Bank Exams рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ

рдкреНрд░: 'K' cycled from A to B at 10 kmph and returned at the rate of 9 kmph. 'L' cycled both ways at 12 kmph. In the whole journey 'L' took 10 minutes less than 'K'. Find the distance between A and B ? 1557 0

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    32.1 km
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    15.23 km
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    3.75 km
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    32.1 m
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рдЙрддреНрддрд░ : 3. "3.75 km"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 3.75 km Explanation: Let 'd' be the distance between A and BK -time = d/10 + d/9 = 19d/90 hoursL -time = 2d/12 = d/6 hoursWe know that, 10 min = 1/6 hoursThus, time difference between K and L is given as 10 minutes. => 19d/90 - d/6 = 1/6=> (19d-15d)/90 = 1/6=> 4d/90 = 1/6Thus,d= 15/4 km = 3.75 km. hence the distance between A and B is 3.75 km.

рдкреНрд░: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4106 0

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    1124
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    1420
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    1345
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  • 4
    1250
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рдЙрддреНрддрд░ : 4. "1250"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

рдкреНрд░: The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is ? 2726 0

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    6 ml
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    11 ml
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    15 ml
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    9 ml
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рдЙрддреНрддрд░ : 1. "6 ml"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 6 ml Explanation: Let us assume that the lotion has 50% alcohol and 50% water.ratio = 1:1As the total solution is 9mlalcohol = water = 4.5mlNow if we want the quantity of alcohol = 30%The quantity of water = 70%The new ratio = 3:7Let x ml of water be addedWe get,4.54.5+x┬а=┬а37=> x=6Hence 6ml of water is added.

рдкреНрд░: Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ? 1664 0

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    24 km
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    50 km
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    42 km
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    30 km
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "50 km"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 50 km Explanation: We know 60 min = 1 hrTotal northward Laxmi's distance = 20kmph x 1hr = 20 kmTotal southward Prasanna's distance = 30kmph x 1hr = 30 kmTotal distance between Prasanna and Laxmi is = 20 + 30 = 50 km.

рдкреНрд░: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 1984 0

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    175
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    345
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    265
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    300
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рдЙрддреНрддрд░ : 4. "300"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.

рдкреНрд░: 6 boys and 8 girls can do job in 10 days , 26 boys & 48 women do work in 2 days. Find time taken by 15 boys and 20 girls to do same work ? 1868 0

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    2 days
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    3 days
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    4 days
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    5 days
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рдЙрддреНрддрд░ : 3. "4 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 4 days Explanation: One day work of 6 boys and 8 girls is given as 6b + 8g = 1/10 -------->(I) ┬а One day work of 26 boys and 48 women is given as 26b + 48w = 1/2 -------->(II) ┬а Divide both sides by 2 in (I) and then multiply both sides by 5 Now we get,┬а15b + 20g = 1/4. Therefore, 15 boys and 20 girls can do the same work in 4 days.

рдкреНрд░: A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ? 2039 0

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    40 km
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    30 km
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    20 km
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    10 km
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рдЙрддреНрддрд░ : 3. "20 km"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 20 km Explanation: Average speed = 2aba+b, here a=25 b=4 = 2 x 25 x 4/(25+4) = 200/29 km/hr. Distance covered in 5 hours 48 minutes = Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms. Distance of the post office from the village = (40/2) = 20 km.

рдкреНрд░: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ? 2343 0

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    1 : 2 : 3
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    2 : 3 : 4
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    3: 4 : 5
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    4 : 5 : 6
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рдЙрддреНрддрд░ : 2. "2 : 3 : 4"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 2 : 3 : 4 Explanation: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x. There is a proposal to increase these seats by 40%, 50% and 75% respectively. Then Seats for Mathematics, Physics and Biology in a school will be 1.4 X 5x, 1.5 X 7x and 1.75 X 8x and ratio will be 7 : 10.5 : 14 ┬а=> 2:3:4.

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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
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      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
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      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ