Trigonometry Question and Answers Practice Question and Answer

Q:

यदि p = cosec θ – cot θ and q = (cosec θ + cot θ)-1 तो निम्नलिखित में से कौन सा सही है?

1139 0

  • 1
    p - q = 1
    Correct
    Wrong
  • 2
    p = q
    Correct
    Wrong
  • 3
    p + q = 1
    Correct
    Wrong
  • 4
    p + q = 0
    Correct
    Wrong
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Answer : 2. "p = q "

Q:

यदि 2sinθ + 2sin2θ = 2, तो 2 cos4θ + 2cos2θ का मान है:

1131 0

  • 1
    1
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    0
    Correct
    Wrong
  • 4
    4
    Correct
    Wrong
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Answer : 2. "2"

Q:

$$ {1\over 1+cot2}+{3\over 1+tan^2θ}+2sin^2θ$$  का संख्यात्मक मान होगा –

1123 0

  • 1
    2
    Correct
    Wrong
  • 2
    5
    Correct
    Wrong
  • 3
    6
    Correct
    Wrong
  • 4
    3
    Correct
    Wrong
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Answer : 4. "3"

Q:

$${1+sinθ}\over cosθ $$  निम्नलिखित में से किसके बराबर है (जहाँ $$θ ≠ {π\over2} $$)

1107 0

  • 1
    $${1+cosθ}\over sinθ $$
    Correct
    Wrong
  • 2
    $${tan θ+1}\over tan θ-1 $$
    Correct
    Wrong
  • 3
    $${tan θ-1}\over tan θ+1 $$
    Correct
    Wrong
  • 4
    $$cosθ \over {1-sinθ}\ $$
    Correct
    Wrong
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Answer : 4. "$$cosθ \over {1-sinθ}\ $$"

Q:

sin (1920°) का मान ज्ञात कीजिए।

1107 0

  • 1
    1 / 2
    Correct
    Wrong
  • 2
    1 / √2
    Correct
    Wrong
  • 3
    √3 / 2
    Correct
    Wrong
  • 4
    1 / 3
    Correct
    Wrong
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Answer : 3. "√3 / 2 "

Q:

$$ secA(secA+tanA)(1-sinA)\over (cosec^2A-1)sin^2A$$ इसके बराबर है:

1106 0

  • 1
    cotA
    Correct
    Wrong
  • 2
    cosA
    Correct
    Wrong
  • 3

       sec2A

    Correct
    Wrong
  • 4

      cos2A

    Correct
    Wrong
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Answer : 3. "

   sec2A

"

Q:

sin 730 + cos 1370का मान है:

1106 0

  • 1

    cos 130

    Correct
    Wrong
  • 2

    sin 130

    Correct
    Wrong
  • 3

    cos 180

    Correct
    Wrong
  • 4

    sin 180

    Correct
    Wrong
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Answer : 2. "

sin 130

"

Q:

(1+sinα) (1-sinβ) (1+sinγ)= (1-sinα) (1-sinβ) (1-sinγ)=?

1101 0

  • 1
    ±cosαcosβcosγ
    Correct
    Wrong
  • 2
    ±sinαsinβsinγ
    Correct
    Wrong
  • 3
    ±sinαcosβsecγ
    Correct
    Wrong
  • 4
    ±sinαsinβcosγ
    Correct
    Wrong
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Answer : 1. "±cosαcosβcosγ"

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