Trigonometry Practice Question and Answer

Q:

$$ secA(secA+tanA)(1-sinA)\over (cosec^2A-1)sin^2A$$ इसके बराबर है:

1229 0

  • 1
    cotA
    Correct
    Wrong
  • 2
    cosA
    Correct
    Wrong
  • 3

       sec2A

    Correct
    Wrong
  • 4

      cos2A

    Correct
    Wrong
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Answer : 3. "

   sec2A

"

Q:

$${cos^2A\over {1+sinA}}$$ का मान क्या होगा?

1224 0

  • 1
    1+sinA
    Correct
    Wrong
  • 2
    1-sinA
    Correct
    Wrong
  • 3
    1+secA
    Correct
    Wrong
  • 4
    1-secA
    Correct
    Wrong
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Answer : 2. "1-sinA"

Q:

यदि $$tan(A+B)=\sqrt { 3} \ $$ और $$ tan(A-B)= {1\over \sqrt { 3} \ }; 0^0<(A+B)<90^0;A>B, $$ तो A और B का मान हैं

1192 0

  • 1
    45° and 15°
    Correct
    Wrong
  • 2
    15° and 45°
    Correct
    Wrong
  • 3
    30° and 30°
    Correct
    Wrong
  • 4
    60° and 30°
    Correct
    Wrong
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Answer : 1. "45° and 15° "

Q:

व्यंजक का मान क्या होगा
 cos 2A cos2B+sin2(A-B)-sin2(A+B)?

1190 0

  • 1
    sin(2A-2B)
    Correct
    Wrong
  • 2
    cos(2A+2B)
    Correct
    Wrong
  • 3
    cos(2A-2B)
    Correct
    Wrong
  • 4
    sin(2A+2B)
    Correct
    Wrong
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Answer : 2. "cos(2A+2B)"

Q:

यदि sec θ − tan θ हो तो sec θ + tan θ = $$ \sqrt { 5} $$ का मान ज्ञात कीजिए 

1190 0

  • 1
    $$5{1\over 5}$$
    Correct
    Wrong
  • 2
    5
    Correct
    Wrong
  • 3
    $$5{1\over 5}$$
    Correct
    Wrong
  • 4
    $$\sqrt { 2} \ $$
    Correct
    Wrong
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Answer : 3. "$$5{1\over 5}$$"

Q:

यदि $${secA={5\over 4}}$$ है, तो $${{tanA}\over 1+tan^2A}-{sinA\over secA}$$ का मान क्या है?

1185 0

  • 1
    1
    Correct
    Wrong
  • 2
    0
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 2. "0"

Q:

व्यंजक का मान क्या है?

(tan0° tan1° tan2° tan3° tan4° …… tan89°)

1185 0

  • 1
    1
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    0
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 3. "0 "

Q:

x cosθ-y sinθ=2 और x sinθ + ycosθ = 4  में से θ हटाने पर कोनसा कथन सत्य होगा ?

1124 0

  • 1

    x2+y2=20

    Correct
    Wrong
  • 2

    3x2+y2=20

    Correct
    Wrong
  • 3

    x2-y2=20

    Correct
    Wrong
  • 4

    3x2-y2=10

    Correct
    Wrong
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Answer : 1. "

x2+y2=20

"

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