Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: A person in a bet 40 shots taken. 50p for a hit, 10p for a miss.(he have to give). Finally he has Rs.5. How many hits he have ? 2131 05b5cc718e4d2b4197774f47c
5b5cc718e4d2b4197774f47c- 115true
- 220false
- 325false
- 430false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 1. "15"
व्याख्या :
Answer: A) 15 Explanation: Let number of hit shots be 'X'Let number of miss shots be 'Y'Given X + Y = 40....(1)50X - 10Y = 500.....(2)Solving 1 and 2, we getX = 15 and Y = 25Therefore, number of hits = 15
प्र: Doctor : Nurse :: ? : Follower 2131 05b5cc69ae4d2b4197774c77d
5b5cc69ae4d2b4197774c77d- 1Managerfalse
- 2Employerfalse
- 3Workerfalse
- 4Leadertrue
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 4. "Leader"
व्याख्या :
Answer: D) Leader Explanation: Here the second one follows the first one. That is a nurse follows a doctor and similarly, a follower follows a leader. Hence, Doctor : Nurse :: Leader : Follower.
प्र: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 2130 05b5cc6cfe4d2b4197774e2ef
5b5cc6cfe4d2b4197774e2ef- 11000 (r - p) + pqfalse
- 21000 p + qrfalse
- 31000 (r - q) + prfalse
- 41000(p - q) + qrtrue
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 4. "1000(p - q) + qr"
व्याख्या :
Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or) The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr
प्र: Square units 13 by 9 of an office area is 2130 05b5cc662e4d2b4197774be89
5b5cc662e4d2b4197774be89- 197false
- 2117true
- 3107false
- 4127false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "117"
व्याख्या :
Answer: B) 117 Explanation: Square units 13 by 9 of an office means office of length 13 units and breadth 9 units. Now its area is 13x 9 = 117 square units or units square.
प्र: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ? 2129 05b5cc6dde4d2b4197774ea00
5b5cc6dde4d2b4197774ea00- 11.5 hrsfalse
- 21.7 hrsfalse
- 32.2 hrstrue
- 43.5 hrsfalse
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उत्तर : 3. "2.2 hrs"
व्याख्या :
Answer: C) 2.2 hrs Explanation: Let the original Speed be "s" kmphAnd the usual time be "t" hrsGiven that if the bus is running at 9s/10 kmph the time is 22 hrs=> [9s/10] x 22 = t x s=> 99/5 = t => t = 19.8 hrs Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
प्र: The sum of the interior angles of a polygon is twice the sum of its exterior angles. How many sides does the polygon have ? 2129 05b5cc72ce4d2b4197774f78d
5b5cc72ce4d2b4197774f78d- 16true
- 24false
- 35false
- 47false
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उत्तर : 1. "6"
व्याख्या :
Answer: A) 6 Explanation: We know that Sum of Interior angles of Polygon = 180(n-2)Sum of Exterior angles of Polygon = 360so 180(n-2)=2x360Therefore, by solving we get n=6 sides.
प्र: Madhu got 32% of the maximum marks in a Bank examination and failed by 8 marks. However, Kumar who took the same examination got 42% of the total marks and got 16 marks more than the cut-off marks. What was the cut-off marks in the examination ? 2129 05b5cc6d1e4d2b4197774e3d4
5b5cc6d1e4d2b4197774e3d4- 176.8false
- 286.8false
- 378.8false
- 484.8true
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उत्तर : 4. "84.8"
व्याख्या :
Answer: D) 84.8 Explanation: Let 'M' be the maximum marks in the examination. Therefore, Madhu got 32% of M = 32M/100 = 0.32MAnd Kumar got 42% of M = 42M/100 = 0.42M.In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1) The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2) Now, Equating (1) and (2), we get0.1M = 24 => M = 24/0.1 = 240'M' is the maximum mark and is equal to 240 marks.We know that Madhu got 32% of the maximum marks.Therefore, Madhu got 32 x 240/100 = 76.8 marks.We also know that Madhu got 8 marks less than the cut-off marks. Therefore, the cut-off marks will be 8 marks more than what Madhu got = 76.8 + 8 = 84.8.
प्र: An express train takes 4 seconds to enter tunnel which is 1 km long. If it is traveling at 108 km an hour, how long will it take to pass completely through the tunnel ? 2129 05b5cc73ae4d2b4197774f8ec
5b5cc73ae4d2b4197774f8ec- 133 secfalse
- 237.33 sectrue
- 336.43 secfalse
- 432 secfalse
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "37.33 sec"
व्याख्या :
Answer: B) 37.33 sec Explanation: Speed = 108 km/hrenter a tunnel,, means that the train covers a distance equal to its own lengthso (108 x 5/18) = x/4 where x= length of trainhence x = 120 mtrsto pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs.so (1120/t) = (108x5/18)t = 37.33 sec

