Answer: B) FALSE Explanation: FALSE. Each hemoglobin molecule can transport four molecules of oxygen.   Hemoglobin, or Hb, is a protein molecule found in red blood cells (erythrocytes) made of four subunits: two alpha subunits and two beta subunits. Heme the component of hemoglobin responsible for binding oxygen consists of an iron ion that binds oxygen and a porphyrin ring that binds the globin molecules, one molecule binds one molecule of oxygen and can bind up to four oxygen molecules.

Answer: B) F is second to the right of B Explanation: From the given information, the circular arrangement is Here F is second to the right of B and the remaning all are wrong.

Answer: B) 3 Explanation:

Answer: C) 0.200 Explanation: Here I converted the original fraction to a fraction with the denominator being 10, because decimals can be written in the tenths place. Divide numerator and denominator with '2'15 x 22 = 210 = 0.2

Answer: D) 8 Explanation: Suppose there are 9 balls   Let us give name to each ball B1 B2 B3 B4 B5 B6 B7 B8 B9   Now we will divide all the balls into 3 groups.   Group1 - B1 B2 B3   Group2 - B4 B5 B6   Group3 - B7 B8 B9   Step1 - Now weigh any two groups. Let's assume we choose Group1 on left side of the scale and Group2 on the right side.   So now when we weigh these two groups we can get 3 outcomes.   Weighing scale tilts on left - Group1 has a heavy ball.Weighing scale tilts on right - Group2 has a heavy ball.Weighing scale remains balanced - Group3 has a heavy ball.Lets assume we got the outcome as 3. i.e Group 3 has a heavy ball.   Step2 - Now weigh any two balls from Group3. Lets assume we keep B7 on left side of the scale and B8 on right side.   So now when we weigh these two balls we can get 3 outcomes.   Weighing scale tilts on left - B7 is the heavy ball.Weighing scale tilts on right - B8 is the heavy ball.Weighing scale remains balanced - B9 is the heavy ball.The conclusion we get from this Problem is that each time weigh. We element 2/3 of the balls.   As we came to conclusion that Group3 has the heavy ball from Step1, we remove 6 balls from the equation i.e (2/3) of 9.   Simillarly we do the ame thing for the Step2.   Now going with this conclusion. We have 6561 balls.   Step - 1   Divided into 3 groups   Group1 - 2187Balls   Group2 - 2187Balls   Group3 - 2187Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 2   Divided into 3 groups   Group1 - 729Balls   Group2 - 729Balls   Group3 - 729Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 3   Divided into 3 groups   Group1 - 243Balls   Group2 - 243Balls   Group3 - 243Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 4   Divided into 3 groups   Group1 - 81Balls   Group2 - 81Balls   Group3 - 81Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 5   Divided into 3 groups   Group1 - 27Balls   Group2 - 27Balls   Group3 - 27Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 6   Divided into 3 groups   Group1 - 9Balls   Group2 - 9Balls   Group3 - 9Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 7   Divided into 3 groups   Group1 - 3Balls   Group2 - 3Balls   Group3 - 3Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 8   So now when we weigh 2 balls out of 3 we can get 3 outcomes.   Weighing scale tilts on left - left side placed is the heavy ball.Weighing scale tilts on right - right side placed is the heavy ball.Weighing scale remains balanced - remaining ball is the heavy ball.So the general answer to this question is, it is always multiple of 3 steps.   For 9 balls  32= 9. therefore 2 steps   For 6561 balls 38 = 6561 therefore 8 steps

Answer: A) Axis Bank Explanation:

Answer: B) 420 Explanation: Given total number of students in the class = 21   So each student will have 20 greeting cards to be send or receive (21 - 1(himself))   Therefore, the total number of greeting cards exchanged by the students = 20 x 21 = 420.

A number of possible explanations for why manhole covers are round include :   1. A round manhole cover cannot fall through its circular opening, whereas a square, rectangular, or oval manhole cover could fall in if it were inserted diagonally in the hole. 2. Circular covers don’t need to be rotated or precisely aligned when placing them on the opening. 3. A round manhole cover is easily moved and rolled. 4. Human beings have a roughly circular cross-section. 5. Round tubes are the strongest shape against the compression of the earth around them, so the cover of the tube would naturally be round as well. 6. It’s easier to dig a circular hole.