Bank Exams प्रश्न और उत्तर का अभ्यास करें

प्र: The ratio of male and female in a city is 7 : 8 respectively and percentage of children among male and female is 25 and 20 respectively. If number of adult females is 156800, what is the total population of the city? 3170 0

  • 1
    4,12,480
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  • 2
    3,67,500
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  • 3
    5,44,700
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    गलत
  • 4
    2,98,948
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    गलत
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उत्तर : 2. "3,67,500"
व्याख्या :

Answer: B) 3,67,500 Explanation: Let the total population be 'p' Given ratio of male and female in a city is 7 : 8 In that percentage of children among male and female is 25% and 20% => Adults male and female % = 75% & 80% But given adult females is = 156800 => 80%(8p/15) = 156800 => 80 x 8p/15 x 100 = 156800 => p = 156800 x 15 x 100/80 x 8 => p = 367500 Therefore, the total population of the city = p = 367500

प्र: Which of the following is not a RM principle? 3169 0

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    Apply the RM process to situations where serious injury might occur
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  • 2
    Accept no unnecessary risk
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  • 3
    Integrate RM into all phases of missions and activities
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  • 4
    Make risk decisions at the appropriate level
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उत्तर : 1. "Apply the RM process to situations where serious injury might occur"
व्याख्या :

Answer: A) Apply the RM process to situations where serious injury might occur Explanation: Apply the RM process to situations where serious injury might occur is not a RM (Risk Management) principle.   Risk Management :: A decision-making process for managing day-to-day schedules when there are conflicts.

प्र: Suppose today is Friday, what day of the week will it be 65 days from now? 3160 0

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    Saturday
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  • 2
    Sunday
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  • 3
    Friday
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  • 4
    Thursday
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उत्तर : 2. "Sunday"
व्याख्या :

Answer: B) Sunday Explanation: The day of the week repeats every 7 days. Given today is Friday. Again Friday is repeated on the 7th day, 14th,... on 7 multiple days. Hence, Friday is on the 63rd day, as 63 is multiple of 7.   Now, the required day of the week on the 65th day is Sunday.

प्र: Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ? 3158 0

  • 1
    Rs. 1595.14
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  • 2
    Rs. 1793.4
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  • 3
    Rs. 595.14
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  • 4
    Rs. 1551.5
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उत्तर : 1. "Rs. 1595.14"
व्याख्या :

Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.

प्र: Bijapur is known for its what? 3158 0

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    Statue of Gomateshwara
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  • 2
    Heavy rainfall
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  • 3
    Gol Gumbaz
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  • 4
    Severe Drought area
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उत्तर : 3. "Gol Gumbaz"
व्याख्या :

Answer: C) Gol Gumbaz Explanation: Bijapur is known for its Gol Gumbaz. Bijapur city is well known for its historical monuments of architectural importance built during the rule of the Adil Shahi dynasty.   What is Gol Gumbaz ::   1. It is the tomb of Mohammed Adil Shah. This is the most famous monument in Bijapur.  2. It is the largest dome ever built in India. 3. A particular attraction in this monument is the central chamber, where every sound is echoed seven times. 4. Another attraction at the Gol Gumbaz is the Whispering Gallery, where even minute sounds can be heard clearly 37 metres away.   Statue of Gomateshwara - Shravanabelagola in Karnataka.   Heavy Rainfall - Cherrapunji in Meghalaya.

प्र: In a certain code DOWN is written as '5@9#' and NAME is written as '#6%3'. How is MODE written in that code ? 3156 0

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    6@53
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  • 2
    %@53
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  • 3
    53%#
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  • 4
    %#35
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उत्तर : 2. "%@53"
व्याख्या :

Answer: B) %@53 Explanation: From the given information : D O W N A M E == 5 @ 9 # 6 % 3 MODE = %@53

प्र: A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ? 3155 0

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    4/3 hrs
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  • 2
    2/3 hrs
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  • 3
    3/2 hrs
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  • 4
    1/4 hrs
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उत्तर : 2. "2/3 hrs"
व्याख्या :

Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour

प्र: Two goods trains each 520 m long, are running in opposite directions on parallel tracks. Their speeds are 42 km/hr and 36 km/hr respectively. Find the time taken by the slower train to cross the driver of the faster one ? 3154 0

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    60 sec
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  • 2
    48 sec
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  • 3
    45 sec
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  • 4
    34 sec
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उत्तर : 2. "48 sec"
व्याख्या :

Answer: B) 48 sec Explanation: Relative speed = 42 + 36 = 78 km/hr = 653 m/s Distance = (520 + 520) =1040 mts. Time = 1040×365= 48 sec

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