Answer: D) 14.5 Explanation: Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.k/l = 5/x ------ (1)k = m - 18 ------ (2)m + 9 = 47 ------ (3)k - l = m ----- (4)(3) => m = 47 - 9 = 38 years(2) => k = 38 -18 = 20 years(1) => 20/l = 5/x => l = 4x(4) => 4x - 20 = 38=> 4x = 58 => x = 14.5

Answer: D) 117 days Explanation: K's work in a day(1st day) = 1/30L's work in a day(2nd day)= -1/60(demolishing)hence in 2 days, combined work= 1/30 - 1/60 =1/60since both works alternatively, K will work in odd days and L will work in even days.1/60 unit work is done in 2 days58/60 unit work will be done in 2 x 58 days = 116 daysRemaining work = 1-58/60 = 1/30Next day, it will be K's turn and K will finish the remaining 1/30 work.hence total days = 116 + 1 = 117.

Answer: B) TZTSTNF Explanation: ARC -> CRA ->(+1) DSB    H ->     H ->(-1) GIVE  ->  EVI ->(+1) FWJ  Similarly,  SYS -> SYS ->(+1) TZT    T ->     T ->(-1) SEMS -> SME ->(+1) TNF

Answer: C) 10 years Explanation: Let the age of the daughter today be ‘x’ years. Mother’s age today = 3x years After 10 years, we have 3x + 10 = 2(x + 10) x = 10 years.

Answer: B) 13 + 1/3 days Explanation: C alone can finish the work in 40 days.As given C does half as much work as A and B together => (A + B) can do it in 20 days(A + B)s 1 days wok = 1/20.A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]B's 1 days work = (1/20) x (2/3) = 1/30(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40 All the three together will finish it in 40/3 = 13 and 1/3 days.

Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ?    55.55 155.00  15.55    0.5    0.05 _______ 226.65 _______   Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.

Answer: C) Along warm water currents from the equator to the poles Explanation:

Answer: B) Rs.12,000 Explanation: We have P = 8748, R = -10 and n = 3Therefore, the purchase price of the machine= P1+R100n= 87481-101003= 8748 x (100/90) x (100/90) x (100/90)= 12,000.   Therefore, the purchase price of the machine was Rs. 12,000.