Bank Exams рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: In the series given below , how many 8's are there each of which is exactly divisible by its immediate preceeding as well as succeeding numbers ?2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6 2981 05b5cc758e4d2b4197774fbc4
5b5cc758e4d2b4197774fbc4- 1fivefalse
- 2fourfalse
- 3twotrue
- 4onefalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "two"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) two Explanation: Clearly, we may mark such sets of 3 numbers, in which the middle number is 8 and each of the two numbers on both sides of it is a factor of 8, as shown below : 2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6 So, there are two such 8's. Hence the answer is C.
рдкреНрд░: A person is asked to put in a basket one apple when ordered 'one', one guava when ordered 'two', one orange whe ordered 'three' and is asked to take out from the basket one apple and one guava both when ordered 'four'. The ordered sequence executed by the person is as follows : 1 2 3 3 2 1 4 2 3 1 4 2 2 3 3 1 4 1 1 3 2 3 4 1. How many apples will be there in the basket at the end of the above order sequence ?┬а ┬а ┬а (a) 4 ┬а ┬а (b) 3 ┬а ┬а (c) 2 ┬а ┬а(d) 1 2. How many fruits will be there in the basket at the end of the above order sequence ?┬а ┬а ┬а (a) 13 ┬а (b) 17 ┬а (c) 9 ┬а ┬а(d) 11 6536 05b5cc754e4d2b4197774fbc3
5b5cc754e4d2b4197774fbc3- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ :
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
1. Answer (c) Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it. Required number of apples = number of 1's - number of 4's = 6 - 4 = 2 2. Answer (d) Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it. Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's) = 6 + 6 + 7 - (2x4) = 19 - 8 = 11.
рдкреНрд░: Statement: There was a spurt in criminal activities in the city during the recent festival season.Courses of action:a. The police should immediately investigate into the causes of this increase.b. In future the police should take adequate precaution to avoid recurrence of such situation during festival.c. The known criminals should be arrested before any such season. 1950 05b5cc754e4d2b4197774fbbe
5b5cc754e4d2b4197774fbbe- 1Both a and b followstrue
- 2Only c followsfalse
- 3Only a followsfalse
- 4Both b and c followsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "Both a and b follows"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) Both a and b follows Explanation: The police ought to find out the lackenings in existing security arrangements and make up for these inadequacies to strengthen security and thus prevent criminal activities in the forthcoming festival. So, both a and b follow. Arresting the known criminals does not ensure safety, for a novice can also indulge in crime. So, c does not follow.
рдкреНрд░: A polygon has 44 diagonals, then the number of its sides are ? 1761 05b5cc754e4d2b4197774fbb9
5b5cc754e4d2b4197774fbb9- 113false
- 29false
- 311true
- 47false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "11"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 11 Explanation: Let the number of sides be n.┬а The number of diagonals is given by┬аnC2┬а- n┬а┬а Therefore, nC2 - n = 44, n>0┬а nC2┬а- n┬а= 44 n2┬а- 3n - 88 = 0┬а n2 -11n + 8n - 88 = 0┬а┬а n(n - 11) + 8(n - 11) = 0┬а n = -8 or n = 11. ┬а As n>0, n will not be -8. Therefore, n=11.
рдкреНрд░: How many parallelograms will be formed if 7 parallel horizontal lines intersect 6 parallel vertical lines? 3293 05b5cc754e4d2b4197774fbb4
5b5cc754e4d2b4197774fbb4- 1215false
- 2315true
- 3415false
- 4115false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "315"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 315 Explanation: Parallelograms are formed when any two pairs of parallel lines (where each pair is not parallel to the other pair) intersect. ┬а Hence, the given problem can be considered as selecting pairs of lines from the given 2 sets of parallel lines. ┬а Therefore, the total number of parallelograms formed = 7C2 x 6C2 = 315
рдкреНрд░: There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ? 4568 05b5cc754e4d2b4197774fbaf
5b5cc754e4d2b4197774fbaf- 1105true
- 27! x 6!false
- 37!/5!false
- 4420false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "105"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 105 Explanation: Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,┬а ┬аThen, 7C1 x 6C2 x 4C4┬а = 7 x 15 x 1 = 105
рдкреНрд░: The value of -4-(-10) is how much greater then the value of -10-(-4) ? 2569 05b5cc754e4d2b4197774fba9
5b5cc754e4d2b4197774fba9- 110false
- 26false
- 312true
- 40false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "12"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 12 Explanation: -4-(-10) = -4+10 = 6 ┬а -10-(-4) = -10+4= -6 ┬а Therefore, 6-(-6) = 6+6 = 12
рдкреНрд░: Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + .... 1696 05b5cc754e4d2b4197774fb9f
5b5cc754e4d2b4197774fb9f- 130,400true
- 230,200false
- 334,600false
- 438,400false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "30,400"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 30,400 Explanation: we can treat every two consecutive terms as one.So, we will have a total of 100 terms of the nature:(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,.... ┬а We know the sum of n terms┬а┬аnn+12 ┬а Now, a= 7, d=6 and n=100Hence the sum of the given series is S= 100/2 x[2 x 7 + 99 x 6]=> 50[608]=> 30,400.