Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved? 2032 05b5cc7d0e4d2b4197775122c
5b5cc7d0e4d2b4197775122c- 11/4false
- 21/2false
- 33/4true
- 47/12false
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उत्तर : 3. "3/4"
व्याख्या :
Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4 PA=12, PB=23, PC= 34 ∴ P( none solves the problem) = P(not A) and (not B) and (not C) = PA∩B∩C = PAPBPC ∵ A, B, C are Independent = 12×23×34 = 14 Hence, P(the problem will be solved) = 1 - P(none solves the problem) = 1-14= 3/4
प्र: 1, 2, 8, 33, ? Find the next number in the given series? 2031 05b5cc6bae4d2b4197774d7e4
5b5cc6bae4d2b4197774d7e4- 1148true
- 2145false
- 3143false
- 4141false
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उत्तर : 1. "148"
व्याख्या :
Answer: A) 148 Explanation: 1 x 1 + 1 x 1 = (1 + 1) = 2 2 x 2 + 2 x 2 = (4 + 4) = 8 8 x 3 + 3 x 3 = (24 + 9) = 33 33 x 4 + 4 x 4 = (132 + 16) = 148 148 x 5 + 5 x 5 = (740 + 25) = 765.
प्र: Who was appointed as Director of the Central Bureau of Investigation in the year 2017 ? 2030 05b5cc76ae4d2b4197774fe8e
5b5cc76ae4d2b4197774fe8e- 1Alok Kumar Vermatrue
- 2Anil Sinhafalse
- 3Rakesh Asthanafalse
- 4Nonefalse
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उत्तर : 1. "Alok Kumar Verma"
व्याख्या :
Answer: A) Alok Kumar Verma Explanation: Senior IPS officer Alok Kumar Verma, Delhi Police Commissioner was appointed as new Director of the Central Bureau of Investigation. He will have tenure of two years. He was selected by a three-member committee comprising Prime Minister Narendra Modi, Chief Justice J S Khehar and Congress leader Mallikarjun Kharge. He will take over from interim director Rakesh Asthana, who was handed the reins of the premier investigating agency after former director Anil Sinha retired on December 2, 2016.
प्र: Which property would be classified as expendable? 2030 05b5cc622e4d2b4197774b7f3
5b5cc622e4d2b4197774b7f3- 1Food given to Armyfalse
- 2Cementfalse
- 3Paintfalse
- 4All of the abovetrue
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उत्तर : 4. "All of the above"
व्याख्या :
Answer: D) All of the above Explanation: Expendable properties are those properties that are consume in use or that lose their identity in use. It also include those properties that become an integral part of other property when put to use and those properties which have an expected service life of less than one year.
प्र: In which of the following organelles does photosynthesis take place? 2030 05b5cc6a7e4d2b4197774ce27
5b5cc6a7e4d2b4197774ce27- 1Miochondriafalse
- 2Chloroplasttrue
- 3Central Vacuolefalse
- 4Ribosomefalse
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उत्तर : 2. "Chloroplast"
व्याख्या :
Answer: B) Chloroplast Explanation: Chloroplasts use energy from light to transform carbon dioxide and water into sugar and oxygen. A green pigment located in membranes within the chloroplasts of plants and algae and in the membranes of certain prokaryotes.
प्र: K and L start a business jointly. K invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit L claims 2/7th share. How much money is contributed by L? 2030 05b5cc767e4d2b4197774fe22
5b5cc767e4d2b4197774fe22- 1Rs. 13,204false
- 2Rs. 14,521false
- 3Rs. 12,800true
- 4Rs. 15,000false
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उत्तर : 3. "Rs. 12,800"
व्याख्या :
Answer: C) Rs. 12,800 Explanation: Given share of L is 2/7 th of profit. Then, their profits are divided in to 5:2 ratio. Ratio of K and L is 16000×8x×4=52 x = Rs. 12,800.
प्र: Find the next number in the given number series? 11, 5.5, 10, 6.5, 9, ? 2030 05b5cc61ee4d2b4197774b753
5b5cc61ee4d2b4197774b753- 16.5false
- 27.5true
- 38.5false
- 410.5false
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उत्तर : 2. "7.5"
व्याख्या :
Answer: B) 7.5 Explanation: The given number series follows a pattern that 11 11 - 5.5 = 5.5 5.5 + 4.5 = 10 10 - 3.5 = 6.5 6.5 + 2.5 = 9 9 - 1.5 = 7.5 Hence, the next number in the given number series is 7.5.
प्र: Which of the following statements about monosaccharide structure is true? 2030 05b5cc65ee4d2b4197774be2c
5b5cc65ee4d2b4197774be2c- 1Aldoses and ketoses differ in the position of their hydroxyl groups.false
- 2Monosaccharides can be classified according to the spatial arrangement of their atoms.true
- 3All monosaccharides contain carbon, hydrogen, oxygen, and nitrogen atoms.false
- 4A six-carbon sugar is called a pentose.false
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उत्तर : 2. "Monosaccharides can be classified according to the spatial arrangement of their atoms."
व्याख्या :
Answer: B) Monosaccharides can be classified according to the spatial arrangement of their atoms. Explanation: Monosaccharides, also called simple sugars, are the most basic units of carbohydrates. They are fundamental units of carbohydrates and cannot be further hydrolyzed to simpler compounds. Hence, Monosaccharides can be classified according to the spatial arrangement of their atoms is true about Monosaccharides.

