Quantitative Aptitude Practice Question and Answer
8Q: The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ? 1981 05b5cc75ce4d2b4197774fc3e
5b5cc75ce4d2b4197774fc3e- 116%false
- 220%true
- 384%false
- 472%false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "20%"
Explanation :
Answer: B) 20% Explanation: Reduction in consumption= P100+P X 100%= 25100+25 X 100%= 20%
Q: 1, 2, 8, 33, ? Find the next number in the given series? 1981 05b5cc6bae4d2b4197774d7e4
5b5cc6bae4d2b4197774d7e4- 1148true
- 2145false
- 3143false
- 4141false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "148"
Explanation :
Answer: A) 148 Explanation: 1 x 1 + 1 x 1 = (1 + 1) = 2 2 x 2 + 2 x 2 = (4 + 4) = 8 8 x 3 + 3 x 3 = (24 + 9) = 33 33 x 4 + 4 x 4 = (132 + 16) = 148 148 x 5 + 5 x 5 = (740 + 25) = 765.
Q: At what time, between 3 o’clock and 4 o’clock, both the hour hand and minute hand coincide each other ? 1977 05b5cc6d8e4d2b4197774e74b
5b5cc6d8e4d2b4197774e74b- 13:16 7/11false
- 23:16 11/4false
- 33:30false
- 43:16 4/11true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "3:16 4/11"
Explanation :
Answer: D) 3:16 4/11 Explanation: Coincide means 00 angle. This can be calculated using the formulafor time A to B means [11m/2 - 30 (A)] Here m gives minutes after A the both hands coincides. Here A = 3, B = 4 0 =11m/2 –30 × 311m = 90 × 2 = 180m= 180/11 = 16 4/11 So time = 3 : 16 4/11
Q: How many days in 4 years? 1976 05b5cc6aee4d2b4197774d1a1
5b5cc6aee4d2b4197774d1a1- 11460true
- 21461false
- 31462false
- 41459false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "1460"
Explanation :
Answer: A) 1460 Explanation: Days in 4 years => Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years. 4 years => 365 + 365 + 365 + 366(Leap year) 4 years => 730 + 731 = 1461 Therefore, Number of Days in 4 Years = 1461 Days.
Q: If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ? 1974 05b5cc6fee4d2b4197774f161
5b5cc6fee4d2b4197774f161- 1Rs. 1033.33true
- 2Rs. 1024false
- 3Rs. 1148.14false
- 4Rs. 1245.32false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "Rs. 1033.33"
Explanation :
Answer: A) Rs. 1033.33 Explanation: Let P's capital = p, Q's capital = q and R's capital = r.Then 6p = 8q = 12r=> 3p = 4q = 6r=>q = 3p/4r = 3p/6 = p/2P : Q : R = p : 3p/4 : p/2= 4 : 3 : 2R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.
Q: Albert invested Rs. 8000 in a scheme for 2 years at compound interest rate 5% p.a. How much amount will Albert get on maturity of the fixed deposit ? 1972 05b5cc6e7e4d2b4197774ed9c
5b5cc6e7e4d2b4197774ed9c- 1Rs. 8840false
- 2Rs. 8800false
- 3Rs. 8810false
- 4Nonetrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "None"
Explanation :
Answer: D) None Explanation: Amount = 80001+51002 = 8000 x 21/20 x 21/20 = Rs. 8820
Q: The calendar for the year 2007 will be the same for the year ? 1971 05b5cc75ce4d2b4197774fc25
5b5cc75ce4d2b4197774fc25- 12014false
- 22019false
- 32021false
- 42018true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "2018"
Explanation :
Answer: D) 2018 Explanation: Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day. Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017Odd day : 1 2 1 1 1 2 1 1 1 2 1 Sum = 14 odd days => 0 odd days.Calendar for the year 2018 will be the same as for the year 2007.
Q: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 1969 05b5cc764e4d2b4197774fdad
5b5cc764e4d2b4197774fdad- 112 a.m.false
- 21 p.m.false
- 311 a.m.false
- 412 p.m.true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "12 p.m."
Explanation :
Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

