Answer: A) A point has no dimension and a line has one dimension. Explanation: A point has no dimension and a line has one dimension is the statement that best compares a line and a point.

Answer: B) 3.5 years Explanation: Given that Rs. 1860 will become Rs. 2641.20 at 12% => Simple Interest = 2641.20 - 1860 = Rs. 781.20 We know I = PTR/100 => 781.20 x 100 = 1860 x T x 12 => T = 78120/1860x12 => T = 78120/22320 => T = 3.5 years.

Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.

Answer: A) 22 yrs Explanation: Let Reena’s present age be 'K' yrs.Given:{(K+3) x 4} - {(K-3) x 3)} => K = 21 yrsSo her present age is 21 yrs.Then, her age after 1 year is 22 yrs.

Answer: B) Fetal period Explanation: The third and longest period of prenatal development, extending from the ninth week until birth is Fetal period.   The process of prenatal development occurs in three main stages. The first two weeks after conception are known as the germinal stage, the third through the eighth week are known as the embryonic period, and the time from the ninth week until birth is known as the fetal period.

Answer: D) all of the above Explanation:

Answer: B) 36 c Explanation: Monday + Tuesday + Wednesday = 37 x 3 -----------(1)Tuesday + Wednesday + Thursday = 34 x 3---------(2)Thursday = 4/5 of Monday ------------------(3)subtract eqn (1) from (2) we get,Thursday - Monday = -9 => Monday - Thursday = 9.......(4)From (3) & (4), we get So,Thursday = 36 C

Answer: D) All the above Explanation: Glycolysis is the chemical process that converts glucose C₆H₁₂O₆, into Pyruvate, CH₃COCOO− + H⁺.   It represents the first stage in the chemical oxidation of glucose by a cell. The free energy released in this process is used to form the high-energy molecules ATP and NADH.