Quantitative Aptitude Practice Question and Answer

Q: The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ? 1981 0

  • 1
    16%
    Correct
    Wrong
  • 2
    20%
    Correct
    Wrong
  • 3
    84%
    Correct
    Wrong
  • 4
    72%
    Correct
    Wrong
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Answer : 2. "20%"
Explanation :

Answer: B) 20% Explanation: Reduction in consumption= P100+P X 100%= 25100+25 X 100%= 20%

Q: 1, 2, 8, 33, ? Find the next number in the given series? 1981 0

  • 1
    148
    Correct
    Wrong
  • 2
    145
    Correct
    Wrong
  • 3
    143
    Correct
    Wrong
  • 4
    141
    Correct
    Wrong
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Answer : 1. "148"
Explanation :

Answer: A) 148 Explanation: 1 x 1 + 1 x 1 = (1 + 1) = 2 2 x 2 + 2 x 2 = (4 + 4) = 8 8 x 3 + 3 x 3 = (24 + 9) = 33 33 x 4 + 4 x 4 = (132 + 16) = 148 148 x 5 + 5 x 5 = (740 + 25) = 765.

Q: At what time, between 3 o’clock and 4 o’clock, both the hour hand and minute hand coincide each other  ? 1977 0

  • 1
    3:16 7/11
    Correct
    Wrong
  • 2
    3:16 11/4
    Correct
    Wrong
  • 3
    3:30
    Correct
    Wrong
  • 4
    3:16 4/11
    Correct
    Wrong
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Answer : 4. "3:16 4/11"
Explanation :

Answer: D) 3:16 4/11 Explanation: Coincide means 00  angle. This can be calculated using the formulafor time A to B means  [11m/2 - 30 (A)] Here m gives minutes after A the both hands coincides. Here A = 3, B = 4 0 =11m/2 –30 × 311m = 90 × 2 = 180m= 180/11 = 16 4/11 So time = 3 : 16 4/11

Q: How many days in 4 years? 1976 0

  • 1
    1460
    Correct
    Wrong
  • 2
    1461
    Correct
    Wrong
  • 3
    1462
    Correct
    Wrong
  • 4
    1459
    Correct
    Wrong
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Answer : 1. "1460"
Explanation :

Answer: A) 1460 Explanation: Days in 4 years =>  Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years. 4 years => 365 + 365 + 365 + 366(Leap year) 4 years => 730 + 731 = 1461   Therefore, Number of Days in 4 Years = 1461 Days.

Q: If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ? 1974 0

  • 1
    Rs. 1033.33
    Correct
    Wrong
  • 2
    Rs. 1024
    Correct
    Wrong
  • 3
    Rs. 1148.14
    Correct
    Wrong
  • 4
    Rs. 1245.32
    Correct
    Wrong
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Answer : 1. "Rs. 1033.33"
Explanation :

Answer: A) Rs. 1033.33 Explanation: Let P's capital = p, Q's capital = q and R's capital = r.Then 6p = 8q = 12r=> 3p = 4q = 6r=>q = 3p/4r = 3p/6 = p/2P : Q : R = p : 3p/4 : p/2= 4 : 3 : 2R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.

Q: Albert invested Rs. 8000 in a scheme for 2 years at compound interest rate 5% p.a. How much amount will Albert get on maturity of the fixed deposit  ? 1972 0

  • 1
    Rs. 8840
    Correct
    Wrong
  • 2
    Rs. 8800
    Correct
    Wrong
  • 3
    Rs. 8810
    Correct
    Wrong
  • 4
    None
    Correct
    Wrong
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Answer : 4. "None"
Explanation :

Answer: D) None Explanation: Amount = 80001+51002   = 8000 x 21/20 x 21/20    = Rs. 8820

Q: The calendar for the year 2007 will be the same for the year ? 1971 0

  • 1
    2014
    Correct
    Wrong
  • 2
    2019
    Correct
    Wrong
  • 3
    2021
    Correct
    Wrong
  • 4
    2018
    Correct
    Wrong
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Answer : 4. "2018"
Explanation :

Answer: D) 2018 Explanation: Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day. Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017Odd day : 1 2 1 1 1 2 1 1 1 2 1 Sum = 14 odd days => 0 odd days.Calendar for the year 2018 will be the same as for the year 2007.

Q: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 1969 0

  • 1
    12 a.m.
    Correct
    Wrong
  • 2
    1 p.m.
    Correct
    Wrong
  • 3
    11 a.m.
    Correct
    Wrong
  • 4
    12 p.m.
    Correct
    Wrong
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Answer : 4. "12 p.m."
Explanation :

Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

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