Practice Question and Answer

Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 2165 0

  • 1
    146
    Correct
    Wrong
  • 2
    203
    Correct
    Wrong
  • 3
    345
    Correct
    Wrong
  • 4
    96
    Correct
    Wrong
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Answer : 1. "146"
Explanation :

Answer: A) 146 Explanation: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? Now arranging the given numbers in descending order.837 746 519 495 328 519 - 746/2 = 519 - 373 = 146.

Q:

दिए गए विकल्पों में से सम्बन्धित अक्षर /शब्द /संख्या/ आकृति को चुनिए।
453 : 17 : : 663 : ?

2164 0

  • 1
    20
    Correct
    Wrong
  • 2
    24
    Correct
    Wrong
  • 3
    19
    Correct
    Wrong
  • 4
    34
    Correct
    Wrong
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Answer : 2. "24 "

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Answer : 2. "Rs. 160"
Explanation :

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Q:

राष्ट्रीय उत्पादकता दिवस किस तारीख को मनाया जाता है?

2164 0

  • 1
    9th फरवरी
    Correct
    Wrong
  • 2
    10th फरवरी
    Correct
    Wrong
  • 3
    11th फरवरी
    Correct
    Wrong
  • 4
    12th फरवरी
    Correct
    Wrong
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Answer : 4. "12th फरवरी"

Q:

लुप्त संख्या ज्ञात कीजिए?
15, 31, 64, 131, ?

2164 0

  • 1
    192
    Correct
    Wrong
  • 2
    524
    Correct
    Wrong
  • 3
    266
    Correct
    Wrong
  • 4
    256
    Correct
    Wrong
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Answer : 3. "266"

Q: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 2164 0

  • 1
    1000 (r - p) + pq
    Correct
    Wrong
  • 2
    1000 p + qr
    Correct
    Wrong
  • 3
    1000 (r - q) + pr
    Correct
    Wrong
  • 4
    1000(p - q) + qr
    Correct
    Wrong
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Answer : 4. "1000(p - q) + qr"
Explanation :

Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or)  The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y   Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr

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