Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: A batsman scored 180 runs which included 11 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets ? 2150 05b5cc75ce4d2b4197774fc4d
5b5cc75ce4d2b4197774fc4d- 162.45%false
- 251.42%false
- 348.88%true
- 447.32%false
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उत्तर : 3. "48.88%"
व्याख्या :
Answer: C) 48.88% Explanation: Number of runs made by running = 180 - (11 x 4 + 8 x 6)= 180 - (92)= 88Now, we need to calculate 88 is what percent of 180.⇒88180×100 = 48.888%.
प्र: In how many different ways can the letters of the word 'OPTICAL' be arranged so that the vowels always come together? 2150 05c2c4f6e9fd00135a4b20e26
5c2c4f6e9fd00135a4b20e26- 1830false
- 2615false
- 3720true
- 4915false
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उत्तर : 3. "720"
प्र: H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is : 2149 05b5cc6e7e4d2b4197774eda6
5b5cc6e7e4d2b4197774eda6- 1360false
- 2180true
- 390false
- 4120false
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उत्तर : 2. "180"
व्याख्या :
Answer: B) 180 Explanation: 4 x 27 x 3125 = 22 × 33 × 55 ; 8 x 9 x 25 x 7 = 23 × 32 × 52 × 7 16 x 81 x 5 x 11 x 49 = 24 × 34 × 5 × 11 × 72 H.C.F = 22 × 32 × 5 = 180.
प्र: Which of the following is a non metal that remains liquid at room temperature ? 2149 05b5cc6e0e4d2b4197774eb43
5b5cc6e0e4d2b4197774eb43- 1Chlorinefalse
- 2Phosphorousfalse
- 3Brominetrue
- 4Heliumfalse
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उत्तर : 3. "Bromine"
व्याख्या :
Answer: C) Bromine Explanation:
प्र: How many such pairs of letters are there in the word ORDINAL each of which has as many letters between them in the word as in the English alphabet? 2148 05b5cc7c8e4d2b41977750e0e
5b5cc7c8e4d2b41977750e0e- 1Nonefalse
- 2Onefalse
- 3Twofalse
- 4Threetrue
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उत्तर : 4. "Three"
व्याख्या :
Answer: D) Three Explanation:
प्र: At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other? A. 5111 B. 15415 C. 16411 D. 4415 2148 05b5cc77ae4d2b41977750133
5b5cc77ae4d2b41977750133- 1Option Afalse
- 2Option Bfalse
- 3Option Ctrue
- 4Option Dfalse
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उत्तर : 3. "Option C"
व्याख्या :
Answer: C) Option C Explanation: At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand. To be coincident, it must gain 15 min. spaces. 55 min. are gained in 60 min. Then 15 min spaces are gained in = 6055×15 min. Therefore, The hands are coincident at 16411 min. past 3 o'clock.
प्र: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ? 2147 05b5cc6e1e4d2b4197774ebde
5b5cc6e1e4d2b4197774ebde- 1215true
- 2268false
- 3254false
- 4216false
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उत्तर : 1. "215"
व्याख्या :
Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 216 - 1 = 215.
प्र: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys? 2146 05b5cc6b9e4d2b4197774d72a
5b5cc6b9e4d2b4197774d72a- 14 daystrue
- 26 daysfalse
- 37 daysfalse
- 45 daysfalse
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उत्तर : 1. "4 days"
व्याख्या :
Answer: A) 4 days Explanation: Given that 6 men and 8 boys can do a piece of work in 10 days 26 men and 48 boys can do the same in 2 days As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B => M = 2B => B = M/2 ……(1) Now Put (1) in 15M + 20B => 15M + 10M = 25M Now, 6M + 8B in 10 days => (6M + 4M) 10 = 100M Then D(25M) = 100M => D = 4 days.