explanation: Downstream speed = 72km/8hrs = 9 kmphupstream speed = 84km/12hrs = 7 kmphspeed of boat = avg of downstream and upstream speedsspeed of boat = (9+7)/2kmph = 8 kmph.current speed = half of the difference of downstream and upstream speedscurrend speed = (9-7)/2kmph = 1 kmph

