जॉइन Examsbook
1669 0

प्र: P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

  • 1
    99
  • 2
    100
  • 3
    89
  • 4
    1
  • उत्तर देखेंउत्तर छिपाएं
  • Workspace

उत्तर : 1. "99"
व्याख्या :

Answer: A) 99 Explanation: Let, Distance between A and B = d   Distance travelled by P while it meets Q = d + 11   Distance travelled by Q while it meets P = d – 11   Distance travelled by Q while it meets R = d + 9   Distance travelled by R while it meets Q = d – 9   Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11   The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9   But given Ratio of speeds of P & R => P : R = 3 : 2  SPSR = SPSQxSQSR = d+11d+9d-11d-9   => d+11d+9d-11d-9 = 3/2   =>  d = 1, 99   => d = 99 satisfies.   Therefore, Distance between A and B = 99

पिछला अगला

Quantitative Aptitude Bank Exams IIT JEE GATE CAT

क्या आपको यकीन है

  त्रुटि की रिपोर्ट करें

कृपया संदेश दर्ज करें
त्रुटि रिपोर्ट सफलतापूर्वक जमा हुई