Bank Exams प्रश्न और उत्तर का अभ्यास करें

प्र: In the following options, select the one which is different from the other three ? 2604 0

  • 1
    Concentration
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  • 2
    Concourse
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  • 3
    Radiation
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  • 4
    Confluence
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उत्तर : 3. "Radiation"
व्याख्या :

Answer: C) Radiation Explanation: Radiation shows the property of spreading while the rest three shows concentration at a point.

प्र: In a class of 60 students where girls are twice that of boys, Laxmi ranked 27th from the top. If there are 9 boys ahead of Laxmi, how many girls are after her rank ? 2603 0

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    23
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  • 2
    21
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  • 3
    22
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  • 4
    24
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उत्तर : 3. "22"
व्याख्या :

Answer: C) 22 Explanation: Given number of girls are twice that of boys. --> G=2B and G+B = 60  Therefore,  G=40 and B= 20 Given Laxmi ranked 27th from the top and 9 boys are ahead of Laxmi. Therefore, There are 17 girls ahead of Laxmi.  Therefore, Number of girls who ranked after Laxmi = 40 - (17+1) = 22.

प्र: At what time between 3 and 4 o’clock will the minute hand and the hour hand are on the same straight line but facing opposite directions ? 2601 0

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    3:15 2/8
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  • 2
    3:49
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  • 3
    3:49 1/11
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  • 4
    3:51
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उत्तर : 3. "3:49 1/11"
व्याख्या :

Answer: C) 3:49 1/11 Explanation: On straight line means 180 degree angle.180 = 11/2 min – 30 hrs180 = 11/2 m – 30 × 3180 = 11/2 m – 90(180 + 90) 2 = 11 mm = 540/11 = 49 1/11 minutes.

प्र: The Famous 'Golconda Fort' is located in which state ? 2601 0

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    Punjab
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  • 2
    Telangana
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  • 3
    Goa
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  • 4
    Andhra Pradesh
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उत्तर : 2. "Telangana"
व्याख्या :

Answer: B) Telangana Explanation:

प्र: M, N and O can complete the work in 18, 36 and 54 days respectively. M started the work and worked for 8 days, then N and O joined him and they all worked together for some days. M left the job one day before completion of work. For how many days they all worked together? 2588 0

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    4
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  • 2
    5
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  • 3
    3
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  • 4
    6
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उत्तर : 2. "5"
व्याख्या :

Answer: B) 5 Explanation: Let M, N and O worked together for x days. From the given data,M alone worked for 8 daysM,N,O worked for x daysN, O worked for 1 day But given thatM alone can complete the work in 18 daysN alone can complete the work in 36 daysO alone can complete the work in 54 days The total work can be the LCM of 18, 6, 54 = 108 units M's 1 day work = 108/18 = 6 unitsN's 1 day work = 108/36 = 3 unitsO's 1 day work = 108/54 = 2 units Now, the equation is8 x 6 + 11x + 5 x 1 = 10848 + 11x + 5 = 10811x = 103 - 4811x = 55x = 5 days. Hence, all M,N and O together worked for 5 days.

प्र: A student can divide her books into groups of 5, 9 and 13. what is the smallest possible number of the books ? 2586 0

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    487
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  • 2
    585
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  • 3
    635
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  • 4
    705
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उत्तर : 2. "585"
व्याख्या :

Answer: B) 585 Explanation: The smallest possible number of books = L.C.M of 5, 9 and 13.Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.

प्र: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2582 0

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    39 days
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  • 2
    37 days
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  • 3
    35 days
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  • 4
    33 days
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उत्तर : 3. "35 days"
व्याख्या :

Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.

प्र: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2582 0

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    55 kms
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  • 2
    35 kms
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  • 3
    25 kms
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  • 4
    65 kms
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उत्तर : 1. "55 kms"
व्याख्या :

Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.

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