Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: Vikram Sarabhai Space Centre is located at 1889 05b5cc6b6e4d2b4197774d5b2
5b5cc6b6e4d2b4197774d5b2- 1Thiruvananthapuramtrue
- 2Punefalse
- 3Sriharikotafalse
- 4Ahmedabadfalse
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उत्तर : 1. "Thiruvananthapuram"
व्याख्या :
Answer: A) Thiruvananthapuram Explanation: Vikram Sarabhai Space Centre is located at Thiruvananthapuram, Kerala. This is the lead centre of ISRO responsible for the design and development of launch vehicle technology focusing on rocket and space vehicles for India's satellite programme.
प्र: Three friends had dinner at a restaurant. When the bill was received, Akshitha paid 2/3 as much as Veena paid and Veena paid 1/2 as much as Lasya paid. What fraction of the bill did Veena pay ? 1889 05b5cc71ee4d2b4197774f5ae
5b5cc71ee4d2b4197774f5ae- 111/3false
- 22/13false
- 33/11true
- 413/4false
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उत्तर : 3. "3/11"
व्याख्या :
Answer: C) 3/11 Explanation: Let Veena paid x,so Akshitha paid 2x/3 , and Lasya paid 2x,So total bill paid is given byx+(2x/3) +2x = 1, we geti.e. x = 3/11
प्र: Secondary consumers are eaten by larger 1888 05b5cc63de4d2b4197774bac0
5b5cc63de4d2b4197774bac0- 1fast animalfalse
- 2animal in the third trophic levelfalse
- 3herbivorous animalfalse
- 4predatortrue
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उत्तर : 4. "predator"
व्याख्या :
Answer: D) predator Explanation: A tertiary consumer is an animal that obtains its nutrition by eating primary consumers and secondary consumers. Usually tertiary consumers are carnivorous predators, although they may also be omnivores, which are animals that feed on both meat and plant material. Tertiary consumers often occupy the top trophic level, and so are predated by no other animals; in this case they are called "apex predators". However, when they die their bodies will be consumed by scavengers and decomposers.
प्र: Penny has 5 children, 1st is January, 2nd kid February, 3rd is called march , 4th is April. What is the name of the 5th. 1888 05b5cc6a4e4d2b4197774cc7b
5b5cc6a4e4d2b4197774cc7b- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
Here If you notice the difference, There is no question mark (?) at the end of the puzzle. In that case, "What" is the name of the 5th child.
प्र: Find by how much percentage the average of first 10 odd numbers (starting from 1) is greater than the last term ? 1888 05b5cc71ee4d2b4197774f56d
5b5cc71ee4d2b4197774f56d- 1991/16 %false
- 2900/19 %true
- 3874/13 %false
- 4719/17 %false
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उत्तर : 2. "900/19 %"
व्याख्या :
Answer: B) 900/19 % Explanation: First ten odd numbers form an arithmetic progression of the form1,3,5,7,9......here a = first term = 1d = common difference = 2Average of first n numbers = (2a + (n - 1)d)/2n th term of the AP = a + (n - 1)dSubstituting a = 1, d = 2 and n = 10 in the above formulas average of first 10 numbers = 1010 th term of the AP = 19Therefore average of first 10 terms is 19 - 10 = 9 greater thanthe last term. Hence the average is greater than the sum by9/19 X 100 = 900/19 %
प्र: The sum of the digits of a two-digit number is 12. The difference of the digits is 6. Find the number ? 1887 05b5cc6d8e4d2b4197774e7af
5b5cc6d8e4d2b4197774e7af- 157false
- 275false
- 348false
- 439true
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उत्तर : 4. "39"
व्याख्या :
Answer: D) 39 Explanation: Let the two-digit number be 10a + ba + b = 12 --- (1)If a>b, a - b = 6If b>a, b - a = 6If a - b = 6, adding it to equation (1), we get2a = 18 => a =9so b = 12 - a = 3Number would be 93.if b - a = 6, adding it to the equation (1), we get2b = 18 => b = 9a = 12 - b = 3.Number would be 39.There fore, Number would be 39 or 93.
प्र: One lady has 2 children, one of her child is boy, what is the probability of having both are boys ? 1887 05b5cc728e4d2b4197774f72d
5b5cc728e4d2b4197774f72d- 11/3true
- 21/2false
- 32/3false
- 42/5false
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उत्तर : 1. "1/3"
व्याख्या :
Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.
प्र: Lucky started working 2 years ago. Her starting salary was half of Karthik's salary at that time. Each year since then Lucky and Karthik have received a rise of 10% in their respective salary. What percentage (to the nearest percent) of Karthik's current salary is Lucky's current salary ? 1887 05b5cc6cfe4d2b4197774e2f9
5b5cc6cfe4d2b4197774e2f9- 175%false
- 222.5%false
- 335%false
- 450%true
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उत्तर : 4. "50%"
व्याख्या :
Answer: D) 50% Explanation: Let the salary of Karthik 2 years ago be Rs.100So, Lucky's salary 2 years ago was Rs.50 Karthik's present salary has seen two 10 percent increases. So as Lucky's salary. So, Karthik's salary 1 year ago = 100 + 10% of 100 = 100 + 10 = 110.Karthik's present salary = 110 + 10% of 110 = 110 + 11 = 121. Lucky's salary 1 year ago = 50 + 10% of 50 = 50 + 5 = 55Lucky's present salary = 55 + 10% of 55 = 55 + 5.5 = 60.5 Lucky's present salary of 60.5 = 50% of Karthik's present salary of 121.

