Trigonometry Practice Question and Answer
8 4 Q:
5ecf342aa7365b2f4ce1cfb0 4 Q:
5dd38322874d2d52fa317fac 4 Q:
5dd38201bfcbc45cddeddb4d 4 Q:
5feeea721f464d740159faae 4 Q:
5efeb11c7228dd6b06e74e29 4 Q:
64abd872299b7896000b39a6 Answer : 3. "
4 Q:
5f76cdfee487e60dced92378 4 Q:
5f058db23f7f070477919df3
Q: (secA – 1)/(secA + 1) के बराबर है।
1314 05ecf342aa7365b2f4ce1cfb0
5ecf342aa7365b2f4ce1cfb0- 1(1 – sinA)/(1 + sinA)false
- 2(1 – cosA)/(1 + cosA)true
- 3(1 + cosA)/(1 – cosA)false
- 4(1 + sinA)/(1 – sinA)false
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Answer : 2. "(1 – cosA)/(1 + cosA)"
Q: sec4 A (1 – sin4A) – 2tan2A का मान है?
1308 05dd38322874d2d52fa317fac
5dd38322874d2d52fa317fac- 1$$ {1\over 2} $$false
- 20false
- 32false
- 41true
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Answer : 4. "1"
Q: यदि $$ sin(θ+30^0)= {3\over \sqrt { 12} } $$ है तो cos2θ का मान ज्ञात करें ?
1301 05dd38201bfcbc45cddeddb4d
5dd38201bfcbc45cddeddb4d- 1$$ {1\over 4} $$false
- 2$$ {3\over 4} $$true
- 3$${\sqrt { 3} \ }\over 2 $$false
- 4$$ {1\over 2} $$false
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Answer : 2. "$$ {3\over 4} $$"
Q: $$ {(sec^{2}θ+tanθ\cotθ-tan^{2}θ)}$$ का मान होगा।
1300 05feeea721f464d740159faae
5feeea721f464d740159faae- 11false
- 22true
- 30false
- 44false
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Answer : 2. "2"
Q: $$ {tan^2θ}$$ के बराबर है—
1300 05efeb11c7228dd6b06e74e29
5efeb11c7228dd6b06e74e29- 1$$ {1\over cot^2{θ}}$$true
- 2$$ {1\over sin^2{θ}}$$false
- 3$$ {1\over cosec^2{θ}}$$false
- 4$$ {1\over sec^2{θ}}$$false
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Answer : 1. "$$ {1\over cot^2{θ}}$$"
Q: निम्नलिखित विकल्पों में से गलत सूत्र का चयन करें।
1292 064abd872299b7896000b39a6
64abd872299b7896000b39a6- 1false
cosec2θ - cot2θ=1
- 2false
sin2θ + cos2θ=1
- 3true
sec2θ + cos2θ=1
- 4false
sec2θ – tan2θ=1
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Answer : 3. "sec2θ + cos2θ=1
"
Q: The value of $$ {2(1-sin^{2}θ)}+{2(1-cos^{2}θ)}$$.
1281 05f76cdfee487e60dced92378
5f76cdfee487e60dced92378- 11false
- 22true
- 33false
- 44false
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Answer : 2. "2"
Q: यदि $$ secθ+tanθ=2+\sqrt{5}$$, है, तो $$ sinθ+cosθ$$ का मान है?
1280 05f058db23f7f070477919df3
5f058db23f7f070477919df3- 1$$ 3\over{\sqrt{5}}$$true
- 2$$ {\sqrt{5}}$$false
- 3$$ 7\over{\sqrt{5}}$$false
- 4$$ 1\over{\sqrt{5}}$$false
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Answer : 1. "$$ 3\over{\sqrt{5}}$$"
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