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In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ?5
Q: In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ?
- 113true
- 2821false
- 3621false
- 42021false
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Answer : 1. "13"
Explanation :
Answer: A) Option A Explanation: Total number of flowers = (8+7+6) = 21. Let E = event that the flower drawn is neither red nor green. = event taht the flower drawn is blue. --> n(E)= 7 --> P(E)= 721=13