Algebra Practice Question and Answer

Q:

рдпрджрд┐┬а$$p├Чq=p+q+{p\over q}$$,┬ард╣реИ рддреЛ┬а8┬а├Ч┬а2 ┬ардХрд╛ рдорд╛рди рдХреНрдпрд╛ рд╣реЛрдЧрд╛┬а?

1240 0

  • 1
    14
    Correct
    Wrong
  • 2
    16
    Correct
    Wrong
  • 3
    6
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 1. "14 "

Q:

рдпрджрд┐┬а$$ {x^2} -4x-1 $$┬а┬ард╣реИ рддреЛ рдЗрд╕рдХрд╛┬а$$ {{x^6} -{x^4}+{x^2}-1}\over {x^3}$$ ┬ардорд╛рди рд╣реЛрдЧрд╛

1223 0

  • 1
    72
    Correct
    Wrong
  • 2
    76
    Correct
    Wrong
  • 3
    80
    Correct
    Wrong
  • 4
    84
    Correct
    Wrong
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Answer : 1. "72"

Q:

рдпрджрд┐┬а$$ {(x-5)^{2} +{(y-2)^{2}}+{(z-9)^{2}=0}}$$┬а┬ард╣реИ рддреЛ┬а(x+y-z)┬ардХрд╛ рдорд╛рди рдХреНрдпрд╛ рд╣реЛрдЧрд╛?

1223 0

  • 1
    -2
    Correct
    Wrong
  • 2
    4
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 1. "-2"

Q:

рдпрджрд┐ a+b+c=7 рдФрд░ a3+b3+c3-3abc=175, рддреЛ (ab+bc+ca) рдХрд╛ рдорд╛рди рдХреНрдпрд╛ рд╣реИ?

1223 0

  • 1
    8
    Correct
    Wrong
  • 2
    9
    Correct
    Wrong
  • 3
    7
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 1. "8"

Q:

рдпрджрд┐┬а$$ {x^{4}+x^{2}y^{2}+y^{4}={21\over256}}$$┬ардФрд░┬а$$ {x^{2}+xy+y^{2}={3\over16}}$$┬ард╣реИ рддреЛ рддрдм┬а$$ {2(x^{2}+y^{2})}=?$$┬ард╣реЛрдЧрд╛ред

1211 0

  • 1
    $$ {3\over 8}$$
    Correct
    Wrong
  • 2
    $$ {5\over 8}$$
    Correct
    Wrong
  • 3
    $$ {3\over 4}$$
    Correct
    Wrong
  • 4
    $$ {5\over 16 }$$
    Correct
    Wrong
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Answer : 2. "$$ {5\over 8}$$"

Q:

рдпрджрд┐ p3 тАУ q3 = (p-q)[(p-q)2+xpq)] ┬ард╣реЛ, рддреЛ x рдХрд╛ рдорд╛рди рдЬреНрдЮрд╛рдд рдХреАрдЬрд┐рдпреЗ

1208 0

  • 1
    1
    Correct
    Wrong
  • 2
    -1
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 3. "3"

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