Aptitude Practice Question and Answer

Q:

1 + 2 + 3 + ............. + 49 + 50 + 49 + 48 + ........+ 3 + 2 + 1 बराबर है -

2083 0

  • 1
    2550
    Correct
    Wrong
  • 2
    2380
    Correct
    Wrong
  • 3
    2500
    Correct
    Wrong
  • 4
    2400
    Correct
    Wrong
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Answer : 3. "2500 "

Q: 200 से बड़ी सबसे छोटी अभाज्य संख्या? 2885 0

  • 1
    201
    Correct
    Wrong
  • 2
    205
    Correct
    Wrong
  • 3
    211
    Correct
    Wrong
  • 4
    203
    Correct
    Wrong
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Answer : 3. "211"
Explanation :

Answer: C) 211 व्याख्या: विभाजन की परीक्षण और त्रुटि विधि से, 201 3 से विभाज्य है 205 5 से विभाज्य है 203 7 से विभाज्य है इसलिए, तीन विकल्पों को समाप्त करने के बाद, 211 है और केवल 1 और स्वयं से विभाज्य है। इसलिए, 211 200 से बड़ी सबसे छोटी अभाज्य संख्या है

Q: A 200 m long train passes a motorcycler, running in the same direction at 12 km/hr, in 15 second and a jeep travelling in the same direction in 20 s. At what speed is the car travelling (length of both the motorcycler and jeep is negligible)? 3354 0

  • 1
    36 kmph
    Correct
    Wrong
  • 2
    32 kmph
    Correct
    Wrong
  • 3
    29 kmph
    Correct
    Wrong
  • 4
    24 kmph
    Correct
    Wrong
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Answer : 4. "24 kmph"
Explanation :

Answer: D) 24 kmph Explanation: Let the speed of the train be 'S' kmph From the given data, Distance = Length of train = D = 200 mts = 200 x 18/5 kms Time = 10 sec given speed of the motorcycler = 12 kmph Relative speed as they are moving in the same direction = (S - 12) kmph (S- 12) = 200 x 18515S - 12 = 48S = 60 kmph  Hence, the speed of the train = S = 60 kmph Now, Let the speed of the jeep be 'x' kmph 60 - x = 200 x 1852060 - x = 36x = 60 - 36x = 24 kmph   Therefore, the speed of the jeep = x = 24 kmph.

Q: Simplify the following equation
 55.55 + 155 + 15.55 + 0.5 + 0.05 = ?
3114 1

  • 1
    8010
    Correct
    Wrong
  • 2
    8020
    Correct
    Wrong
  • 3
    8030
    Correct
    Wrong
  • 4
    8040
    Correct
    Wrong
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Answer : 1. "8010"
Explanation :

Answer: A) 8010 Explanation: (2000 + 3)(2000 + 4) - (2000 + 1)(2000 + 2) = ? Since (2000 x 2000) - (2000 x 2000) is equal to zero. ?= (8000 + 6000 + 12) - (4000 + 2000 + 2) => 14012 - 6002 = 8010.

Q:

निम्नलिखित में से कौन सा अंश सबसे बड़ा है?

2087 1

  • 1
    7/12
    Correct
    Wrong
  • 2
    9/16
    Correct
    Wrong
  • 3
    13/20
    Correct
    Wrong
  • 4
    32/80
    Correct
    Wrong
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Answer : 1. "7/12"
Explanation :

Answer: A) 7/12 स्पष्टीकरण: यहाँ यह बताने के लिए कि दिए गए विकल्पों में से कौन-सी भिन्न बड़ी है, वह भिन्न जिसमें समान हर वाला बड़ा अंश हो या समान अंश वाला छोटा हर। दिए गए विकल्पों में से बड़ी भिन्न ज्ञात करने के लिए, सभी हरों का LCM ज्ञात करके विकल्पों के लिए हरों को समान बनाएं। 7/12, 9/16, 13/20, 32/80 अब, 12, 16, 20, 80 = 240 का एलसीएम। फिर, 140/240, 135/240, 156/240, 96/240 यहां 156240> 140240 > 135240 > 96240=> 1320 > 712 > 916 > 3280 इसलिए, सबसे बड़ी भिन्न = 13/20।

Q: Compounding interest means interest accrues 2276 1

  • 1
    at variable rates throughout the term
    Correct
    Wrong
  • 2
    more quickly than simple interest
    Correct
    Wrong
  • 3
    more slowly than simple interest
    Correct
    Wrong
  • 4
    at the same rate as simple interest
    Correct
    Wrong
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Answer : 2. "more quickly than simple interest"
Explanation :

Answer: B) more quickly than simple interest Explanation: Compounding interest means interest accrues on the interest charged and the principal amount each period the interest is charged. Compound interest is calculated by multiplying the principal amount by one plus the annual interest rate raised to the number of compound periods minus one.The total initial amount of the loan is then subtracted from the resulting value. The formula for calculating compound interest is: [P (1 + i)n] – P = P [(1 + i)n – 1] (Where P = Principal, i = nominal annual interest rate in percentage terms, and n = number of compounding periods.) Take a three-year loan of Rs. 10,000 at an interest rate of 5% that compounds annually. What would be the amount of interest? In this case, it would be: Rs. 10,000 [(1 + 0.05)3] – 1 = 10,000 [1.157625 – 1] = Rs. 1,576.25.   How it grows ::

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Answer : 1. "48 kmph"
Explanation :

Answer: A) 48 kmph व्याख्या: मान लीजिए अखिल की प्रारंभिक गति '4p' kmph है तो गति में कमी के बाद गति = '3p' kmph हम जानते हैं कि, गति में परिवर्तन == समय में परिवर्तन दिए गए आंकड़ों के अनुसार, 243p - 244p = 35 - 2560=> p = 12 अत: अखिल की प्रारंभिक गति = 4p = 4 x 12 = 48 किमी/घंटा।

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