Trigonometry Question and Answers Practice Question and Answer

Q:

sin222° + Sin268°+ Cot2 30° का मान होगा।

1260 0

  • 1
    $$ {5\over 4}$$
    Correct
    Wrong
  • 2
    $$ {3\over 4}$$
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    3
    Correct
    Wrong
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Answer : 3. "4"

Q:

यदि a=tanθ + 1 और b=sinθ+cosθ है तो (b2-1)a का मान होगा—

1254 0

  • 1
    ab
    Correct
    Wrong
  • 2
    2bsecθ
    Correct
    Wrong
  • 3
    2b
    Correct
    Wrong
  • 4
    2bsin θ
    Correct
    Wrong
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Answer : 4. "2bsin θ"

Q:

$${\sqrt{1-cosA\over{1+cosA}}}$$ का क्या मान है?

1251 0

  • 1
    cosecA-sinA
    Correct
    Wrong
  • 2
    cosecA+cotA
    Correct
    Wrong
  • 3
    secA-cotA
    Correct
    Wrong
  • 4
    secA+cotA
    Correct
    Wrong
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Answer : 1. "cosecA-sinA"

Q:

ΔPQR, Q पर एक समकोण है। यदि cos P = 3/5 है, तो cos R का मान ज्ञात करें?

1246 0

  • 1
    $$ {3\over4}$$
    Correct
    Wrong
  • 2
    $$ {5\over3}$$
    Correct
    Wrong
  • 3
    $$ {4\over5}$$
    Correct
    Wrong
  • 4
    $$ {4\over3}$$
    Correct
    Wrong
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Answer : 3. "$$ {4\over5}$$"

Q:

यदि $${secθ+tanθ\over secθ-tanθ}=2{51\over79}$$, तो sinθ का मान बराबर है:

1243 0

  • 1
    $${35\over72}$$
    Correct
    Wrong
  • 2
    $${36\over72}$$
    Correct
    Wrong
  • 3
    $${91\over144}$$
    Correct
    Wrong
  • 4
    $${65\over144}$$
    Correct
    Wrong
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Answer : 4. "$${65\over144}$$"

Q:

$$ {3sin60°-4sin^{3}60°=?}$$.

1241 0

  • 1
    $$ {2\sqrt{3}}$$
    Correct
    Wrong
  • 2
    $$ {4\sqrt{3}}$$
    Correct
    Wrong
  • 3
    0
    Correct
    Wrong
  • 4
    50
    Correct
    Wrong
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Answer : 3. "0"

Q:

यदि $$ {sin\ {θ}}={1\over {\sqrt{2}}}$$  है तब  (tanθ+cosθ का मान ज्ञात कीजिये।

1230 1

  • 1
    $${1\over{\sqrt{2}}}$$
    Correct
    Wrong
  • 2
    $${2\over{\sqrt{2}}}$$
    Correct
    Wrong
  • 3
    $${3\over{\sqrt{2}}}$$
    Correct
    Wrong
  • 4
    $$ {(1+\sqrt{2})\over{\sqrt{2}}}$$
    Correct
    Wrong
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Answer : 4. "$$ {(1+\sqrt{2})\over{\sqrt{2}}}$$"

Q:

यदि $$ {tan\ θ={a\over b}}$$  है तो $$ {a\sinθ+b\cosθ\over{a\sinθ-b\cosθ}}$$   का मान होगा—

1228 0

  • 1
    $$ {a\over {a^{2}+b^{2}}}$$
    Correct
    Wrong
  • 2
    $$ {b\over {a^{2}+b^{2}}}$$
    Correct
    Wrong
  • 3
    $$ {a^{2}-b^{2}\over {a^{2}+b^{2}}}$$
    Correct
    Wrong
  • 4
    $$ {a^{2}+b^{2}\over {a^{2}-b^{2}}}$$
    Correct
    Wrong
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Answer : 4. "$$ {a^{2}+b^{2}\over {a^{2}-b^{2}}}$$"

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