Trigonometry Question and Answers Practice Question and Answer

Q:

व्यंजक का मान क्या है?

(tan0° tan1° tan2° tan3° tan4° …… tan89°)

1294 0

  • 1
    1
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    0
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 3. "0 "

Q:

$${cos^2A\over {1+sinA}}$$ का मान क्या होगा?

1286 0

  • 1
    1+sinA
    Correct
    Wrong
  • 2
    1-sinA
    Correct
    Wrong
  • 3
    1+secA
    Correct
    Wrong
  • 4
    1-secA
    Correct
    Wrong
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Answer : 2. "1-sinA"

Q:

$$ {tan\ 40°+tan\ 20° +\sqrt{3}\ tan20° tan40°}$$ का मान है—

1284 0

  • 1
    $$ {\sqrt{12}}$$
    Correct
    Wrong
  • 2
    $$ {1\over{\sqrt{3}}}$$
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    $$ {\sqrt{3}}$$
    Correct
    Wrong
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Answer : 4. "$$ {\sqrt{3}}$$"

Q:

यदि sec θ − tan θ हो तो sec θ + tan θ = $$ \sqrt { 5} $$ का मान ज्ञात कीजिए 

1281 0

  • 1
    $$5{1\over 5}$$
    Correct
    Wrong
  • 2
    5
    Correct
    Wrong
  • 3
    $$5{1\over 5}$$
    Correct
    Wrong
  • 4
    $$\sqrt { 2} \ $$
    Correct
    Wrong
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Answer : 3. "$$5{1\over 5}$$"

Q:

यदि $$tan(A+B)=\sqrt { 3} \ $$ और $$ tan(A-B)= {1\over \sqrt { 3} \ }; 0^0<(A+B)<90^0;A>B, $$ तो A और B का मान हैं

1281 0

  • 1
    45° and 15°
    Correct
    Wrong
  • 2
    15° and 45°
    Correct
    Wrong
  • 3
    30° and 30°
    Correct
    Wrong
  • 4
    60° and 30°
    Correct
    Wrong
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Answer : 1. "45° and 15° "

Q:

यदि $${secA={5\over 4}}$$ है, तो $${{tanA}\over 1+tan^2A}-{sinA\over secA}$$ का मान क्या है?

1274 0

  • 1
    1
    Correct
    Wrong
  • 2
    0
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 2. "0"

Q:

यदि $$ sinA= {4\over 5}$$है, तो $$sin^2A$$ का मान क्या है?

1218 0

  • 1
    $$16\over 25$$
    Correct
    Wrong
  • 2
    $$26\over 25$$
    Correct
    Wrong
  • 3
    $$48\over 25$$
    Correct
    Wrong
  • 4
    $$36\over 25$$
    Correct
    Wrong
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Answer : 1. "$$16\over 25$$"

Q:

$$\left({1\over cosecθ}-{1\over sinθ} \right)+{1\over {cosecθ-cotθ}} -{1\over secθ+tanθ} =?$$

1218 0

  • 1
    sinθcosθ
    Correct
    Wrong
  • 2
    sinθtanθ
    Correct
    Wrong
  • 3
    secθcosecθ
    Correct
    Wrong
  • 4
    cosecθcotθ
    Correct
    Wrong
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Answer : 3. "secθcosecθ"

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