Bank Exams рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: 10 boys can complete a work in 7 days and 10 girls take 14 days to complete the work. How many days will 5 boys and 10 girls take to complete the work ? 1254 05b5cc6dee4d2b4197774ea85
5b5cc6dee4d2b4197774ea85- 113 daysfalse
- 210 daysfalse
- 37 daystrue
- 416 daysfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "7 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 7 days Explanation: 1 boy's 1 day work = 1/70 1 girl's 1 day work = 1/140 (5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7 ┬а 5 boys and 10 girls will complete the work in 7 days.
рдкреНрд░: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ┬а? 3117 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "4312 sq.m"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.┬а┬а ┬а2╧Аs = 264 and┬а2╧Аl = 352┬а┬а ┬а ┬аs =┬а2642╧А and l =┬а3522╧А┬а┬а┬а Difference between the areas =╧Аl2-╧Аs2┬а┬а┬а ┬а┬а=┬а╧А1762╧А2-1322╧А2┬а ┬а┬а= 1762╧А-1322╧А┬а┬а ┬а = (176 - 132)(176 + 132) /┬а╧А┬а┬а ┬а = (44 x 308) / (22/7) = 4312 sq.m
рдкреНрд░: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned ┬а? 2175 05b5cc6dee4d2b4197774ea74
5b5cc6dee4d2b4197774ea74- 1Rs. 11828.80false
- 2Rs. 19828.80true
- 3Rs. 9828.80false
- 4Rs. 19328.80false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "Rs. 19828.80"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) Rs. 19828.80 Explanation: Let the sum be Rs. P P{ 1+81002- 1 } = 2828.80 ┬а It is in the form of┬а┬аa2-b2┬а=┬аa+ba-b ┬а P(8/100)(2 + 8/100) = 2828.80 ┬а P = 2828.80 / (0.08)(2.08) ┬а = 1360/0.08 = 17000 ┬а Principal + Interest = Rs. 19828.80
рдкреНрд░: Rifath Sharook has designed the worldтАЩs lightest satellite тАЬKalamSatтАЭ. He hails from which country ┬а? 1271 05b5cc6dee4d2b4197774ea6f
5b5cc6dee4d2b4197774ea6f- 1Russiafalse
- 2Pakistanfalse
- 3Dubaifalse
- 4Indiatrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "India"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) India Explanation: Indian teen Rifath Sharook from Tamil Nadu has designed the worldтАЩs lightest & smallest satellite named тАЬKalamSatтАЭ. The satellite weighs only 64 grams and will be launched by NASA on June 21, 2017. With this, he will become the first Indian student to have his experiment launched by NASA. The main role of the satellite will be to demonstrate the performance of 3-D printed carbon fibre. The satellite has been designed in a way which will have a 240-minute mission in space and will operate for 12 minutes in a micro-gravity environment of space.
рдкреНрд░: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 4167 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
- 235false
- 354false
- 440false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "20"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 20 Explanation: Numbers of students in section A = x тИ┤ Numbers of students in section B and C = (100 тАУ x) тИ┤ x 70 + (100 тАУ x) 87.5 = 84 100 => 70x + 87.5 100 тАУ 87.5x = 8400 => 8750 тАУ 17.5x = 8400 => 17.5x = 8750 тАУ 8400 => x = 20.
рдкреНрд░: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ┬а? 1664 05b5cc6dee4d2b4197774ea5b
5b5cc6dee4d2b4197774ea5b- 110 secfalse
- 248 secfalse
- 336 sectrue
- 456 secfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "36 sec"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.
рдкреНрд░: The arithmetic mean of the following numbers 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6 and 7, 7, 7, 7, 7, 7, 7 is ┬а ? 2265 05b5cc6dee4d2b4197774ea60
5b5cc6dee4d2b4197774ea60- 16false
- 29false
- 37false
- 45true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "5"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 5 Explanation: Arithmatic mean = sum/members┬а => (1x1 + 2x2 + 3x3 + 4x4 + 5x5 + 6x6 + 7x7) / (1 + 2 + 3 + 4 + 5 + 6 + 7) => 140/28 = 5
рдкреНрд░: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ┬а? 3990 05b5cc6dee4d2b4197774ea56
5b5cc6dee4d2b4197774ea56- 168 kmphtrue
- 252 kmphfalse
- 376 kmphfalse
- 450 kmphfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "68 kmph"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph

