जॉइन Examsbookउत्तर : 4. "4 is correct"
The degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression:
1. α=x+y+1i-1
2.α=x+y-1i-1
3. α=i-1x+y+1
4. α=i-1x+y-15
प्र: The degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression: 1. α=x+y+1i-1 2.α=x+y-1i-1 3. α=i-1x+y+1 4. α=i-1x+y-1
- 11 is correctfalse
- 22 is correctfalse
- 33 is correctfalse
- 44 is correcttrue
- उत्तर देखेंउत्तर छिपाएं
- Workspace
उत्तर : 4. "4 is correct"
व्याख्या :
Answer: D) 4 is correct Explanation: Van't Hoff factor (i) = Observed Colligative PropertyNormal Colligative Property AxBy1-α→xA+yxα+yB-xyα Total Moles = 1-α+xα+yα = 1-αx+y-1 i=1+αx+y-11 ⇒α=i-1x+y-1
समान प्रश्न
Since Nithya and Suganya exchange places, so Rita’s new position is the same as Monika’s earlier position. This position is 17th from the right and 10th from the left. Therefore Number of girls in the row = (16 + 1 + 9) = 26.