Bank Exams Practice Question and Answer
8Q: The study of Heavenly bodies is called 3707 05b5cc6a2e4d2b4197774cbc7
5b5cc6a2e4d2b4197774cbc7- 1Astronomytrue
- 2Astrologyfalse
- 3Astrophysicsfalse
- 4Astronauticsfalse
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Answer : 1. "Astronomy"
Explanation :
Answer: A) Astronomy Explanation: Astronomy is the study of planets and heavenly bodies. Historically, astronomy has focused on observations of heavenly bodies. It is a close cousin to astrophysics. Succinctly put, astrophysics involves the study of the physics of astronomy and concentrates on the behavior, properties and motion of objects out there.
Q: Which pair of atoms has the highest electronegativity difference? (Calcium's electronegativity is 1.0 Fluorine's electronegativity is 4.0 Hydrogen's electronegativity is 2.2 Sodium's electronegativity is 0.93) 3704 05b5cc669e4d2b4197774bf7c
5b5cc669e4d2b4197774bf7c- 1F-Ffalse
- 2Ca-Ffalse
- 3H-Ffalse
- 4Na-Ftrue
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Answer : 4. "Na-F"
Explanation :
Answer: D) Na-F Explanation: F-F = 4 - 4 = 0 Ca-F = 4 - 1 = 3.0 H-F = 4 - 2.2 = 1.8 Na-F = 4 - 0.93 = 3.07 Hence, the highest electronegativity difference is in Na-F.
Q: Select the correct statement about cellular respiration? 3704 05b5cc6a3e4d2b4197774cc34
5b5cc6a3e4d2b4197774cc34- 1All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide moleculetrue
- 2All the carbon atoms in glucose ultimately incorporated during cellular respiration into NADH moleculefalse
- 3All the carbon atoms in glucose ultimately incorporated during cellular respiration into ATP moleculefalse
- 4All the carbon atoms in glucose ultimately incorporated during cellular respiration into water moleculefalse
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Answer : 1. "All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule"
Explanation :
Answer: A) All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule Explanation: All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecules.
Q: P and Q can complete a job in 24 days working together. P alone can complete it in 32 days. Both of them worked together for 8 days and then P left. The number of days Q will take to complete the remaining work is ? 3697 05b5cc6c0e4d2b4197774db05
5b5cc6c0e4d2b4197774db05- 156 daysfalse
- 254 daysfalse
- 360 daysfalse
- 464 daystrue
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Answer : 4. "64 days"
Explanation :
Answer: D) 64 days Explanation: (P+Q)'s 1 day work = 1/24 P's 1 day work = 1/32 => Q's 1 day work = 1/24 - 1/32 = 1/96 Work done by (P+Q) in 8 days = 8/24 = 1/3 Remainining work = 1 - 1/3 = 2/3 Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.
Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3696 05b5cc71be4d2b4197774f4fe
5b5cc71be4d2b4197774f4fe- 1Rs. 404.80true
- 2Rs. 536.80false
- 3Rs.440false
- 4Rs. 160false
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Answer : 1. "Rs. 404.80"
Explanation :
Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Q: In an election between two candidates K and L, the number of valid votes received by K exceeds those received by L by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did L get ? 3696 05b5cc6d7e4d2b4197774e6fb
5b5cc6d7e4d2b4197774e6fb- 13241false
- 22457false
- 32642false
- 42834true
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Answer : 4. "2834"
Explanation :
Answer: D) 2834 Explanation: Let the total number of votes polled in the election be 100k.Number of valid votes = 100k - 20% (100k) = 80kLet the number of votes polled in favour of K and L be a and b respectively.a - b = 15% (100k) => a = b + 15k=> a + b = b + 15k + bNow, 2b + 15k = 80k and hence b = 32.5kIt is given that 100k = 872032.5k = 32.5k/100k x 8720 = 2834 The number of valid votes polled in favour of L is 2834.
Q: Which among the following is a folk dance of India? 3681 05b5cc690e4d2b4197774c418
5b5cc690e4d2b4197774c418- 1Garbatrue
- 2Kathakalifalse
- 3Manipurifalse
- 4Mohiniattamfalse
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Answer : 1. "Garba"
Explanation :
Answer: A) Garba Explanation:
Q: Direction 15. In this question five words are given. Which of them will come in the middle if all of them are arranged alphabetically as in a dictionary? 3679 05c419177c5835e577229cab8
5c419177c5835e577229cab8- 1Rumbustiousfalse
- 2Rumanianfalse
- 3Rumourfalse
- 4Ruminatetrue
- 5Rumplefalse
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