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प्र: In a certain code, MONKEY is written as XDJMNL. How is TIGER written in that code ? 3039 0

उत्तर : 4. "QDFHS"
व्याख्या :
Answer: D) QDFHS Explanation: The letter of the word are written in a reverse order and then each letter is moved one step backward to obtain the code.

प्र: Find the odd one out of the following words ? 1665 0

उत्तर : 1. "cruise"
व्याख्या :
Answer: A) cruise Explanation: Cruise = a sea voyage for pleasure. All other words are related to ‘journey on land, sea with an aim’.

प्र: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1658 0

उत्तर : 3. "40"
व्याख्या :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

प्र: STIMULANT : ACTIVITY :: 1577 0

उत्तर : 2. "fertilizer : growth"
व्याख्या :
Answer: B) fertilizer : growth Explanation:

प्र: The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 1513 0

उत्तर : 4. "245 mts"
व्याख्या :
Answer: D) 245 mts Explanation: Let the length of the brigade is x mtsThen Distance = 130 + x mtsgiven speed = 45 kmph = 45 x5/18 m/sTime = 30 secT = D/S => 30 = 130+x/(45x5/18)=> x = 245 mts.

प्र: If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ? 2037 0

उत्तर : 1. "40 kms"
व्याख्या :
Answer: A) 40 kms Explanation: Let the actual distance travelled be x km. Then x/8=(x+20)/12 => 12x = 8x + 160=> 4x = 160=> x = 40 km.

प्र: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 3056 0

उत्तर : 3. "102 men"
व्याख्या :
Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.

प्र: It takes one minute to fill 2/7 th of a vessel. What is the time taken in minutes to fill the whole of the vessel ? 1884 0

प्र: In a certain code, MONKEY is written as XDJMNL. How is TIGER written in that code ? 3039 05b5cc6d9e4d2b4197774e820

उत्तर : 4. "QDFHS" व्याख्या :Answer: D) QDFHS Explanation: The letter of the word are written in a reverse order and then each letter is moved one step backward to obtain the code.

प्र: Find the odd one out of the following words ? 1665 05b5cc6d9e4d2b4197774e81b

उत्तर : 1. "cruise" व्याख्या :Answer: A) cruise Explanation: Cruise = a sea voyage for pleasure. All other words are related to ‘journey on land, sea with an aim’.

प्र: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1658 05b5cc6d9e4d2b4197774e816

उत्तर : 3. "40" व्याख्या :Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

प्र: STIMULANT : ACTIVITY :: 1577 05b5cc6d9e4d2b4197774e811

उत्तर : 2. "fertilizer : growth" व्याख्या :Answer: B) fertilizer : growth Explanation:

प्र: The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 1513 05b5cc6d9e4d2b4197774e80c

उत्तर : 4. "245 mts" व्याख्या :Answer: D) 245 mts Explanation: Let the length of the brigade is x mtsThen Distance = 130 + x mtsgiven speed = 45 kmph = 45 x5/18 m/sTime = 30 secT = D/S => 30 = 130+x/(45x5/18)=> x = 245 mts.

प्र: If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ? 2037 05b5cc6d9e4d2b4197774e802

उत्तर : 1. "40 kms" व्याख्या :Answer: A) 40 kms Explanation: Let the actual distance travelled be x km. Then x/8=(x+20)/12 => 12x = 8x + 160=> 4x = 160=> x = 40 km.

प्र: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 3056 05b5cc6d9e4d2b4197774e807

उत्तर : 3. "102 men" व्याख्या :Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.

प्र: It takes one minute to fill 2/7 th of a vessel. What is the time taken in minutes to fill the whole of the vessel ? 1884 05b5cc6d8e4d2b4197774e7fd

उत्तर : 2. "7/2 min" व्याख्या :Answer: B) 7/2 min Explanation: Time taken to fill 2/7 = 1Then to fill full 1 = ?? = 1/(2/7) = 7/2 minutes.

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प्र: In a certain code, MONKEY is written as XDJMNL. How is TIGER written in that code ? 3039 0

उत्तर : 4. "QDFHS"
व्याख्या :
Answer: D) QDFHS Explanation: The letter of the word are written in a reverse order and then each letter is moved one step backward to obtain the code.

प्र: Find the odd one out of the following words ? 1665 0

उत्तर : 1. "cruise"
व्याख्या :
Answer: A) cruise Explanation: Cruise = a sea voyage for pleasure. All other words are related to ‘journey on land, sea with an aim’.

प्र: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1658 0

उत्तर : 3. "40"
व्याख्या :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

प्र: STIMULANT : ACTIVITY :: 1577 0

उत्तर : 2. "fertilizer : growth"
व्याख्या :
Answer: B) fertilizer : growth Explanation:

प्र: The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 1513 0

उत्तर : 4. "245 mts"
व्याख्या :
Answer: D) 245 mts Explanation: Let the length of the brigade is x mtsThen Distance = 130 + x mtsgiven speed = 45 kmph = 45 x5/18 m/sTime = 30 secT = D/S => 30 = 130+x/(45x5/18)=> x = 245 mts.

प्र: If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ? 2037 0

उत्तर : 1. "40 kms"
व्याख्या :
Answer: A) 40 kms Explanation: Let the actual distance travelled be x km. Then x/8=(x+20)/12 => 12x = 8x + 160=> 4x = 160=> x = 40 km.

प्र: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 3056 0

उत्तर : 3. "102 men"
व्याख्या :
Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.

प्र: It takes one minute to fill 2/7 th of a vessel. What is the time taken in minutes to fill the whole of the vessel ? 1884 0

उत्तर : 2. "7/2 min"
व्याख्या :
Answer: B) 7/2 min Explanation: Time taken to fill 2/7 = 1Then to fill full 1 = ?? = 1/(2/7) = 7/2 minutes.