Answer: C) /30 Explanation: A point-to-point link uses only two hosts. A/30, or 255.255.255.252, mask provides two hosts per subnet.

Answer: C) 200.10.5.64 Explanation: This is a pretty simple question. A/28 is 255.255.255.240, which means that our block size is 16 in the fourth octent. 0,16, 32, 48, 64, 80, etc. The host is in the 64 subnet.

Answer: B) 255.255.255.224 Explanation: You need 5 subnets, each with at least 16 hosts. The mask 255.255.255.240 provides 16 subnets with 14 hosts - this will not work. The mask 255.255.255.224 provides 8 subnets, each with 30 hosts. This is the best answer.

Answer: C) 30 Explanation: A/27 (255.255.255.224) is 3 bits on and 5 bits off. This provides 8 subnets, each with 30 hosts. Does it matter if this mask is used with a Class A, B, or C network address? Not at all. The number of host bits would never change.

Answer: D) Router(config)#ip subnet-zero Explanation: A Class C subnet mask of 255.255.255.224 is 3 bits on and 5 bits off (11100000) and provides 8 subnets, each with 30 hosts. However, if the command ip subnet-zero is not used, then only 6 subnets would be available for use.

Answer: C) 127.0.0.1 Explanation: To test the localstack on your host, ping the loop back interface of 127.0.0.1

A default Class B is 255.255.0.0. A Class B 255.255.255.0 mask is 256 subnets, each with 254 hosts. We need fewer subnets. If we used 255.255.240. 0, this provides 16 subnets. Let's add one more subnet bit. 255.255.248.0. This is 5 bits of subnetting, which provides 32 subnets. This is our best answer A/21

A/23 is 255.255.254.0. The third octet is a block size of 2.0, 2, 4. The subnet is in the 16.2.0 subnet; the broadcast address is 16.3.255