Answer: D) Rs.480 Explanation: SP = Rs.800 ; Profit = 25%  CP = SP x 100100+P% = 800 x 100100+25 = 640    Now, CP = Rs.640   Loss = 25% = 25% of Rs.640 = Rs.160   Thus, SP = CP - Loss = Rs.640 - Rs.160 = Rs.480

Answer: A) 10000 and 15000 Explanation: As both A and B invest the same amounts, the ratio of their profits at the end of the year is equal to the ratio of the time periods for which they have invested.   Thus, the required ratio of their profits = A : B = 8 : 12 = 2 : 3.   Hence, share of A in the total profit = 2 x 25000/5 = Rs.10000   Similarly, share of B in the total profit = 3 x 25000/5 = Rs.15000

Answer: C) Rs. 59000 Explanation: Interest received by A from B = 10% of half of Rs.50000 = 10% of Rs. 25000 = Rs.2500. Amount received by A per annum for being a working partner = 1500 x 12 = Rs.18000 Let 'P' be the part of the remaining profit that A receives as his share. So,total income of A = (Rs.2500 + Rs.18000 + Rs. P ) Total income of B = only his share from the remaining profit = 'P', as  A and B share the remaining profit equally.   We know that income of A = Twice the income of B  So, (2500 + 18000 + P ) = 2(P) P = 20500   Thus, the total profit = 2P + Rs.18000 = 2(20500) + 18000 = Rs.59000.

Answer: B) Rs. 150 and Rs.200 Explanation: Let the incomes of A and B be 3P and 4P. If each saves Rs. 100 per month, then their expenditures = Income - savings = (3P - 100) and (4P - 100).   The ratio of their expenditures is given as 1 : 2. Therefor, (3P - 100) : (4P - 100) = 1 : 2 Solving, We get P = 50. Substitute this value of P in 3P and 4P. Thus, their incomes are : Rs.150 and Rs.200

Answer: C) 810 acres Explanation: 12 men120 acres36 days54 men?54 days  As 12 men can reap 120 acres, 54 men will be able to reap more acres in 36 days, 120 acres of land was reaped, so in 54 days, more land will be reaped.   Thus, the numbers of acres that can be reaped by 54 men in 54 days = 5412x120x5436 = 810 acres

Answer: B) 111.12 meters Explanation: A runs 1000 meters while B runs 900 meters and C runs 800 meters. Therefore, B runs 900 meters while C runs 800 meters. So, the number of meters that C runs when B runs 1000 meters = (1000 x 800)/900 = 8000/9 = 888.88 meters Thus, B can give C (1000 - 888.88) = 111.12 meters start

Answer: C) 127.5 meters Explanation: When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters. Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters. So, in a race of 1000 meters, A beats C by (1000 - 787.5) = 212.5 meters to C. So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.

Answer: B) 117 Explanation: Let us calculate both the length and width of the room in centimeters. Length = 6 meters and 24 centimeters = 624 cm width = 4 meters and 32 centimeters = 432 cm As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room. Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 624 and 432 = 48 Thus, the number of square tiles required = (624 x 432 ) / (48 x 48) = 13 x 9 = 117